Moment of a Force | Mechanics Statics | (Learn to solve any question)

[@QuestionSolutions]

⭐⭐If you'd like to see more examples covered and at the same time support the channel, please see: kzbin.info/www/bejne/pIHZeGSYjquVodE ⭐⭐ 🔹Clockwise moments positive, or counter-clockwise positive? kzbin.infoP029mqnp4XY 🔹Please note there is a typo at 6:23. The "k" term is negative, not positive, so it's {-128.34i + 128.34j - 256.68k} 🔹At 6:31, there is a typo in the question, we are finding the moment about point B, NOT A. This is a typo in the question only, all steps are correct. 🔹When to use sine or cosine: kzbin.infovynnKlJD_Jo

[@moonbunnies5216]

Hi sorry for bothering. For the j term in the same timestamp you've provided, I can't seem to get positive j. 4(-42.78)-(-2)(21.39) = -128.34

[@moonbunnies5216]

btw thank you so much for these videos. Its really helping me a lot you have no idea how thankful I am to have found this channel.

[@QuestionSolutions]

@@moonbunnies5216 Since this is the second multiplication, it will have a negative in front first, so it will be like this: -[4(-42.78)-(-2)(21.39)]. You can always double check using this website: onlinemschool.com/math/assistance/vector/multiply1/ . Simply plug in the 2 vectors. And you are very welcome, glad to hear these videos are helping :)

[@moonbunnies5216]

@@QuestionSolutions oh my god I totally forgot about the formula for that, should've checked myself before commenting, thank you so so soo much for letting me know.

[@QuestionSolutions]

@@moonbunnies5216 Happens to everyone I think :) Best wishes on your studies!

[@alienx097]

Completing my Engineering from KZbin University of Engineering and Technology

[@QuestionSolutions]

Best wishes with your studies!

[@divineobot1605]

For realll😂😂😂😂❤

[@aadhilhasan7815]

Best KZbin professor😊 thanks a lot

[@ShubhamKumar-u7b7g]

Same condition same place 😂

[@Rabeetah]

Which engineering program?

[@A1M2099]

5x faster than my prof.

[@QuestionSolutions]

👍😁

[@aaqibkhursheed9523]

And its easier to understand 😃😂

[@d7o0myalshlaly59]

5x better

[@trevorclark7985]

honestly, my professor makes this stuff seem like rocket science with how bad he is at teaching it

[@1Katula]

well I'm obviously subscribing. I have been struggling with this topic for a while and your video just helped me get it. 1 step closer to becoming an engineer thank you : )

[@QuestionSolutions]

That's really awesome and I am super glad you got it :) Thank you so much and I wish you the best on your journey to become an awesome engineer!

[@j.d.b.7581]

Same here✨

[@ivoryas1696]

@@QuestionSolutions Awesome. Thanks dude. 👌🏾

[@adinadjiressem6669]

@@QuestionSolutions Very Smart

[@BigSmokeEnthusiast]

Your honestly one of two best tutoring channels for physics in all of YT. Continue making quality vids bro!! (also new sub)

[@QuestionSolutions]

Thank you so much for your kind words! Really nice of you :) I will do my best to continue the channel.

[@zoelogan1841]

Thank gosh I found you! I was struggling so much with moments and now I know it's the PERPENDICULAR distance. Thank you so much :)

[@QuestionSolutions]

Haha, yes, perpendicular distance :) Glad to hear this helped!

[@nicerice9689]

You are doing god's work my man, bless your soul holyyyyyy, Keep doing what you're doing man

[@QuestionSolutions]

Many thanks! I wish you the best on your studies.

[@kidusteshome8440]

you explained the whole topic and worked all possible types of problems related to this topic in just 8mins! you're amazing!

[@QuestionSolutions]

Thank you very much!

[@leeafd1-o33]

Who is still watching this in2024

[@silentkiller-xw3hx]

Me Me✋ I am a student at the Oil Institute, Department of Mechanics, and I have backlogs in many subjects because in the first half I did not study hard, but I regret it now and I am trying to make up for everything

[@QuestionSolutions]

Try creating a timetable for yourself, allocating a certain amount of time per each course. So for example, 1 hour for course one, 1.5 hours for course two, etc. More time for ones you struggle with, and less for ones you are confident in. This process helps a lot of students out. Best wishes with your studies and you can do this!!!

[@silentkiller-xw3hx]

@@QuestionSolutions Thank you very much❤️

[@YarZarYarZar-v3t]

Me too

[@Eng.ZeinYassin]

May God bless you, your family, and your knowledge that you spread. You have made me understand, so I ask God Almighty to increase you and bless the goodness in you and increase you. Syria🇸🇾🥇

[@QuestionSolutions]

Wow, thank you very much, that was a really nice comment. I wish you the best in your studies and all your future endeavors!

[@Hussain-qt5ti]

At 5:47, why can't you just split the force into its x and y components and then solve the question like the previous two?

[@QuestionSolutions]

Excellent question! This is a 3D problem, that means the force now has x, y and z components. You cannot break it into components the same way you did with 2D problems. So you have the express that force as a cartesian vector, in other words, we must express the 80 N force in it's x, y, and z components, and then take the cross product to find the moment.

[@kentpimentel9300]

I got -128.34i +128.34j -256.68k for the cross product in 6:24.

[@QuestionSolutions]

You are right, there is a typo, the k term should be negative. 👍

[@sbarz106]

Thank you so much you've saved me, in just minutes you managed to explain better than hours of lectures!

[@QuestionSolutions]

I am really glad to hear that :) Best wishes with your studies!

[@Tay7r]

Same bruh, my professors can't teach shit

[@bigiron4018]

Awesome, so helpful. I was having trouble with this topic, watched the video, worked some practice stuff out on paper and cruised through the rest of my homework on this subject. Thank you!!

[@QuestionSolutions]

You're very welcome. You're doing exactly what I hoped students would do :)

[@easymoney7344]

Damn man im really happy i found your channel man💓💓 i read a lot of book but its kind of confusing. While you explain it very simple. Thank you man I already shared your videos to my classmates since it is very helpful💓

[@QuestionSolutions]

Thank you so much 💓 I really appreciate your comment and the shares, super nice of you! 💓💓💓💓

[@ritushikder-c7q]

F1x = F sin 30. How this is possible.. We know that Fx = Fcos(degree) for any force in axis. Why here F1x = F sin 30..

[@QuestionSolutions]

That is incorrect. x-components are NOT just for cosine. I don't know where students learn this from, but that is not correct at all. Please see this, it's less than 60 seconds, and you won't lose marks on your exams: kzbin.infovynnKlJD_Jo

[@yortzan5747]

nope, you use either sine or cos to whatever component, Sine when opposing the angle; but use cosine when adjacent with the angle

[@melyvaleriabanuelosvazquez959]

At 4:25 it was mentioned clockwise was positive, while I’m aware that counterclockwise is positive while clockwise negative, could you explain? as I’m confused now 😢

[@QuestionSolutions]

You can use whatever way you want to be positive. If you like counter-clockwise to be positive, you can solve it that way. Regardless, you will end up with the exact same answer. :)

[@mpadithyaanoopnambiar7835]

You Deserve a Globe's Best Teacher Award 🤩

[@QuestionSolutions]

🤩 You're too kind!

[@freakingik2781]

Yes,he indeed deserves it. God bless u.....

[@QuestionSolutions]

@@freakingik2781 :)

[@RedSarGaming]

Coming from a class with a curriculum that doesn't follow the book to the T, this is such a great way to get study/example problems. THANK YOU SO MUCH!!!!

[@QuestionSolutions]

You are very welcome! I hope you gain a firm grasp of the materials and do amazingly on your exams!

[@brownbearedurardo]

I am here just for the recap since most of the engineering lessons I took required this procedure to solve problems. Thank you! You discussed better than my college instructor. Specific and concise!!!

[@QuestionSolutions]

I try my best to make them as concise as possible :) Best wishes with your finals!

[@BilboBagends]

BIG UP MY MAN QUESTION SOLUTIONS!! Thank you for putting these together!

[@QuestionSolutions]

Many thanks!! 👍👍

[@randomname1392]

tysmmmm I've been trying to figure this out on my own for an hour now and you just made it all clear now I'm definitely going to like and subscribe

[@QuestionSolutions]

Thank you so much, really glad to hear it was helpful! Keep up the awesome work.

[@kriistyy.]

in 6:13 , I used the position vector OA. Why the direction of Z axis of my moment is -256.62 and not 256.2. Is it wrong?

[@QuestionSolutions]

It should be negative. Please show me the position vector you got. Thanks!

[@viva7416]

Sir,here is the moment when I use the position vector OA. Mo={ -128i + 128.34j - 256.68k } rOA= { 3i +3j +0k } So if there's not any mistake the Moment must be the same for both position vector rOA and rOC. isn't sir Thanks a lot for ur help 😊😊

[@harshmangukiya91]

amazing!

[@QuestionSolutions]

Thank you!

[@emanuelbutron6798]

for the pipe assembly problem, even though vector was given in cartesian form why didn't you make it a unit vector like you did previous?

[@QuestionSolutions]

You only need the unit vector to express a scalar force in cartesian form. If it's already given in cartesian form, you don't need to do anything to it. Use it as is.

[@halleighfaulkner3963]

for the fourth example, why are you using the position vector for BC if you're taking the moment about point A? would you not use AC?

[@QuestionSolutions]

There is a typo in the question, the moment was suppose to be about point B. I wrote a pinned comment about this too because I get asked it so many times. 😅

[@muhammadhilmi6529]

For question 2, why the solution for Ma is 35(0.9) +60.62(0.7) ?? not 35(0.7)+60.62(0.9) ?

[@QuestionSolutions]

You have to multiply by the perpendicular distance. So the perpendicular distance to point A from the 35 N force is 0.9 m, not 0.7 m.

[@pimientopicante3870]

Thnx so much for explaining it! I had mix feelings about this topic since my professor went over it fast

[@QuestionSolutions]

I hope it was helpful to you. Best wishes with your studies!

[@danconte954]

You deserve my subscribe! I hope all students trying to learn this lesson would see this video. Thanks for the tutorial. Keep it up.

[@QuestionSolutions]

Thank you very much! :)

[@sujalbhatu999]

thank you so much brother

[@QuestionSolutions]

You are most welcome.

[@nataliatothemoon]

Praying Tanaka has a suggestion: may you include sample problems where we are given angles and not just lengths? It would be very helpful 🌝 🙏

[@QuestionSolutions]

I am not sure I understand what you mean? You need distances to calculate a moment, or you use the angles given to figure out the distances first. Could you elaborate on what you would like to see? :)

[@DanielBoakye-ic2cr]

Sir. Pls, u're going too fast What made the MF3= -300, instead of 300?

[@QuestionSolutions]

I don't know where you're referring to. Please use timestamps.

[@wolfchrt]

6:45 why is the reaction of BC used and not A?? Why is point B relevant?

[@QuestionSolutions]

The question written is incorrect, the moment is found about point B, not A. I made a typo in the question.

[@btw_itachi_uchiha]

amazing helpful

[@QuestionSolutions]

Thank you very much!

[@Bindie]

my brothers in the Egyptian 3rd secondary, assemble 🇪🇬

[@QuestionSolutions]

👍

[@davidandrews5262]

what is magnitude of 3d force? lets say is our moment

[@QuestionSolutions]

You find the magnitude by squaring each term, and then adding it all together and taking the square root of it.

[@Ijee12]

Hi, i thought clockwise direction was negative and counterclockwise was positive or it doesn't matter?

[@QuestionSolutions]

See pinned comment.

[@NjabuloShongwe-y3y]

Sir we not able to see you diagram and the values because of your words you speak the block the view 😭😭😭

[@QuestionSolutions]

Are you talking about subtitles? You can disable subtitles anytime you want (press the CC button) and you can even move them to another location by clicking and holding and moving it across the screen.

[@itsmemags4778]

Isn't F1x be equal to cos(theta)? since cosine represents the x-axis while sine represents the y-axis?

[@QuestionSolutions]

Please, take 1 minute and watch this video: kzbin.infovynnKlJD_Jo That is incorrect, and you must erase that thought from your mind. You will lose so many marks on your exams from that view point, and I have no idea where students got this idea from.

[@PaulOtoo-n3e]

It's good, but the speed is too much for we the beginners Learning it.😊

[@QuestionSolutions]

Thanks for the feedback :)

[@emanabdelrahman8728]

i didn't understand how did you know where is the line of action in the first example?

[@QuestionSolutions]

Follow the arrow of the force vector straight ahead. That is your line of action.

[@andrespardo3623]

The only thing that I dont know is when u use the position vector and after that find the unit vector. Im so confuse when I try to solve my hw problems

[@QuestionSolutions]

Whenever you need to express a force in cartesian form, you first need a position vector and then a unit vector. I cover it in this video: kzbin.info/www/bejne/eXTIiKxnoNKrg9U

[@eiadm2047]

Thx for your great effort! In the last problem, If we wanted to use position vector OA, what force should we use when doing the cross product?

[@QuestionSolutions]

The forces remain the same, only the position vector changes. So when doing the cross product, you would use rOA. 👍

[@AnilVerma-jr8qz]

At least when u upload the videos plz check none of ur content must not hide

[@QuestionSolutions]

I am not sure what you are referring to. Please let me know and I will do my best to help. Thanks!

[@jiahe6255]

I thought clockwise is negative and anti clockwise is positive?

[@QuestionSolutions]

Read pinned comment.

[@nacure360]

For example 3, if r is the position vector from the point where we take the moment about to any point along the line of action of the force, can r be the position vector from O to A? if I do that i get -128.4i +128.4j -256.08k? (the only difference is the sign of the z component to your answer).

[@QuestionSolutions]

You absolutely can. I have a typo in my answer (see pinned comment). Your answer is correct.

[@nacure360]

@@QuestionSolutions ohh thank u

[@ummiaisyah7560]

I cant be thankful enough to came across ur vids!! definitely helps me to understand it like whatttt soo much better than my actual lecture. And the fact u r replying to all the comments is amazing and i get to learnt from others comments too! great job really, keep doing what u r doingg thank u veryy muchhhh

[@QuestionSolutions]

Thank you for your kind comment and I am very happy to hear that these videos help. Keep up the awesome job and I wish you the best with your studies! :)

[@ummiaisyah7560]

@@QuestionSolutions Will do my best and thank youu for the wishh!!!

[@QuestionSolutions]

@@ummiaisyah7560 You're very welcome!

[@نادرالكيك]

A uniform metre scale of mass 200 g carries of a block of mass 800g at one of its end .At what distance from the same in end does does a knife and balance the scale?

[@QuestionSolutions]

Sorry, I don't solve questions like this because then I have to solve everyone's problems 😅 I encourage you to use math/physics forums if you need help with a specific question.

[@kafukwamekemeh]

Umm aren't clockwise values negatives instead of postives? u seem to say that in this timestamp 4:09

[@QuestionSolutions]

Use whatever direction you like best. You will get the same answer. It is always easier and faster to pick the direction that will give you the most positive signs, otherwise, you will have to deal with more negative signs, but it is your choice.

[@ThunderGowPlayer]

Hi, I have a question, why in 5:45 we get the position vector from OC and in 6:41 its from BC? That wouldn't mean that our position vector in 5:45 should be from O to A? I have tried that and it will change the values of the momentum vector

[@QuestionSolutions]

You can take it from O to A, and you will get the same answer. There will be no difference. You most likely wrote down an incorrect position vector. The position vector OA would be 3i+3j+0k. Keep in mind that there is already typo in the solution for that question as mentioned in the pinned comment. The answer for that problem is -128.34i+128.34j-256.68k. Whether you use a position vector from O to C or O to A, you will get the same answer.

[@ThunderGowPlayer]

@@QuestionSolutions Oooh, I just checked, and you are right! I was messing up with the position vector, but yeah, when you do it with 3i+3j+0k, you get the same answer. Sorry for the confusion. Thank you for your help and answering my comment, even though this video is 3 years old! New subscriber

[@QuestionSolutions]

@@ThunderGowPlayer You're very welcome. I am glad you got it :) Keep up the great work and best wishes with your studies.

[@akira...7819]

In the first problem why is it that all of the x and y components are positive?

[@QuestionSolutions]

So unless you specify a direction when writing out equations, forces don't have negative or positive values, they are just magnitudes. For example, imagine you push on a box to the left. That's a force you applied, it's not a negative force. Now imagine you pulled on the box to the right. It's still an applied force with a magnitude, it's not a negative force. We only consider them negative and positive when we write out equations with a coordinate system.

[@Milkiyas312]

At 7:56, shouldn't the net torque be (0,720,0)Nm? I don't understand how you got (-720,720,0)Nm. Wouldn't the 1800i and -1800i cancel out? I'm so confused.

[@QuestionSolutions]

So you're not reading the values correctly, you need to be more thorough or you will lose marks on your exams (it's always the small things that students lose marks for). It's not 1800-1800, it's -1800+1080 = -720. Again, NOT 1800 but 1080. Let me know if you need any other help, best wishes with your studies. :)

[@Milkiyas312]

@@QuestionSolutions OHHH tysm! How did I not see that? lol

[@QuestionSolutions]

You're very welcome!@@Milkiyas312

[@ThecarsHQ]

please i'd like to ask if the position vector could be from anywhere like Rac instead of Roc

[@QuestionSolutions]

Please kindly provide a timestamp to the place you're referring to.

[@jesustheodore5126]

Thank you so much, Great Video! it was very helpful for my statics exam!

[@QuestionSolutions]

I am very glad to hear that :) I hope you did well on your exam.

[@ponarapholo7885]

How do I do the cos product, how do I apply that formula there

[@QuestionSolutions]

Please see: kzbin.info/www/bejne/fGmseaWdaNWWbck

[@adamwalk3410]

How come the y component is not negative because it's acting down

[@QuestionSolutions]

Please give me a timestamp so I know where you're referring to. Thanks!

[@darwisyhhaiqal6081]

at 7.30 1800 should be positive

[@QuestionSolutions]

No, it's not positive. -720x2.5 = -1800

[@husseingafer2093]

6:34 I think the question is to find the moment about point B not A there is no poin A

[@QuestionSolutions]

Yes, see pinned comment.

[@marisolreveles2575]

I thought + was counterclockwise and - clockwise?

[@QuestionSolutions]

You can pick either direction, it makes no difference as long as you follow through with your positive and negative signs.

[@QuestionSolutions]

So for example, assume you picked counterclockwise to be positive, then if you get a negative answer, the moment is clockwise. If you picked clockwise to be positive and you got a negative answer, then the moment is counterclockwise. If you picked counterclockwise to be positive and you got a positive answer, then the moment is counterclockwise. Lastly, if you picked clockwise to be positive and your answer is positive, then it is clockwise.

[@marisolreveles2575]

@@QuestionSolutions Thank you!!

[@tamagoeggzy9443]

5:58 in the position vector rAC why did it became {(4-3)i + (0-3)j + (-2-0)k}, why is it that the given points A is subtracted to the given points C?

[@QuestionSolutions]

Please watch this video first: kzbin.info/www/bejne/eXTIiKxnoNKrg9U where I explain the fundamentals of position vectors :)

[@tamagoeggzy9443]

@@QuestionSolutions okay. Thank you so much for the video:) I'll watch the video about position vectors later:)

[@QuestionSolutions]

@@tamagoeggzy9443 Please do watch it, it's only 6 minutes and will help clear up a lot about position vectors. This is super important for pretty much everything else that will come up in the future of your course, even 3D equilibrium problems. Best wishes with your studies :)

[@harshshah7599]

What's the difference between torque and moment

[@QuestionSolutions]

Nothing. I copied this from wikipedia: In physics and mechanics, torque is the rotational analogue of linear force. It is also referred to as the moment of force (also abbreviated to moment). Simply put, it's just force times perpendicular distance.

[@basavarajgl5453]

hi sir at 6.21 why you taken roc instead of roa

[@QuestionSolutions]

You can take either, you'll get the same answer. 👍

[@The.Wonderful.Inspiration.Of.]

Hello, I think there is a mistake at 6:23, Roc should be Roa since the starting point of the force is A no ? Or maybe I don't know the rule well ^^ Edit : Well I just heard "position vector from point O to any point of the line of force action", I learned that thank you :)

[@QuestionSolutions]

Yes, as long as the vector goes to any point on the line of action of the force, you will get the same answer 👍

[@rorygame5835]

Great video! Really helped me wrap my head around this. With the curved rod question, wouldnt the k-value of the cross-product be -256.68k? ((4 x -64.17)-(0x21.39)=-256.68k) Otherwise it wouldnt be perpendicular to the plane created by the two vectors.

[@QuestionSolutions]

Glad to hear it was helpful. :) And yes, I have a pinned comment with the typo corrected. 👍

[@MashoodAhmad-ks1ee]

In example no 4 moment of force about point B not A😊

[@QuestionSolutions]

Yup, there is a typo. :)

[@ragnarlothbrok6324]

Hi, I love you thanks for this.

[@QuestionSolutions]

You're welcome! 👍

[@aidanshum4991]

I don't see there's any point a for the question at 6:39

[@QuestionSolutions]

Please see pinned comment. Thanks!

[@muhammedyamenabdulhadi8840]

thanks for the awesome explanation methods you just made the subject extremely easier

[@QuestionSolutions]

I am really glad to hear that! Best wishes with your studies.

[@PeterChisha-o6y]

Can you please make a video on space trusses

[@QuestionSolutions]

I'll add it to my to-do list. :)

[@ronaldleeweimeng2125]

why clockwise is positive? is it negative?

[@QuestionSolutions]

You can pick either direction, it makes no difference as long as you follow through with your positive and negative signs. So for example, assume you picked counterclockwise to be positive, then if you get a negative answer, the moment is clockwise. If you picked clockwise to be positive and you got a negative answer, then the moment is counterclockwise. If you picked counterclockwise to be positive and you got a positive answer, then the moment is counterclockwise. Lastly, if you picked clockwise to be positive and your answer is positive, then it is clockwise.

[@eurydice8963]

I FINALLY GET IT!!! 😭😭😭😭😭🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻 I was so confused what the hell is those clockwise and counterclockwise direction lmao I didn’t know how where and what does it mean. THANK YOUUUUUU I LOVE YOU

[@QuestionSolutions]

I'm really happy you got it. Keep up the great work and I wish you the best with your studies.

[@JGambrosia]

6:23 why doesn’t rA x F work? Why do we need to use rOC? F is acting at point A, shouldn’t we use the position vector rA when calculating the cross product? where rA = 3i + 3j + 0k

[@JGambrosia]

Please help.

[@QuestionSolutions]

You can use either rOC or rOA. They give the same exact answer.

[@JGambrosia]

⁠​⁠​⁠​⁠@@QuestionSolutions ahhhhhh, no wonder i was so confused! You made a tiny mistake while calculating the cross product of r X F the answer is -256.68k****** not +256.68k. You forgot the minus sign for the k component. So when i calculated rOA X F i got a minus sign for that component and thought they were different. See im not an idiot haha.

[@QuestionSolutions]

@@JGambrosia Yes, please refer to pinned comments first before assuming you made a mistake. Mistakes are pinned at the top of the comments.

[@sadhananarendar2992]

Excellent explanation. Thank you very much. Very well explained. The best part is explaining the solution really fast and also clearly.

[@QuestionSolutions]

Thank you so much for your nice comment. I really appreciate it.

[@jamess3493]

i do not know why u are saying clockwise to be positive in everything, everyone says clockwise in negative and counterclockwise is positive

[@QuestionSolutions]

Moments are not positive or negative. They have directions. We arbitrarily assign clockwise as positive or negative to solve problems. You get the same answer whether you pick clockwise to be positive or clockwise to be negative. Use whichever you like best. It makes absolutely no difference. Over time, as you gain more experience, you should be able to assign a positive direction based on the question so you have to deal with less negative signs.

[@jamess3493]

i see, thanks@@QuestionSolutions

[@QuestionSolutions]

@@jamess3493 You're very welcome. Let me know if you have any other questions.

[@glm1195]

This 8 minutes video totally saved me from being crazy huhuhu literally ripped my scratch paper moment before encountering this video 😅 new subscriber here❤

[@QuestionSolutions]

I am glad to hear it helped you out. Keep up the great work, and best wishes with your studies!

[@baktybek6454]

2:45 where did you get this numbers like 250cos30, 300cos60, 500*4/5 , all this numbers?

[@QuestionSolutions]

So all of those numbers are forces broken into x and y components. If you need a refresh, please see: kzbin.info/www/bejne/hKOvZpdjZ6iUmLM

[@janecm6136]

Thank you. I think I get it now. I’ve been stressing and struggling summation of forces and moments. I think I finally got the principle. It’s just that the figure is overwhelming me but I think I’m almost at it now. I’m definitely subscribing ❤

[@QuestionSolutions]

Thank you very much. I am sure you will get it, just practice a few problems and follow along the examples :) I wish you the absolute best with your studies!

[@0nub1s]

first of all thanks for the beautiful explanation, but I have a question, why'd you multiply the horizontal component of F3 with 4? shouldn't the perpendicular distance from point A to Fx be 5 as well? or is every point along the horizontal part of the pipe considered as point A? (in the 1st problem)

[@QuestionSolutions]

So you can actually draw two lines at point A (perpendicular to each other like a coordinate system), extending towards the edges of your page. Then it's easier to see the perpendicular distances better. So for Fx, we are looking to see the distance towards the horizontal line, which is just 4m.

[@0nub1s]

@@QuestionSolutions thanks man appreciate it

[@letsdevise2949]

Is not clockwise the negative moment instead of positive?

[@QuestionSolutions]

You can pick either direction, it makes no difference as long as you follow through with your positive and negative signs. So for example, assume you picked counterclockwise to be positive, then if you get a negative answer, the moment is clockwise. If you picked clockwise to be positive and you got a negative answer, then the moment is counterclockwise. If you picked counterclockwise to be positive and you got a positive answer, then the moment is counterclockwise. Lastly, if you picked clockwise to be positive and your answer is positive, then it is clockwise.

[@letsdevise2949]

@@QuestionSolutions Thank you!

[@koala1084]

Gorgeous explanation, thank you!

[@QuestionSolutions]

You're very welcome!

[@johnnym500]

For the first question, when solving the moment for M3: Shouldn't it be -300n(5m)+400N(4)?

[@QuestionSolutions]

So remember, we are looking for the perpendicular distance. F_x is horizontal, so we are looking for the vertical distance from point A, that's the perpendicular distance, which is 4m. F_y is vertical, so we are looking for the horizontal distance from point A and that's 5m.

[@divineobot1605]

I think I'll come back and watch this again 😅😅😅😅. But it's very clear🎉... maybe I dont get it yet.😅😅😅😅😅😅😅😅. Thank you very much.🎉

[@QuestionSolutions]

You're very welcome. Come back, watch it a few times, do the examples and then if you have any questions, let me know. I'll do my best to answer them. Best wishes with your studies. 👍

[@darrylcarter3691]

In the problem starting at 6:58, I got {-694.8i + 730.8j + 0k} N m. Is that close enough?

[@QuestionSolutions]

Hmm, you should get pretty exact numbers because there isn't much rounding involved. Are you able to pinpoint where you deviated?

[@footballclips5013]

Sir at 2:45,when finding the components of x and y for F1,why did you use sin for the x-component instead of cos and cos for the y-component instead of sin? Or am I mistaking please?

[@QuestionSolutions]

Please watch this: kzbin.infovynnKlJD_Jo?feature=share It'll clear up all your doubts. :)

[@lostsky3631]

Was studying these same things for four hours and didn't understand a single thing. Can't believe I just understood everything in 8minutes😂😂I appreciate 🙏

[@QuestionSolutions]

I am really happy to hear that! Well done and keep up the awesome work :)

[@Hussain-e9z]

In Q2, the force was applied at point B. How did u transfer that to point A? Also which way would the pipe rotate?

[@QuestionSolutions]

Please see pinned comment. There is a typo in the question.

[@Hussain-e9z]

@@QuestionSolutions Thanks for replying. In the pinned comment you talk about Q4 having a typo. But I have a doubt in Q2 starting from 4:30 . You don't address that. Can you please help me out? Thanks!

[@QuestionSolutions]

​@@Hussain-e9zokay, I see. For future questions, please use timestamps so it's easier for me to find. So in this question, it's not really a transfer of forces. When a force is applied anywhere along the pipe, a moment is created about point B. You can visually see this if you break a force into components. For example, look at force FX. We can slide that force along the horizontal length of the pipe and it will create the same moment regardless. Why is that? That's because the moment created is only dependant on the magnitude of the force and the perpendicular distance. In this case, it's 0.9m. Now look at FY, the perpendicular distance is 0.7m. For the second part of your question, the pipe will rotate clockwise. Imagine the pipe is free to rotate about point A and you push at point B towards the left. Then we can see it would start spinning clockwise.

[@Hussain-e9z]

@@QuestionSolutions Thank you so much! You're really good at explaining. Please never stop uploading videos.

[@JZTynes]

Good information, but goes too quickly through calculations and removes equations once solved.

[@QuestionSolutions]

The pause button is your friend.

[@dennardleonard1228]

This is the best video

[@QuestionSolutions]

Thank you very much!

[@zaynnazam2084]

hi for the question at 5:56 you found r oc how come u dont do it while finding ro a

[@zaynnazam2084]

nevermind I just seen your reply

[@QuestionSolutions]

Okay :)

[@Evanescence29]

dudee you're such a legend!!!

[@QuestionSolutions]

Thank you :)

[@ashlynraj6939]

At 2:41 Why did you use the horizontal component of F2 for F2x instead of the vertical component like in F1?

[@QuestionSolutions]

Okay, so I think what you're actually asking is, why did I use cos for F2x, but use sin for F1x, and you are assuming cos and sin are related to horizontal and vertical components. If this is your question, please erase that thought out of your head. Sin and cos are NOT related x/y/horizontal/vertical components. They are purely based on the angle and it's corresponding side. I have no idea where students get this notion from, but please make sure you don't think like this. 😅I really encourage you to look at this video (kzbin.info/www/bejne/hKOvZpdjZ6iUmLM), it's not long, and if you're really tight on time, just watch the first example. It will give a very good foundation for working with sin/cos and how to properly use them. I break it down step by step and by the end you will never get confused again but sin and cos. If this isn't what you're asking, I am not too sure I understand your question. Maybe rephrasing it might help me, if so, I am sorry :(

[@xXZackTheGuyXx]

shouldn't the resultant vector be from the origin to point C and not point B to c at 6:45 ? The problem wants us to find the moment about point A (which I assume is the origin), and not point B.

[@QuestionSolutions]

I pinned a comment about this as well, there is a typo in the question, it should be about point B, not A.

[@itumeleng6055]

For the first question, why is F1x 'sin' and not cos? I thought we used cos for x-components & sin for y-components?

[@QuestionSolutions]

The amount of times students say this is quite scary :) This is absolutely NOT the case. Sine and cosine are NOT related to x or y components, they are based on the angle and the side relating to that angle. Please, take 5 minutes to watch this video, I explain this step by step. kzbin.info/www/bejne/hKOvZpdjZ6iUmLM If you're really tight on time, please watch the beginning and the first example. It will clear everything up, and set up the foundation needed for future chapters and pretty much every other course you will take that involves cosine and sine.

[@christopherverse]

Why is it negative 300?

[@QuestionSolutions]

Please use timestamps. I don't know where you're referring to.

[@gangstashuckle]

Top G lesson

[@QuestionSolutions]

Many thanks! 👍

[@kiran4456]

Great explainations 👏, hope for more videos 👍

[@QuestionSolutions]

Awesome :) Thank you so much! 👍👍👍👍

[@TuExklusiv]

Amazing

[@QuestionSolutions]

Thank you! Cheers!

[@kyordannydelvalle523]

Wow, Even after graduating. I still remember how to do it. Just needed to refresh my memory a little.

[@QuestionSolutions]

Congrats on graduating and well done for remembering!

[@عمرغسان-م2خ]

Thank you so much ❤

[@QuestionSolutions]

You're welcome 😊

[@atherbukharii]

The best video on KZbin, nothing better than this but could have been the best video in the galaxy if video was a bit slow. Edit: by bit slow i mean 10x slower

[@QuestionSolutions]

Thank you for your feedback. :)