How to solve? | Nice Math Olympiad Question

[@noski33]

Something is wrong! a^(m+n) is not equal to a^(m•n); it is equal to a^m•a^n. The steps he wrote after are correct though

[@MathBeast.channel-l9i]

You are right....that is a typo. I realized it now that was written mistakenly and I'm sorry for that 😔

[@angelbest19lop78]

Is there a way to record video ?? Poor students will get headaches and start hating math because of mistakes or typos mentioned..Please! Amen​@@MathBeast.channel-l9i

[@angelbest19lop78]

​@@MathBeast.channel-l9isorry re-record and delete video I meant

[@RealQinnMalloryu4]

6^{x+x ➖ }+{2+2 ➖} ➖ 36 =6^{x^2+4} ➖ 36=6^2x^2 ➖ 36 36x^2 ➖ 36={1.24+1.124}=2.48 2.24^24 2.2^12^2^12 1.1^6^6 2^3^2^3 2^1^1^3 23 (x ➖ 3x+2).

[@alfredhorstman]

O common!!! That can be much shorter!!!

[@MathBeast.channel-l9i]

Okay Boss 🙂

[@srinivasch-re2oq]

Very simple, 6^x (36 -1) = 60 6^x = 60/35 = 12/7 Apply logerthms then find x value. xlog6 = log(12/7) We should know logerthm, log inverse values from 1 to 20 while preparing for such exams.

[@srinivasch-re2oq]

We can do with simple multiplications and divisions.

[@MathBeast.channel-l9i]

@@srinivasch-re2oq Alright Boss 🙂

[@MrThetaphi]

At <a href="#" class="seekto" data-time="29">0:29</a> you write a^(m+n) = a^(m*n) which feels terribly wrong, also at <a href="#" class="seekto" data-time="460">7:40</a>. Luckily, you didn't use this, else you'd have gotten doomed. Am I totally wrong?

[@MathBeast.channel-l9i]

No. You are totally right Sir. It's a typo. Very sorry for that it was mistaken 😔 It's actually a^(m+n) = a^m × a^n

[@Skywarddecrypter]

Why u increased unnecessary steps?

[@MathBeast.channel-l9i]

To explain well🙂

[@에스피-z2g]

6^x(36-1)=60 6^x=12/7 x=(log12-log7)/log6 x=1+(log2-log7)/log6 x=1-(log7-log2)/log6