Lec-32 Compensator Design Using Root Locus Plots (Contd.)

[@souravambastha9920]

started this mind rejuvenating lecture at 9:00pm and ended up at 3:00am...love u NpTel..!!!! gd nyt..

[@andrelucio8394]

Thanks from UFMG, Brazil! Saw all your lectures! Really great!

[@satishpatel8461]

Thank you very much from Vishwakarma Government Engineering College, Ahmedabad, Gujarat, India.

[@mohinder3333]

Thanks from McMaster University, Ontario Canada!

[@johnconrad5487]

Prof M. Gopal, thank you for your series of lectures. Most lectures start with an expression for the Plant. how do I calculate this expression? is there a lecture that shows this?

[@rakidedigama]

Thanks from Asian Institute of Technology, Thailand.

[@abr6strings]

ur lecture was awesome,,,hlp me alot to undrstand this...thank u very much,,,jadavpur university

[@georgesalloum5753]

King Gopal

[@thunderdrummer1]

This stuff is so helpful. Thanks from Dublin City University, Ireland.

[@mohiminulislamnahid8352]

its a great lecture sir. thank u soo much. love and respect from east west university, dhaka

[@guilhermenunesguimaraes5662]

Thanks from Coventry University, UK. Great lectures!

[@mamba52us]

thank you from ryerson university, toronto, canada

[@muralidhar40]

Hi, dominance condition is applied when Real part of a pole is 5-10 times the real part of other poles. In the R.L. shown (in the first deaign problem), how did the professor made the pole at origin as insignificant? As gain increases, the pole moves to the left but so do the complex conjugate poles(which the professor took as dominant poles)?

[@priyanshpurohit7875]

Prof. is right. He make the line for desired zeta and see the intersection with R.L. When he got the point, he calculates the gain at that point because the design problem is to find all the closed loop poles for zeta=0.5 and that can be done by calculating K. Then he gets the value of other poles(which is no longer equal to 0 as you asked) at calculated K. Your second qsn is that complex poles moves with increasing gain, you are right, but here what we need is the CALCULATE K WHERE ZETA LINE INTERSECTS. He is not varying K. He is just finding other two poles where he has already got the two complex poles. Moreover the dominant poles are those which are closer to imaginary axis.

[@AmZmZ00]

Thanks from King Fahad University of Petroleum and Minerals , Saudi Arabia

[@5209-z2k]

There's a mistake at 38:32, K should be about 1.7 using the magnitude criteria

[@abdulhananzaroo8704]

love the way he says intuitive :)

[@gmuzz777]

Thank you from the University of Central Florida, USA

[@Doomac33]

thanks from EME, NUST, Pakistan

[@CasinoGallo]

Thanks from University of Life

[@parvathykutralingam4961]

You are the best sir...

[@adityarajchaurasia4181]

Thanx from SRMGPC, LUCKNOW 😁

[@bahadircoskuner]

Also thanks from Turkey

[@dintism]

thanks from Queensland University of Technology, Brisbane Australia

[@_akashgholap]

love you sir!!!!!!!!!!!

[@ishitol]

Thanks from Bangladesh University of Engineering and Technology

[@geobruce1995]

what is the name of the intro song?

[@mamba52us]

thank you from ryerson universuty, toronto, canada

[@michaelzhang6632]

Thanks from BTU Cottbus, Germany

[@lubwee]

Thanks, from Polytechnic of Namibia

[@alperkaracakaya]

thanks from İstanbul Technical University

[@SoorajGopakumar]

Thank you very much sir..

[@Abdullah_aljohani]

Thank you from taibah university,KSA meddinah

[@vanzwans]

Thanks from Kahosl, Gent, Belgium

[@chati1000]

thancs from Durban university of technology

[@swipersniper7471]

thank you very much sir

[@AbdulsalamKsa]

thanks from KingSaudUniversity (SaudiAabia)

[@Auautonic]

Thanks form Air University, Islamabad

[@rafapalazzo]

Thanks a lot!!!!

[@Quran_Sindhi]

thnx from IIUI Islmabad

[@alinabaraz5526]

thx

[@ghoslin1]

thanks from bit china

[@tejdalwadi5699]

God

[@krtmddhs]

i thought in china u dont do study in english