Chapter 7 Permeability - Example 4: Rate of Seepage (Artesian Pressure)

[@uwabageserabertin1349]

Good lecture

[@taxfree4603]

Why did you choose cosine alpha for those two values

[@oreoandbeesly]

Does this problem assume a rectangular cross section with a width of 1 meter? Also, how do the units work out to be m^3/sec/m?

[@uSeeGeo]

This problem assumes the cross-section has a unit width of 1 meter (i.e., unit width into the screen). Therefore, the unit of seepage rate becomes volume/time/unit width, i.e., m^3/sec/m.