How To Solve Sudoku The RIGHT WAY - SHC 242

[@SmartHobbies]

📕Get my FREE Solving Guide that will help you solve over 80% of all Sudoku puzzles🧩to include NYT Hard👉👉www.buymeacoffee.com/timberlakeB/e/125822 Timestamps 0:00 Intro 00:21 It’s Solving Time 00:32 Puzzle Story 00:56 Tip #1 04:10 Tip #2 06:53 Tricky Solve #1 08:45 Tip #3 10:00 Tricky Solve #2 13:21 BONUS Trick 14:38 Tip #4 16:37 Solving The Green Cell

[@JohnRandomness105]

I normally don't do the puzzles with the red alerts on, but they were on now and I didn't bother to turn them off. I'm pretty sure they may unraveling the centermarks considerably faster. Block 7's 3 was my first digit, although I didn't zero in on it immediately the way you did. I found lots of pairs and triples, which helped. 4:30 I followed the same next four solves as you, although I didn't get the 1 in block 8 until I'd gone through my routine of cornermarking. Every (ungiven) digit was cornermarked in block 8, and R9C4 had only a 1. The next 1 and the 5s came immediately, of course. Afterwards, I detoured back to block 8, and placed the digits except for an 89 pair. I also cornermarked in a couple more blocks, but then went to the 4 in block 2. 8:20 I'd already done block 8, so my next step after block 2's 4 was the 34 pair in block 5, column 4. That gave a 79 pair, and resolved block 8's 89 pair. 8:10 My way was much easier. Cross-hatch block 2's 4, and immediately get the 34 pair. The remaining three cells are 789, with 8 only allowed in R8C4. 9:20 What I did following this was to centermark blocks 2, 3, 4, and 5 -- including block 2's pointing pair of 9s. I centermarked rows 8 and 9, leading to a 246 triple in column 9 and a residual 17 pair. 10:00 When I'm stuck, I go and centermark houses, hoping to find something. I found something above (the triple). Now, I finished cornermarking block 8 and found something else: column 8's pointing pair in 6s, pointing at a 69 cell R4C8. That unraveled a bundle of centermarks (and cornermarks) and gave me a bundle of digits, including all of block 2 and your important 79 pair. It also gave me a 67 pair in row 8, which unraveled a bundle more. Right now, reviewing what I did, I can see 23 limited in column 7 to two cells. I didn't see it during my solve, because I was too busy with other things. Then the cells got resolved without my ever seeing the 23 pair. Cleaning up the centermarks gave me a 145 triple in row 3, which gave me a 29 pair. One of the 29 cells was the green cell. 12:20 I got both 67 pairs, although through radically-different solve paths. 15:10 Ditto for the 29 pair in block 1. Having centermarked block 4, I immediately got the 269 triple after the 29 pair. That gave me a 47 pair in the column. The rest was unraveling the centermarks.

[@indigobunting2431]

Easy to see... afterwards! Thanks. That triple was especially murky.

[@SmartHobbies]

Glad you liked the video and you found it helpful to find that triple. 😊

[@eugenetswong]

Thanks for walking us through this! I appreciate the time that you spent. I didn't find any of the first few things on my own, because I was concentrating on eating for the first few minutes. Regarding 06:53 Tricky Tip #1, I tried it on my own to see if I could get the 79 that you got without me listening. Of course I didn't! :-D Fortunately, I did solve for another pair, though. That being said, to find the 79 first like you did, I discovered that it might actually help to think of it this way: 1) Okay...we have these 4 givens in column 4. 2) Of the remaining 5 candidates, which of them are excluded, using the block first, and then using the row second? Using the row second reduces eye movement. 3) If there are still 3/5 or more candidates remaining, then are there any other candidates excluded using the blocks below? Do you think that my suggested 3 steps are the most efficient process for most beginners and experts? Regarding 14:38 Tip #4, I got very confused immediately after you found 29. How you know to look for the triple, as opposed to a quadruple? Why did you not check to see if any of those candidates were available in the other cells? I think that your teaching is in hindsight, which makes it hard to solve in foresight, when we need the wisdom the most.

[@SmartHobbies]

I appreciate your feedback Eugene. For your first question, I do believe your first method is a great way to teach beginners on how to spot pairs. For the second question about the triple, I remember solving the 29 and then looking down the column to see what it gave me, and saw there was now a naked triple. I thought you had a keen observation about hindsight vs foresight. What do you think would help bridge that gap for first time solvers?

[@Ramakrishnagm]

It's taken 45 min. PPPE. Needed filling in all cells. * r2c8= 8, *R8c2= 3, *R1c3= 8, *R1c8= 4 ( only place for 4, count NOS 1 to 9, *R9c4= 1 (only place for 1 ) *R8c4= 8, *34 pairs in Col 4, *269 tripple and 1&5 in Col 6., *R7c9=8, *Box-8 = 9&6, *246 in Col 9, and 1&7, *6s in box 6 col 9-it make 9 in r4c8, *Now row 4 completed with 26 pairs, These are enough to solve, in between got 67s UR in row 7&8. Taking notes took time. Very good puzzle from ASHISH. Now the watching time.

[@SmartHobbies]

Congrats on your persistence. Glad you were able to solve it. Thank you for sharing what you did.

[@georgesthibaudeau1533]

Fun puzzle à la Kumar. Notation free. First, the two angled corners give 8 in block 3 at 28 and 3 in block 7 at 82. Then 4 at 16 (naked single), 34 pair in block 5 at 45 and 46; 8 in 84, 1 in 94, 1 in 46, 5 in 45 and the 79 pair to complete row4. The top remains difficult to disambiguate, but restrictions elsewhere will come to the rescue, such as the 67 pair in the middle column of block 9. Great stuff, although notation free becomes quite an exercise for a 75 year old memory. Great demo as usual, thanks.

[@SmartHobbies]

Glad you liked it Georges.

[@AnonimityAssured]

Another fine-looking puzzle. One tricky step (82 = row 8 column 2): 82, 28, 94, 46, 45, 86, 95, 16, 84 (hidden pair in box 5), 75, 79, 48, 24, 44, 15, 35, 26, 11, 13, 87, 89, 39, 12 (hidden single, owing to triple in column; not easy to find), 37, 38, 27, 17, 64, 54, 68, 97, 98, 99, 87, 57, 65, 55, 61, 59, 49, 42, 33, 31, 73, 32, 53, 66, 56, 62, 51, 71, 21, 83, 78, 88, 72, 23, 22, 93.

[@SmartHobbies]

Way to go Julian!

[@AnonimityAssured]

@@SmartHobbies Oops! I accidentally posted this reply below a different video. I am following your solution now. Interestingly, I found that 4 in box 2 by different means, but it was my first write-in after the few easy cells at the beginning. Oh, I actually found the 4 in box 5 before the one in box 2. In any case, it led to the same sequence of easy 4s elsewhere. Follow-up: Well, I was right. I would never have spotted the Discontinuous Loop as such, but some of my virtual chains are not unlike it.

[@SmartHobbies]

@@AnonimityAssured 😊

[@Ramakrishnagm]

I saw your video 4 and 1 is similar, and other solvings are different, very nice solving and teaching. Thanks.

[@SmartHobbies]

Glad you liked it. Have you solved any Ashish Kumar puzzles before these videos?

[@Ramakrishnagm]

​@@SmartHobbies I solved in Smart Hobbies, and Unshackling Channel some puzzles, l know ASHISH will give tough, l expected before the puzzle needs more no's in all cells.😊❤

[@BradJames878]

Another hard puzzle that took me over an hour, not counting additional time spent referring to the video. I started pretty good, but then started filling in way too many candidates. I had all block 8 filled in and found a triple on column 9 before needing to resort to the video, but I didn't spot the 4 in block 2 or the conjugate pair in column 7. No telling how long the puzzle would have taken if the video didn't tell about column 7, because nothing was pointing towards it.

[@SmartHobbies]

Good insight here, Brad. What areas are you seeing improvement in your scanning?

[@anaayoung9142]

Nice. Not a good time for me: 13:50. I decided to try alone first, but got lost. Your help at 11min with the 23 pair and the 9 in box 6 was crucial for my solve. Thank you!

[@SmartHobbies]

You are welcome. This was quite a tricky combo to spot.

[@fubaralakbar6800]

Hidden triples are a tremendous pain my butt, because they are such a basic strategy and yet so hard to spot. It's like they're mocking me😁

[@SmartHobbies]

They can be tough to spot. Have you checked out my Hidden Triple Tutorial?

[@fubaralakbar6800]

@@SmartHobbies No, but I will do so soon!

[@ke9tv]

About when you were working the 269 triple in C2, I saw the 29 pair in C3, which then forced a 7 in R5C1. That was the pivotal solve for me, rather than your green cell. Either one lets you run the rest of the board with ease. (Took me forever to spot the 29, though.)

[@SmartHobbies]

Nice job spotting that Row 3 pair! Thanks for sharing.

[@rogerweir1772]

Hidden pair in block 5...(34)

[@SmartHobbies]

Nice job spotting that Roger!

[@sharmilisharmili472]

NF But ooh 40m 31s Very bad timing, atleast I had the patience to continue for so long. Now let me watch ur video.

[@SmartHobbies]

Way to stick with it. I picked this one because I also found it particularly challenging.

[@georgesthibaudeau1533]

NF 41 minutes, you win again :)

[@Ramakrishnagm]

​@@georgesthibaudeau1533 Both are notation free likers and masters, for me NF is not reachable thing, at the same time I don't take any worry about this.:-))

[@sharmilisharmili472]

@@georgesthibaudeau1533 I learnt doing NF solve frm you and NMC , credit goes to you both. Thanks!

[@luishectormejiaflores]

(2,8)=8 (8,2)=3 único lugar (1,6)=4; par(3,4) en 4a col dentro del bloque 5 ent (8,4)=8 (7,9)=8; único lugar (9,4)=1 (4,6)=1 (4,5)=5 (9,5)=6 (7,5)=9 (8,6)=5; par(7,9) en 4a col; tercia(2,6,9) en 6a col; tercia (2,4,6) en 9a col ent (4,8)=9 (4,4)=7 (2,4)=9 (2,6)=2 (3,5)=3 (1,5)=7 (1,1)=3 (1,3)=8; par (6,7) en 8a fila ent (8,9)=1 (8,7)=9 (3,9)=7; tercia(1,4,5) en 3a fila ent (3,9)=7; par(2,9) en 3a fila dentro del bloque 1; tercia(2,6,9) en 2a col quedando la tercia (1,4,7) ent (1,2)=1 (1,7)=6 (2,7)=5 (3,1)=5 (3,7)=1 (3,8)=4 (7,7)=4 (6,8)=3 (6,4)=4 (5,4)=3 (5,7)=2 (9,7)=3 (5,9)=4 (4,9)=6 (4,2)=2 (3,2)=9 (3,3)=2 (6,2)=6 (6,6)=9 (5,6)=6 (5,3)=9 (5,1)=7 (6,1)=8 (6,5)=2 (5,5)=8; Rectángulo Especial UR(4,7) en 1er y 7 bloque...

[@SmartHobbies]

Nice job.