If the resultant force of the two tugboats is 3kN, directed along the positive x axis, determine the

[@gr_engineering]

CORRECTION: Please note that at 4:22 I wrote down and said to ADD (2)(3)(1.615)cosθ. This expression is SUBTRACTED, NOT ADDED. Therefore, when you plug in (-2)(3)(1.615) into the denominator, you are automatically yielded with the final answer shown here, 38.26°. I apologize for any confusion.

[@m.ehsaan.]

Can I do it without the cosine rule?

[@SigninPurposes]

Hi! would this still be possible to solve if only FA and its angle were the only given?

[@gr_engineering]

Hello, at a minimum you would need more information, such as the magnitude and direction of the resultant force or the second force.

[@Myllys2]

Thank you

[@gr_engineering]

You're welcome!

[@karimkemo5786]

What if fa is unknown and fr is still known and u need fb to be minimum how do u make sure that fb has the minimum value ?

[@gr_engineering]

@@karimkemo5786 Do you have the angles between Fa/FR and Fb/FR?

[@karimkemo5786]

Only for Fa which is 30 degree

[@gr_engineering]

@@karimkemo5786I apologize for the delayed response. If you still are stuck please submit a request in the link in the description.

[@emitre08]

​@@karimkemo5786sample problem 2.2 from vector mechanics for engineers?