Mod-01 Lec-07 Semi empirical Mass Formula Cont..

[@sumitachar2958]

Sir Where the term A^(3/4) comes form in the pairing term???

[@navneetmishra3208]

Empirical result by Fermi

[@gow0753]

And I think Ac(columb ) can be calculated 🤔right?

[@Aritra-M4Glacier]

This term is come from experimental results..this has no theoretical background... that's why the formula is known as semi empirical mass formula

[@omarh-nower9298]

Please can I get these lectures in pdf format?

[@ankurmalakar7803]

Great lecture ❤️

[@kathyfrejoles775]

Where did the original formula go?

[@gow0753]

I think Ac(columb ) can be calculated 🤔right?

[@IamAdarsh1414]

No, because distance between two protons are different for each pair of protons. Here the radius of nucleus is used as the distance between two protons, which is clearly an approximation. If you want to calculate it then you have to consider each pair of protons separately and calculate the energy of the system keeping in view that they are not in isolation. So other changes will also affect the calculations. It's almost impossible to calculate all these things even for one nucleus, once you do that then you will have to check whether it's applicable on the other nuclei or not because distribution of nucleons is not same for all the nuclei, even the number of protons gets changed.🙂

[@mustafacubukcu2969]

Thank you professor..

[@Iamukumar]

how to solve the question: Let Es denote the contribution of the surface energy per nucleon in the liquid drop model.The ratio Es(Al(z=13,A=27)):Es(Zn(z=30,A=64)) is:

[@divyanshshrimali2651]

Udai Kumar Es is proportional to A^2/3 so for pernucleon case it will be A^1/3, so the ratio will be (27/64)^1/3 = 3/4

[@srinugadde4676]

Surface energy per nucleon is proportional to A^-1/3 not A^1/3

[@omarhatim-p8m]

Please can I get these lectures in pdf format?

[@drashyatutorial9379]

good

[@supermario2076]

Sir av, as, ac, asym, ap are always keep fixed value?...

[@sayanjitb]

yes