How to Solve the Diode Circuits (Explained with Examples)

[@ALLABOUTELECTRONICS]

The timestamps for the different topics covered in the video: 1:02 Graphical Method (Using the Load Line) 3:19 Diode Approximations 4:29 How to Solve a circuit problem using diode approximation 7:46 Example 1 ( Series connection of Diode) 9:54 Example 2 12:11 Example 3 (Parallel Connection of Diode) 13:41 Example 4 (Parallel Connection of Diode with different diodes (Si and Ge)) 16:11 Example 5 (Parallel connection of diode with different voltages) For more Solved Questions on the Diode Circuits, check out this playlist: kzbin.info/www/bejne/nGHbfn-MpdpjsNE

[@baljeerai3789]

In ex 3..why did u only subtract 0.7 ..there was 2 Si diode..so u should have to subtract 1.42??

[@rajugawala]

@@baljeerai3789 because only 0.7volt drop between common node will be there of two diodes suppose them as single element with 0.7 volts

[@vincentburdeos6152]

In example 5, how do you choose which diode is conducting?

[@mav1133]

In example 4 there are two diodes , what happens to the current , does it pass equally through two diodes?

[@orbhaisabkaisahoothik14]

Last one answer should be 4.3V

[@clown12ify]

Thank you indian guy, you're saving a student for doing this tutorial video

[@johangustafsson7396]

For every course I cannot understand, I can rest assured that there's and indian guy with a dedicated youtube channel for it somewhere.

[@clown12ify]

Not all heroes wear cape, some make educational diode circuits solving problems video

[@Honest-King]

Yeah they are everywhere ...

[@CarsonScholz]

Yeah literally man.

[@GStar1]

@@CarsonScholz being Indian I also know there'll some Indian to help me out 😂

[@azyle2104]

@@GStar1 lmao same

[@danielstoy171]

This is the most perfect video ever. Clear and concise with perfect explanations. Thank you!

[@Honest-King]

The accent though ...

[@danielstoy171]

man not really. I can still understand him pretty well with the accent

[@Astra20284]

yeah u r right

[@covertmediocrat]

@@Honest-King you probably are virgin because nobody around you looks like Kim Kardashian but you know with that face of yours you won't be able to impress bar dancers 😂

[@priyanshupreet8108]

@@covertmediocrat bro itna offend kyu ho gya?😂

[@yasminekudjoe7548]

I was so confused with this diodes stuff but you saved my llife. Thank you, you are the best

[@ahsanhabib8877]

I study in one of the top university in Bangladesh having one of the best physics teachers in South Asia. I admit you make it clearer than those over learned professors. Thank you so much sir.

[@harshalshah1058]

Before that video I was very much confused about diode solving but now I got confidence in this topic .Thanks sir for this amazing tutorial ✌️👍👍

[@mnada72]

This is a great channel for studying circuits and electronics

[@pranavipranu607]

9:49 Current = 4 mA Voltage = 4 volt

[@neelimathakur2802]

9:49

[@neelimathakur2802]

I=4 ma V=4 volt

[@burraqamber663]

Right 👍

[@orbhaisabkaisahoothik14]

@MD TAIYAB 21PKBEA500 it should be 4.3V I guess the other terminal is at -1 hence total difference is of 4.3V

[@LousyPainter]

I can see an immediate use for the last circuit. Thanks. Excellent demonstration!

[@SSRReloaded]

Thanks a lot, sir, my electronics exam is just 3 days away, and despite covering the syllabus, I was just blanked out of how to solve problems. Thanks a lot for making my concept clearer & helpin me on solving problems ❤️🙏

[@Scolar69]

I am here before 30 min lol

[@salmansabbir5692]

Thank's Sir. It's the best tutorial. After watching this tutorial, nobody else has any problem, I think.

[@minepro1206]

Again you proved better than my professor.

[@kesusd]

The voltage across the 1k ohm resistor is 4 V and the current for the circuit is 4 mA for the example with one silicon diode and one germanium diode.

[@ManojKumar-ho5mf]

I came here for concept used at 15:45 And it is cleared thank you 😊

[@chiraggupta8908]

best explanation I have ever seen.... Thank you Sir for making video like this....

[@drammeh1209]

Tamam... Your explanations are always Crystal Clear...

[@wtfchazpwnt]

Perfect video. So clear and direct.

[@Honest-King]

I wouldn't say "clear"

[@aleemahmed9981]

Thanks have a test on diodes your way made everything more clear.

[@kdu4249]

you just saved my life sir.. thank you so much for this.

[@sarahjohansson957]

Hell clear now. Thank you sir!

[@MelonLuminus2845]

thank you sir, i'm studying about this and transistor at my school, and this video helps me a TON!!!

[@codingfacts4835]

This video is very helpful guys.Thankyou ower of this channel

[@vegas2287]

I was in a big trouble.This is a nice video.love it!Thank you very much

[@jaishreedagar]

ya same here thankyu sir

[@Jared-Cruz]

Excellent video. Very clear and helpful.

[@shikiwoo]

Thank you for the quick and simple explanation.

[@altairishere2357]

You are life saver!!!!👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍

[@diptishah3232]

very nicely Explained

[@akshatpanda9799]

Problem in 9:50 :- current = 4 mA voltage across Si diode = 0.7 V voltage across Ge diode = 0.3 V voltage across Load resistance = 4 V

[@gauravmaurya7755]

Nice

[@oppk4667]

Im 2022 neet aspirant...thank u for this vdo n u r perfect ❤️

[@VersatileAnthem]

great explanation !!! take love :)

[@shameelashaik6423]

Easy to understand the concept. Nice explanation.

[@bsbsb9068]

Your examples selection makes your teaching amazing sir👍👍👍

[@vincentburdeos6152]

In example 5, how do you choose which diode is conducting?

[@kaleabgetahun4458]

i think there would be a 1.3V at the 4V source diode which results in the diode conducting because 4V is bigger than 1.3V , im not confident with my guess tho lol

[@vanhoangtran8783]

The video is excellent with the clear explication ! Congratulation ! For me, I just have one question in the final example. In effect, what is the value of V0 if the first source is 3.5 V in stead of 2 V ? And the voltage of the first diode is 0.2 V in this case ? Thanks very much for your contribution !🎉🎉🎉

[@arsal16]

massive W for this whole series

[@bobbydreamsforu]

Thank you brother. Nice illustration and presentation.

[@umairalii4737]

Thanks man ! Love from Pakistan 🇵🇰

[@coco-oc8qq]

For the first time i understood electronics ❤❤

[@NEERAJKUMAR-hc1wk]

Mast Sir.. I like it...this is recall my past study's

[@jhoanasuelo8474]

For item 9:38 the value of I= 4mA and Vo= 4V

[@KhalidAli-tr4nw]

How is that ??

[@Senthilselvan-d1b]

@@KhalidAli-tr4nw 5V - (0.7V for Si + 0.3V for Ge)

[@rohithchalla1089]

Super explanation brother 👌. Keep it up!!

[@theceltfan32]

Very well done!!!

[@triptivashist4502]

Thnx for this video. It really helped a lot.

[@Bravo-xr9yr]

in the last example how about the -1V source and 1k resistor ? do they have any effect on the output ?

[@rejithretnan8365]

I too have that doubt

[@ClaimItCrypto]

thankyou brother for guiding us🇵🇰

[@Gamingtax]

Aapna muja acha SA samja diya thanks,💖💖💗💗💗

[@lachgarnoureddine4458]

Indian are the best. From morocco ❤

[@jonesmath]

This really helped. Thanks!

[@shrutikadam4315]

Perfect explanation 👍🏻....but because of that subtitles the stuff u were writing on that part was not visible.....btw u don't need subtitles...ur English can be understood by everyone 👍🏻🔥

[@ALLABOUTELECTRONICS]

If required, you can manually turn off the subtitles in the video settings.

[@Emadrust]

You are amazing man! Thank you

[@yarenkaya7872]

Thank you very much for the tutorial. Yet, I wish you had emphasized the importance of the directions and the signs. What could happen if your assumption were wrong and how can you check whether it is or not? If I am not mistaken, I have figured out this issue as follows: We always assign positive voltage to the entering port and negative to the leaving port of a diode. If we assume that the diode is ON, then after solving the circuit(maybe by the virtue of node analysis and substituting a corresponding voltage source whose potential difference is V0(threshold voltage), we should look at the direction of the current coming into the diode. If it is consistent(with the assigned voltage direction), we're right, if not the diode was actually OFF. If at first, we assume that the diode is OFF, it requires the potential difference on the diode is smaller than V0. After solving the eq. by assuming that the diode acts as an open circuit, the potential difference condition( must be smaller than V0) must be checked to see whether the assumption is correct or wrong.

[@persona_jam2458]

12:13 for output voltage why we minimize it from V2 not v1

[@bhpwner]

Curious why Vo is calculated different in example 2 and example 5? Why not care about the voltage drop across the 1k ohm resistor?

[@orbhaisabkaisahoothik14]

Yes the answer should be 3.3+1 = 4.3V

[@e-footballworld8828]

​@@orbhaisabkaisahoothik14 So current will be I= v/R which is 3.3-(-1)/1=4.3mA....so Vo will be -1+(I*R) = -1+(4.3*1) that is 3.3v 😅

[@e-footballworld8828]

In example 2 there is a resistor before the diode so there will be a voltage drop

[@nguyentu-mc5nl]

At the example 5, 18:0, i think Vout should be (Vo= -1+Vr) because we have a -1V source at the bottom, therefore, it should be 4.4V right? pls i need explanation, someone helps me

[@raghava8561]

Mera life save kar dhiya Thanks bhai

[@katsurakotaro552]

Very much appreciated! Thanks.

[@gcjas1998]

At 12:04, why is the output voltage only V2-5V? What happened to 10V , V1, and the 0.7V of the diode?

[@ALLABOUTELECTRONICS]

see here we are applying the KVL. And we are interested in finding the voltage at a particular node in the circuit. You can start from that side too. In that case, Vo = 10 - V1 - 0.7 Or you can say that Vo = V2 - 5 V. Both ways you will get the same output.

[@gcjas1998]

@@ALLABOUTELECTRONICS Oh! So its a matter of choice between the two. Thank you.

[@6packabb]

@@ALLABOUTELECTRONICS But Vo=10 - 8.16 - 0.7= 1.14 Which is not equal when calculated from the other end

[@indhujag5920]

@@6packabb it's same only. Just .02 difference. It's not an issue.

[@PavithranD22]

​@@6packabbit's due to the approximation of current value

[@jakehealthx]

Wow, so helpful!

[@beryyyllium]

In example 5, why is it that the diode with the 2-volt source will be the one to stay off instead of the one with the 4-volt source? is it only based on assumption?

[@ALLABOUTELECTRONICS]

Let's say, for example, the diode which is connected with a 2V voltage source is ON. in that case, the voltage at the cathode of the diode is 2- 0.7 = 1.3V. The same voltage will also appear at the cathode of the second diode. (The connected with 4V source). With that assumption, the voltage at the anode of the second diode is 4V, and the cathode is 1.3V. That means the second diode should also conduct. And in that case, the voltage drop across the second diode is more than 0.7V (which is not possible) On the other end, if second diode is conduciton alone, then voltage at the cathode both diode is 4 - 0.7 = 3.3 V. And in that case, the first diode will remain off. (also there is no violation of KVL) I hope it will clear youir doubt, why first diode is OFF.

[@vaishnavip2327]

Why In 2 example , u didn't consider V1?

[@sumitpundir9547]

Voltage across 1 kilo ohm resistance is equals to 4 volt

[@rv6130]

Well explained,thank you❤️😁

[@hectormota6728]

I do not understand what I have to know in theory to calculate vo = v2 - 5v, what If I assume vo = 10v-v1-0.7? help! for 11:59

[@pupu25-o4r]

I exactly don't know the theory...but.. suppose the -5v wasn't there...v0 would be v2 (I think that's clear)...now...we r adding this -5 v...adding v2 and -5v we get the result

[@Enigma758]

11:00 the -(-5) part is a little confusing.

[@DhruvsDomain]

For example 5, can you not also make the assumption that the top diode is ON and the bottom diode is OFF? This assumption would still be correct, but v0 and a different value of 1.3 V instead?

[@aagmanarora2556]

same ques

[@ShreyaRajBEC]

Same doubt

[@zainmd1234]

10:23 How can you apply KVL in an open circuit?

[@himanimalik6973]

In Eg. 2 for calculating V0 why not consider V1

[@righteousness185]

good teaching, thank you.

[@hemanthadithya459]

Bro please use spot light while explaining the questions...🙏 Thank u for this amazing video...💖💖

[@rohandevaki4349]

very nice explaination and tricky sums thankyou sir.

[@suniltiwari8708]

Sir, in example 5 you said that upper diode will off but for diode to be off potential drop across diode should be less than diode voltage but when you say that at right terminal of upper diode potential is 3.3volt then for upper diode potential drop is 1.3 volt which is more than that zener voltage then how it can be off ? please tell sir

[@gaurisharma2120]

very clear explaination..thank you...

[@mayurshah9131]

Nice Narration

[@vinayk531]

sir , in last case why didnt we consider the -1v acting at that node ...pls sir explain??

[@rkumar.761]

Nice explanation...Thanks Sir. 💓💓💓💓💓💓💓💓

[@winnieaguilarjr6737]

thankYou for the video. :) its very helpful.

[@kandilkandil-o1c]

Hi, Thanks for this very simple, clear & very good presentation. I have a question: what about the voltage at the load R (-1 V)?

[@ALLABOUTELECTRONICS]

You mean to say the voltage drop across 1K resistor. If so, then at one end of resistor the voltage is 3.3 V, while at the other end, the voltage is -1V. So, voltage drop across it is 3.3 - (-1) = 4.3 V

[@TechSouls-wn6jc]

why in example 5 the diode with 4V input will be considered as on while with 2v input will be considered as off?

[@zgryx8428]

Nice video, helps me a lot

[@mohabubalam8068]

Sooo nice video sir...sooo nice.it is physics with beautyy.thanks for your good explanation.

[@shatakshisingh2513]

I didnt understood the 5th example.....can someone please help me with this like what if the second diode remains OFF then too the voltage will remain same at both the nodes (1.3V)

[@sanskarkumar8674]

So helpful thank you Sir and keep going🖒

[@abuanas8569]

very fine explanation. Thank you

[@PraveenKumar-zj9db]

Very good explanation. Thank yy

[@bilalaslam189]

KZbin University > Any University

[@akhil5586]

Worthful video

[@Harshavardhan-zr2ip]

Excellent...but please answer to it...as soon as.. While drawing equivalent ckt of diode we are taking opposite to voltage supply (but it is actually inside diode electric field is from higher potential+ to lower -) so same direction of supply...

[@at6727]

THANK YOU BRO THANKS A LOT!!!

[@TRICKSBYCHEMISTRYGURU]

how did u calculate vo in example 2

[@kewtomrao]

I think because they are parallel

[@student6830]

Vo = I * R

[@oneeyedeagle549]

EX2 : why did we assume the current through v1 and v2 are same they are in parallel right?

[@ALLABOUTELECTRONICS]

Because they are connected in the series. when in doubt, just draw the supply voltages with + and - signs, (In this case, just draw the 10V and -5V voltage sources) and draw the complete circuit. You will get it.

[@enami_0136]

thanks. when the courant is negative and when it is positive???

[@snoviya9826]

Nice explanation

[@haseebsafdar6712]

@9:06 why did you subtract both 0.7 from 5V

[@ALLABOUTELECTRONICS]

Because both Si diodes are in series. So, you need to consider the drop across both diodes.

[@ritik839]

love from agra

[@tom24helmetboy46]

Great video, thanks a lot

[@saiprakashputrevu7512]

Nice explanation sir...

[@ravindragupta04]

An ac voltage of peak value 30V is connected in series with a germanium diode and a load resistor of 400 ohm. the forward resistance of the diode is 20 ohm and the barrier voltage is 0.3V. Find the peak current through the diode and peak voltage across the load,

[@ravindragupta04]

Please solve this Question........

[@evelynfdz590]

In example 5, if D2 were changed to -4, what would happen to Vout?

[@PavithranD22]

Reverse bias ..D1 will start to conduct

[@onkarambuse8286]

Nice sir which is this app you use