How to solve this Nice Exponential Equation ✍️ Math Problems ✍️

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Leo Dorber

Leo Dorber

Күн бұрын

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@cloudanu
@cloudanu 18 күн бұрын
In future videos could you please explain the logic of everything you're writing down? e.g. I have no idea how you arrived at 2, exponent 3 in the second line. Or how you arrived at y.
@That1SupportiveFriend
@That1SupportiveFriend 18 күн бұрын
For those who don’t want to spend 10 minutes for the answer x=log2(3) or ~ 1.589
@nasrullahhusnan2289
@nasrullahhusnan2289 11 күн бұрын
(8^x)+(2^x)=30 --> (2^x)³+(2^x)=30 (2^x)[(2^x)²+1]=30 Note that 30=3×10 --> 30=3(3²+1) hence (2^x)[(2^x)²+1]=3(3²+1) 2^x=3 --> x=[log(3)]/log(2)
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