JEE Main PYQ Function 30 January 23 (2)

[@jyotishka]

In objective questions always try to use some short intuitive checks. Realizing that the domain is [-2,3] , check the value at the end points which is sqrt(5).Hence probably the correct choice is either (b) or (d). Next, equate the two radicals i.e. 3-x=2+x which gives x=0.5 which is a likely inflection point. This may not always be true but worth a check. Value at 0.5 is sqrt(10). Since this is one of the option hence you are pretty sure that's the answer. I use to do these tricks to quickly solve objectives when I cracked JEE in 1998.

[@parthasarathirout6286]

🙏asm....Give some more tips and trick for math

[@harsh.mscrm991]

thank you

[@HarmeetSingh-ou1eh]

Just squaring both side and min value is when the root term is zero and max when the root term is max check via differentiate

[@surendrakverma555]

Excellent explanation Sir. Thanks and Regards

[@dakshgaming1037]

Great explanation sir ❤️

[@DeepakKumar-sp1ph]

Sir aapko starting me positive nahi non-negative bolna chahiye

[@adityat2627]

Nice solution,but the question is trivialised by the Cauchy Schwartz inequality

[@LaughingKing40]

Sir wavy curve mhi laga sakte kya

[@sanjaypandey3642]

Good morning sir , I am Anant dev student of class 12th F I liked your explanation a lot, Thank you sir

[@sanjeevsir29077]

Thanks

[@Arpd94]

Sir aap maths ke eduniti ban jao 😂

[@adityasarraf3843]

Sir by using AM GM inequality the minima is coming as root 10 what's wrong here?

[@sanjeevsir29077]

@@adityasarraf3843 please keep in mind domain also

[@adityasarraf3843]

@@sanjeevsir29077 sir the minima is coming on x=1/2 (using AM GM inequality) which is right well in domain)

[@ravisankar8259]

How did you arrive at conclusion, sir, that the minimum is only at -2 or 3?

[@MaheshKumar-lx1ku]

😂😂😂 because function is defined between-2 and 3 only

[@MaheshKumar-lx1ku]

In Which standard u are

[@goodvibez9415]

Function has the addition of two square roots Square roots can never be negative so therefore we took 3 - x >_ 0 2 + x >_ 0 as the square root can be zero hence functioned is defined between -2 and 3 Im a 11th grader forgive me for any wrong logic

[@hypertejas.p4110]

Sir in second method differentiation is wrong... You forgot 2 in denominator in 1/√2+x.... But answer is still right how?

[@vdisonair3668]

Yeah….because 2 comes in the denominator but the lcm would be the same and also denominator is playing no role for giving critical points

[@SakshiShreya-rr2mr]

Sir I am in class 10th now, a fiitjee student but I can understand the explaination of the question very well and also able to solve it by 1st method🙏🙏🙏

[@Princesingh0004]

Bro I am in 10th class, I am not able to join any coaching because financial condition 😞. Can you pls send me modules of your coaching. Pls 🙏

[@adityadas5934]

​@@Princesingh0004 bro I will suggest u best KZbin channel to study 😢 and app to

[@mentosgamer1994]

Bhai mohit tyagi sir ke lectures dekhlo iit pakka h ❤​@@Princesingh0004

[@rutamupadhye1828]

Enjoy

[@INSTASHORTS-jh1pc]

❤