IIT JEE advanced PYQ 2024 Paper 2

[@rajvirdi1816]

Jee nikale 3 saal hogye, mere homepage pe aise hi video aagyi aur mai dekhne lag pda.These questions and these logical concepts are just so interesting.

[@cutedemon43]

I'm emotional at the moment sir...I used to practice such kind of questions when I was in 12th... subsequently I decided not to pursue the dream of going into this line...due to some personal problems...I miss those days when I used to solve these problems with all my dedication. I got recommended a mathematical PYQ video after 5 years...I can't express in words how sorry I am for leaving this line

[@prakharchanchal]

Same

[@Guruju5555]

What r u doing currently

[@samuraijosh1595]

What are you doing now?

[@cutedemon43]

@@samuraijosh1595 I'm pursuing masters in Entomology

[@abhishekshaweducation2041]

I can understand your feelings. It is the worst feeling that none can understand.

[@user-kc2hr3cs9v]

Well explained, anybody having basics level of understanding can understand this

[@sanjeevsir29077]

Thanks

[@samratsur218]

Very good question really tests your knowledge in a lot of concepts

[@gloomyend1232]

Sir your video made me nostalgic I gave exam back in 2017 now I feel old 😂😂

[@AdhiNarayananYR]

I gave the jee in 2008. You’re not that old 😂

[@basit_yt]

Sir way of explaining proves why maths is so beautiful❤

[@user-uc1lr1dm1m]

Completed my btech now watching with passion thnx sir reminded me old days.

[@dhruvshah8310]

Nostalgic stuff! Thank you sir. Just passed our this year! :)

[@SonuKumar-fm3jn]

Best thing about sir is he considered all possibilities instead of just solving the question. ❤

[@kanishkrana9426]

Felt proud that i was able to solve this by looking at this and starting the way that what could not be negative. Really cool step by step explanation

[@Qwerty25414]

Easiest advance question, dekhte hi ho gya

[@bluesky5794]

Yep

[@RahulGupta-uk7xy]

Dekhte hi to nhi ho sakta kuch to karna hi padega solve , tukka mara h to aese hi bol de

[@ayanagarwaliitdelhi7662]

Nahi Bhai sochna pada tha yeh lawda insan hai isme sabse pehele neeche ka quadratic socha ki zero nhi hoskta toh uske cancell krdia fir sinx+2 zero nhi hoskta fir epix zeero nhi hoskta bas voh 2023 wala bacha usme -1 solution aya

[@shivam_09x]

Bhai maine 2023 solution maar diya 😭

[@mdkashif1956]

​@@shivam_09x Same bhai 😥

[@SurajYadav-bc5id]

KZbin recommend this out of no where. It's been 7 years clearing JEE. Those were some days!!!

[@kingshuksaha8405]

Today I have completed my BE in ME from JU , still I am able to get a hang of this question ...I pick my copy n try to solve it ...may be this all what IIT JEE does to you ...Only one comment do cherish and enjoy the journey undertaken by all of you .

[@i_play_chess_8564]

Sir I got admission into NIT nagpur in 2019 and I dropped out in 2020. 4 years later, today, KZbin randomly recommend this video, and it made me feel so happy, such an easy and understandable explanation, makes me wonder that I used to solve all such maths questions with ease a few years ago, now my brain is all rusty I can't even imagine doing calculus again.😅

[@Asjk-zb3iv]

Applying Descartes' rule of signs directly gives us the number of solutions for x is one.

[@harjotsingh9713]

Be cautious it also counts repeated root twice

[@Asjk-zb3iv]

@@harjotsingh9713 yes. But not in this case..here it directly gives 1. And we also can take a derivative test for repeated roots..that not much work for this problem

[@opps150]

​​@@Asjk-zb3iv this rule does not gurantee you you have exactly one root, it's juld tells you maximum possible number of solution,, there may be no solution also

[@Asjk-zb3iv]

​​​​@@opps150 phirse dhyan do, socho. Your knowledge is incomplete. Kya bolte hai wo theorem?..agar number of roots reduce hota hai to kiske multiple mein hota hai? Wo yahan apply karke dekho. Kya yahan wo possible hai?..dyan se padho cheeso ko, tumhara hi bhala hoga..agar phir bhi nahin samajh aya, to Wikipedia mein 1st para padhlo. Theorems yuhin nehin kaam karte, kaam karwanewala chahiye bete.

[@smaug9833]

Loved these types of questions. Analyzing functions and their behaviour. Some would say it's the best thing to do in Mathematics.

[@pavan9965]

sir you explained very well i really like your explanation

[@balajiyadav4250]

It's not about the answer but the explanation was crystal clear and awesome sir❤

[@soumyadipbanerjee2074]

This is a very good question 🔥🔥

[@pragyapaliwal6101]

Sir don't get demotivated due to less views one day you will have more than 1 Million subscribers Please do something for bitsat 2024 june attempt pls pls pls .

[@Pokemonmaster2235]

Me with more subscribers 😅

[@vishalfgm]

​@@Pokemonmaster2235check now dude

[@saritdas3833]

You are a brilliant teacher.

[@goravgupta9334]

Marvellous

[@arnavkumar8388]

Chalo 4 saal baad bhi kuch questions toh ban hi Jate😂

[@vishalmishra3046]

*Denominators are equal and non-zero* (for real x). So, they can be cancelled without changing the problem. It's because { e^(πx) > 0 for all real x. x^2 - x + 3 has b^2 < 4ac so no real roots, and the expression is always positive, with minima at 2x - 1 = 0 or x = 1/2 so x^2 - x + 3 has min value of 3.25 - 0.5 = 2.75 }. (sin x + 2) is always positive (non-zero), so the problem can be simplified to - find number of real-roots of { x^2023 + 2024 x + 2025 } which again is a strictly positive function with negative values when x < -1 and strictly positive values when x > -1 (It's 0 at x = -1). Hence, for the overall problem, there is *only 1 real root which is x = -1*

[@sssoup]

Brilliant explanation - how to attack problems like this - Actually learnt a method not just the solution

[@bharatsharma93]

Try studying

[@abhiroop1231]

Great explaination.

[@kushagra89]

Teachers like you are a blessing to this world…what an explanation

[@sanjeevsir29077]

@@kushagra89 thanks

[@jyotishka]

Easy question. I did it in my head and got the answer -1 i.e. one solution.😀

[@funfunandfun863]

Superb sir

[@AdityaBhardwaj-d4c]

Stunning

[@radhikagupta254-t3v]

me Motion coaching ki ek student hu, pahle mujhe JEE ka paper bahut hard laga tha but jab hamare teachers ne class me paper slove karvaya to paper bahut ache se samjh aagya gya 🙌🙌

[@gauravdwivedi7903]

Which batch

[@labeebzaidi]

Jab 12th me tha tab in questions se dar lagta tha, after studying engineering maths, it seems so easy 😂

[@bhuneshwar646]

Good morning sir

[@dictetord12]

Pehli bar dekh ke chod diya,but badne odd degree fn dekh ke orally correct kr diya

[@akshatchauhan5708]

Guys please look ye questions maine dekhte kaise kiya tha , . Maine socha denominator zero to na ho sekta check kerne pe aya ki denominator always positive hai , fir uper ko terms dekhi ,sin x ko zero kerne ka koi fayeda nehi , to akir me x²⁰²³+2024x+2025 hi zero higa to hi f(x)zero hoga , fir me dekha ki x ki kisis bhi positive value 0 se na satisfy kerne waali kyuki x pe odd Power hai to ek hi tukka bhidha -1 ka , uske alaea logically x²⁰²³ +2024x ka sun 2025 ke negative nehi hota , bus answers agaya 1 😂😂,aur ye kaam ksm se 2min ke ander kiya maine men ke ander

[@anuragagrahari447]

Jab bhi koi Aisa polynomial dikhe jo ki solve na ho sake simply to go through calculus

[@shabinperuval908]

Art of mathematics ❤❤❤❤

[@vickyprabhat]

Majaa aa gaya, After 8 years.

[@yashawantgupta1380]

Sir kisi bhi quadratic ka agar D negative and leading coefficient positive ho to vo always greater than zero hota h to aapke samjhane ka tarika thoda casual h😊😂

[@shubhamnaiknaware4311]

The answer should be -1 right

[@ashutoshdwivedi4679]

Easy tha ye to

[@jamesngullie3368]

Always wanted to do engineering since my 10th grade, but life took a terrible turn.

[@sanjeevsir29077]

@@jamesngullie3368 keep patience

[@KK_classes007]

Make the maths alive😊

[@satyapalsingh4429]

x=-1 is the only solution .

[@pepperjohnns]

Only real solution no?😊

[@sneaky6969]

​@@pepperjohnns the domain of f is R So x=-1 is the "only" solution

[@rockyjohnson6248]

Orally..

[@krishnarao5533]

I solved this one in 20 secs 😊 in exam

[@FBI_Overlord]

I thought I was an idiot because I found such questions very difficult back in my JEE days. Turns out, I just had really bad teachers. Sir is there any course by you which teaches complete JEE Mathematics? I just want to learn maths from you.

[@sanjeevsir29077]

@@FBI_Overlord yes

[@anuragagrahari447]

Sir i want to study whole maths for jee is there any way to study with you

[@sanjeevsir29077]

Online

[@anuragagrahari447]

Sir ji apka cource kis platform per milega , sir kaha milega

[@krishnagupta4788]

@@sanjeevsir29077 exactlyy sir!! i alsooo wannna studyy whole maths subject forr jee from you!! u aee greatt!!!!! i understand everyy single word u speak!! plzz tell meee howw can i study from you? online kese!!!!!!!

[@kushalchakrabortty1602]

Isme to pen bhi nahi chalana pada tha 😅

[@Yash-mv8mz]

-1 is the root Only one

[@user-cn3ps2kq8k]

Ye question un logo ko fasane ke liye tha jo question dekhte hi leave kar dete hai but it was easy

[@argh_a]

Can you explain it in more easy way

[@soldierboy38]

kash mera paper iss baar hota itna easy question , only 1 minute

[@Jha_Abhash]

😂 pura paper solve krke dekh!

[@_dyson]

Waha tu padhega bhi nhi poora 😂 and agge bhar jayega hard dekhte hi

[@facthub9964]

Maime to dekhte hi chhod Diya tha 😢😢

[@CrazyGamer-nz8vf]

Kitne numbar aaye?

[@saurav_sing_h]

Sir how to become maths teacher like you

[@sanjeevsir29077]

@@saurav_sing_h 🙂

[@saurav_sing_h]

@@sanjeevsir29077 please reply

[@ViranshandVivaan]

Denominator ko positive kyo dikhaya sir jee wo to already zero hi jayega jbb wo right side jayega

[@sanjeevsir29077]

Denominator negative bhi to ho sakta hai

[@sanjeevsir29077]

Isliye check karna jaruri hai ki vah positive hai ya negative

[@ViranshandVivaan]

@@sanjeevsir29077 negative hoga to kya ho jayaga actually me zero hi find karna hai na sir -f(x)=0 means f(x)=0

[@anant6865]

Hurray 1 solutions my answer right ❤❤ but chemistry ki wajah se Mera jee nhi hoga 🙂😣🥹

[@sneaky6969]

Same...😢

[@praveenrai4199]

Solution dekhkar 😂

[@alliswell4163]

Tukka sahi hua 😅

[@bhaveshmali852]

I solved orally within half minute

[@bhaveshmali852]

But questions easy tha 😅

[@-_-h1]

Are you in eleventh??

[@bhaveshmali852]

@@-_-h1 no bro .IIT me hu.

[@-_-h1]

@@bhaveshmali852 okay nice which IIT btw

[@VanshVansh-bz3en]

True

[@amiryaseenkhan7147]

When x=-1, f(x)=0 (:

[@ajayakumarmahapatra6540]

Ye baht easy hai but explanation acha nhi hai...

[@rohitmanhas8154]

Kaleen bhaiya before being the king of mirzapur :

[@sanjeevsir29077]

🙂

[@Chargesheetaccountant]

Solved in 10 seconds

[@argh_a]

How? Can you explain

[@Chargesheetaccountant]

@@argh_a bhai bas dekhte hi strike hogya ki increasing function hai or -1 pe zero ho rha hai so only 1 solution

[@tanishksinghal6373]

Sir you have a great method of teaching Do you have any online course also?

[@sanjeevsir29077]

Yes

[@tanishksinghal6373]

@@sanjeevsir29077 how can I enroll in it?

[@pragyapaliwal6101]

​@@sanjeevsir29077 It's a sincere request please bring something for BITSAT if I have found you early I would have scored great in jee mains ,, pls bring something for bitsat

[@krishnagupta4788]

@@sanjeevsir29077 plzzzz tell sir!! youtube pr hai? sir plzz chapter explaination ki video daal dijiye!!

[@AmanSharma-bj2yc]

This is a joke. Wish this was in 2020.

[@samyakwagde4522]

Sir baki hogaye ye wala galat hogaya

[@samyakwagde4522]

Sir mere 75 to 80 hai maths me accha college mil jayega

[@crickettipeslivematch5287]

Total kitna hai

[@samyakwagde4522]

@@crickettipeslivematch5287 total paper 1 aur 2 milake mere hai 143

[@abhirupkundu2778]

@@samyakwagde4522 80 in JEE advance? If you got something around 35-40 in the other 2 subjects, I am damn sure you will get a good college for sure.

[@samyakwagde4522]

@@abhirupkundu2778 thanks bro

[@shubhamkumarpandey8162]

Waise ye kya hai 🫣