Very nice coment from the teacher at approx 28:13 when he tells his students that he is very happy by noticing that his students are not being dampened their enthusiasm even in lunch time. That is because the lecture is interesting done by the teacher capturing and keeping the interest from his students. 👏👏👏
@francoisjohnson46685 жыл бұрын
The rear wheel receive braking before the front, on vehicles that carry drum at the rear and disc at the front. This is done by a metering valve that is incorporated in the Combination valve. The emergency brake is independent of the foot operated brake, so some vehicle carry drum at the rear to facilitate the emergency brake only.
@ajaysingh65559 жыл бұрын
great lecture on longitudinal dynamics please upload more videos on automobile engineering on other topics too.
@ranjith2637 жыл бұрын
Hi, Can you please share the link for the difference between Longitudinal Dynamics and Lateral Dynamics?
@neerajkumarmishramastering83412 жыл бұрын
wonderful lecture.. can we have some vedios on three wheeler dynamics .
@robstechchannel36878 жыл бұрын
18:00 In the traction force equation you are missing the "rotational inertia factor", which has to be added as a negative force.
@tarunsharma15366 жыл бұрын
no.that inertial force is the resultant action force applied by the tyres.we considered the force applied by the ground on the tyre as tractional force which is the reaction of the ground in the forward direction.delambert force or the inertial force or pseudo force is also the resultant force but it is the action force.so we can not consider it during force balance eqn because it is a resultant force.i tried my best to explain but this is quite complicated.i hope it will help😊
@narayanarajuambati9105 жыл бұрын
Robs Tech Channel Sir,how to calculate the load transfer during retardation after the application of brakes
@pranavzamre92644 жыл бұрын
Hello. In the equation for maximum possible acceleration for either rear or a front wheel drive vehicle, the driving force 'F' is assumed to be constant in nature. However according to me the driving force F would remain constant only till the motor or driving body reaches it's peak power. After that, the driving torque and hence the generated driving force, would become a function of velocity and would continuously decrease. This is because the motor or driving body will then maintain the peak power to a constant value and keep on increasing the RPM till the vehicle reaches a terminal velocity. My question is, in the constant power mode mentioned above, the driving force F would be a function of angular velocity. In such a case, how do we calculate the maximum possible acceleration?
@tapaskoner904 жыл бұрын
I want to know the load distribution regarding articulated vehicle, like 4X2 tractor trailer, capacity 35T or 40T. And how to calculate the position of the coupling on the tractor?
@tanveerashiq37744 жыл бұрын
for gradient θ, if we don't approximate cosθ=1 and if we instead take the actual value of cosθ, the sum of Wf and Wr would not produce total weight, W. Why is that?
@nirbhay.8400k2 жыл бұрын
The sum of Wf and Wr would produce the Wcos theta component which is normal to the road surface (assuming no acceleration perpendicular to road).
@balagachaitanya23506 жыл бұрын
When Air resistance, traction force and rolling resistance act parallel to the direction of motion, how can they produce clockwise or anticlockwise moments which are perpendicular to the direction of their action
@litolraju79313 ай бұрын
also, if the braking force is being distributed to the front and back, then the maximum braking force we found for both front and rear, is it before or after distribution?
@papaveneti77594 жыл бұрын
Can we calculate the tractive force with that equation: F = n*TotalGearRatio*Te/Rw with n = Pout/Pengine, Te = engine torque and Rw= Radius of the wheel Or another equation: F = n*P/(w*Rw) where P is the power output of the engine, n = Pout/Pin and Rw = Radius of the wheel and w= rad/s of the wheel
@pramithdesai6535 Жыл бұрын
I have one concern, why is the clockwise moment taken positive, when according to the convention it should be taken negative?
@tarunsharma15366 жыл бұрын
if we do cosider angle thita as small and neglect it,so we also have to neglect wsinthita and it will no more be the case of uphilling because during climbing,the magnitude of the angle is around 30 digree or more which cant be neglected.isnt it?
@CUSenthilKumar6 жыл бұрын
I'm also having the same doubt....if u found the solution means please reply me
@joshg32485 жыл бұрын
seems like he is just simplifying the rolling resistance equation only
@ranjith2637 жыл бұрын
Hi, I have a small question. Professor has told the braking is carried out first on rear wheels and next of front wheels. What is the time difference between them to lock the wheels(front and rear)?
@tanveerashiq37744 жыл бұрын
where does he mention such a time difference?
@viragshah83834 жыл бұрын
would a complete rear braking system undergo weight transfer?
@abhiyantrik71894 жыл бұрын
the people handling the camera are selvam, robert, kartikeyan, ramkumar, ramganesh, sathiaraj
@siddhantsarraf3 жыл бұрын
Respectfully F-Y All
@abhiyantrik71893 жыл бұрын
@@siddhantsarraf 😂
@siddhantsarraf3 жыл бұрын
@@abhiyantrik7189 seriously bro I'm trying my level best to concentrate but this cameraman is 😭
@abhiyantrik71893 жыл бұрын
@@siddhantsarraf I get u. Meri samvednaye aapke sath hai 😔.
@sakthivishveshwarnaharajan860 Жыл бұрын
Why we considering L2 for Wf
@rishirao95025 жыл бұрын
do dry tyres have rolling resistance
@lsrinivasan2422 жыл бұрын
If the tyre material is not visco elastic then no rolling resistance will be there
@lsrinivasan2422 жыл бұрын
If the tyre material is not visco elastic then no rolling resistance will be there
@litolraju79313 ай бұрын
if we consider cos thetha equals 1 shouldnt sin thetha equal 0 then?
@ramakrishnan6913 Жыл бұрын
what is Ff and Fr in the eq
@sreekarachanta21194 жыл бұрын
Can I know which textbook is being used for the course?
@muthannamoe4 жыл бұрын
I want to know as well ...
@avinashrathore80814 жыл бұрын
Thomas d Gillespie fundamentals of vehicle dynamics
@victoreduardorodriguesdeca59564 жыл бұрын
Why didn't he simplified equation 6 into 8? Why is there an "l" left on both numerator and denominator. Did I miss anything? Also he used a parenthesis and then a bracket, what confused me.
@vinayneilpanda56394 жыл бұрын
he did simplify 6 to 8 at 35:12 l is total length between the wheels. The way the equation is formed makes it easier to plug values. parenthesis, bracket was a mistake
@SamarthGolwalker9 ай бұрын
where is that Pseudo Force gone ?
@darshanpabari18109 жыл бұрын
if the car is going uphill , ma or (w/g)a should be upwards , so while counting Wf , it will be in anti-clock wise direction... am i right?
@ranjith2637 жыл бұрын
ma is a inertia or D'Alembert force, which will be opposite to the direction of motion (in general)
@tarunsharma15366 жыл бұрын
no sir.actually dlambert force is basically the action that the wheel is putting on the ground and ground is giving its reaction in the form of tractional force.while taking the moments we just have to take the action forces not the reaction forces.the force which you are talking about is the reaction for that is ground is putting.so it has to be downwards.hope this will help.thanks☺
@pawanwarkhede22536 жыл бұрын
Whats the value of "mu" we should consider while calculations..??
@pavankumar-jz3gq6 жыл бұрын
all the forces in the free body diagram are o.k why again extra W/g*a mentioned in the diagram
@_isDev4 жыл бұрын
He rewrites m like W/g (W=mg -> W/g=m) that is all!!
@ravirajyaguru59058 жыл бұрын
please fire the videographer! Why is he constantly moving the camera ? Just put in one angle and focus on the board!
@gejost5 жыл бұрын
why did you care, lol. You want good cinema, go for Netflix.
@pushpendraverma15545 жыл бұрын
@@gejost idiot its very problematic to study like this
@shivamnegi4956 жыл бұрын
how to find retardation when brake is applied and how to find braking force waiting 4 ur answer
@lotfizeghmi32597 жыл бұрын
Hi, i have a simple question : can we couple the longitudinal and vertical(with modeling the pitch motion ) dynamics ? i didnt found that in any litterature books. Thank you so much.
@girdharparth5356 жыл бұрын
Lotfi Zeghmi yes you can do that by using a third damper
@girdharparth5356 жыл бұрын
Or an anti pitch bar
@rojaamgoth21288 жыл бұрын
wt is wf
@ranjith2637 жыл бұрын
Wf = Normal reaction on front tyre
@motofriend-vlog85664 жыл бұрын
Sir you assume cos(thita)≈1 that means the (thita) is very close to zero. So why we didn't write sin(thita) as zero.
@CoolDesaster4 жыл бұрын
Fcos(theta) can be approximated as F but Fsin(theta) cannot be approximated zero as the other forces in that direction are of the same magnitude. But making Fcos(theta) as F doesn't cause much error
@charlessams69814 жыл бұрын
Fcos(theta≈90)differential coefficient is 0,but Fsin(theta≈90)differential coefficient is 1,so Fsin(theta) cannot be approximated zero.
@charlessams69814 жыл бұрын
(theta≈0 sorry
@robstechchannel36878 жыл бұрын
35:16 can anybody tell me how he arrives at the rearrangement after subbing 6 into 8? For instance, where did the F from eq. 6 go?
@ranjith2637 жыл бұрын
substitute F with mu*Wf and rearrange the terms. Finally you will end up with the equation "(1+(mu*h)/L)*Wf=(l2/L+(fr*h)/L)*W". You will get the value of 'Wf'. And finally as you are well aware that Fmax = mu * Wf. Substitute. You will get the answer as on 35:16. Thank you Ranjith
@robstechchannel36877 жыл бұрын
Thank you so much!!
@NavaneethanThangavel6 жыл бұрын
Thank you so much bro!
@ragulkrishnamoorthy21026 жыл бұрын
A.Naga Ranjith Kumar thanks a lot
@JayTheMachine2 жыл бұрын
I don't feel like he is that good of a teacher. He is great at the subject but not at teaching.
@tejasharihar82574 жыл бұрын
Worst Cameraman
@VineetKumar-wp9yr7 жыл бұрын
14:44 left side of screen, thank me later :p I'm a mechanical engineer 42:30