Hydraulic Conductivity

[@nokuthabanleya439]

A whole topic in a few minutes. I love it

[@dr.mariaceciliamarcos]

Thank you!

[@mjruizsalvador7663]

@13:41 seepage velocity = discharge velocity/porosity Vs=V/n na multiply nyu po ata. ans: 2.079x10^-3

[@aeldanmoar]

bali tama lang kasi n=e/(1+e) so pag nilagy mo siya doon sa formula magiging Vs = V/e/(1+e) = V(1+e)/e

[@johncichon9232]

Division of fraction po sir bale reciprocal lang so tama ung multiply kasi if you noticed naka flip ung porosity formyla

[@mjruizsalvador7663]

@@johncichon9232 ok. nakita ko na. Antok na kasi ako nito. tama pala yung sagot.

[@mjruizsalvador7663]

@@aeldanmoar 👍

[@vovo8425]

I don't understand what is being said here but my understanding is that seepage velocity is always less than discharge velocity.

[@copernicofelinis]

I'm not into hydraulics, but... Can we say this is the hydraulic analogous of Ohms law? The conductance (conductivity times area divided by length) is given by the current intensity (Q/t) divided by the potential difference (h). On a side note: what tablet/pen did you use to write that beautifully?

[@zainabmohammed9426]

Thanks a lot 💚

[@dr.mariaceciliamarcos]

Thanks too!