How to Solve for the Coefficient of Friction

[@quacxks100]

This is gonna help me sooooo much. Have a physics test tomorrow, Will update. Update: 92%!!! Let's, GOOOOOOO

[@LHHELPS]

good job!

[@squidward2154]

Congrats

[@ak_buckets7962]

W

[@charlielesch6323]

Now I have a physics text tmr, will update 😳

[@SpartanWolf120]

​@@charlielesch6323 it's been a month

[@sapaiVFX]

Thx a lot for this. Helped w/ my IB physics lab report

[@dominicappleton3449]

IB physics gang!

[@monikachaudhary9569]

Hi , Thankyou so much . Lots of love 💕💕 from INDIA.

[@kevinkinal9557]

The 10 sec version Coef of Friction = Force/ wt. For ex, if 1 lb moves a 2 lb object Coef = .5 (it takes half the wt to move it)

[@AaronAbu-f8b]

Thanks a lot, video still helping 4 years later

[@yaduvanshiayush3215]

It's amazing explanation..!! Love from India dude ❤💗

[@pr3ttysus922]

you saved my life, THANK YOU SO MUCH!

[@jinanabrahams5195]

Thanks so much. My teacher just threw me in the deep end, and this really saved me😊

[@danuwu2514]

Thank you so much, you made it so easy for me!

[@jyotsnarishita669]

It helped me a lot thanku I am glad I watched your video I got 100 /100 💯💯

[@NikiweMokoana]

How do you calculate the coefficient if there where two blocks with different masses connected

[@dennybuka969]

Love you ❤you saved my life

[@renadi5673]

شكراً لك كان مفيد جداً لي

[@mgms2000]

مو عربي

[@andrefelipe2643]

Thank you ! 😃 you made it look quite easy, I am not even good at math and I understood that 😅.

[@jippo91]

What if i have to calculate the coefficient of friction in an angle and with the downwards force. For example when i have a box on a sin=15° degree angle slope and the downwards force "gravity" is 200N. I have been trying to solve this for two days and i'm supposed to get the answer Gx = 51,763N. I just dont get it. The equation goes sin=15°, G=200N, Gx=Fu. Sin= Gx:G, Gx= 200N • sin15°, Gx= 51,763N. What am i missing?

[@dianelibarnes2519]

Thank youuuuu ❤️❤️❤️ I was really having troubles with this one 😭😭

[@annrahennaramirez5821]

thank you this is the video that im looking for two days hahahaha

[@gabriellesanthya9539]

Hi is it possible if you explain superposition theorem 😊

[@BattierJam]

Thank you so much for this my teacher is terrible at explaining things

[@vladvalevski5608]

Saved my life

[@Seansangweni]

a load of 7tonnes is pulled along a horizontal track by a force inclined at 30 degrees to and above the track .Find the frictional force if the coefficient of friction is 0,2..................help..??

[@DMaciaga]

You'll have to find the normal force (mgcostheta) then plug that into the friction force equation (Ff = mu x Fn). Looks like you'll have to convert 7 tons to kg.

[@samsonphiri8951]

I have done that 7000kg *9.8 to find the weight of the Load. And the weight of the Load= to the normal force since it is pulled along the horizontal surface.

[@Soyuzniki21]

Isnt that the limiting friction?

[@Soyuzniki21]

0:46

[@gordspins7298]

yes. this video was very helpful thanks

[@gordspins7298]

subscribed and liked

[@ellaea4505]

physics final thank you for the help

[@amartitesfaye7297]

Thanks for this video!

[@VinsanityNailed]

Please please please leave your units in. You don’t explain WHY the coefficient of friction doesn’t have units. It’s because the units divide out. Leaving units out is a really bad habit for students

[@kivalbalasar9403]

Dont put units in for coefficient of friction you lose marks

[@vinchenzowitbooi_8599]

This video saved my liiiife oh my gaaawd😂😂

[@sohanreddyk2537]

And how is that dude

[@c7nal7ammadi78]

@@sohanreddyk2537 maybe he had an exam and watched this vid??????

[@twangerrrrrr]

I have my grade 11 physics dynamics test next period in a couple of minutes. I hope I do well. I missed 2 days of school because I moved homes and now I fell behind in friction and gravitation.

[@lifesavergaming5583]

Brilliant

[@samsonphiri8951]

Since the 7 tones load is pulled along horizontal the normal force= weight of the Load which is equal to 68600N and the acting at the of 30° by the free body diagram the horizontal force = 39606.23N this is the force which must be overcome to accelerate the load of 7000kg.

[@krazzyyyyy7302]

Tnx a lot sir!

[@efath-bz8hv]

thank you brother

[@ShivamYadav-jo5bl]

You are very op brother

[@Rookiwi]

thanks bruh

[@aradhyth9]

It can be obtain by inequality

[@russkayaimperiya5779]

THANK YOU!

[@hellleyy]

Thank you👍

[@xyama8433]

thanks so much

[@proplayer6053]

Thanks ☺️

[@irshadtarsoo7734]

Thank youu❤️💯👍

[@tsekokatse2118]

Thank you

[@nadia-tw1en]

THANK YOU

[@arielleestrada7753]

i love you

[@J.Michael1]

Thanks!!!

[@karabogift2297]

Thnx

[@c7nal7ammadi78]

انا عندي امتحان و الساعة 4 الفجر و للحين ما درست😂😂

[@forza_INT]

😂😂😂نفس بعض

[@sulaimankhan2152]

king

[@jjeonacid1282]

what if there’s a frictional force present in the box??

[@shumailkhan7205]

Friction is a force that is between 2 surfaces. so friction is between the box and the ground. There is no friction 'present in the box'

[@jimtsitsos]

the greek letter is called "me" :')

[@SpartanWolf120]

Eat your cereal

[@apanba1050]

L

[@learningtwice347]

Thanks 😊🙏

[@kristalsmith2552]

Thank You!!!!!!!