Mod-02 Lec-05 Analytic functions; the exponential function

  Рет қаралды 27,563

nptelhrd

nptelhrd

Күн бұрын

Пікірлер: 11
@Madhuri20201
@Madhuri20201 4 жыл бұрын
Thanks sir for the lecture, 1 st time in the history I didn't get bore the lecture of complex analysis
@akavyascv0415
@akavyascv0415 2 жыл бұрын
I understand the concept of exponential clearly in this video .. really helpful .. tq so much sir ..
@Jkfgjfgjfkjg
@Jkfgjfgjfkjg 6 жыл бұрын
Great lecture. The use of different colors added liveliness and excitement to the the discussion.
@raghvendrapratapsingh8441
@raghvendrapratapsingh8441 Жыл бұрын
Great Explanation.
@pyrole
@pyrole 4 жыл бұрын
Thank you sir. Great introduction to Exponential functions in complex plane.
@silverfox1754
@silverfox1754 2 жыл бұрын
I am from physics i think this is not meant for mathematical physics course... I am literally lost here idk what to search for to understand less..I don't need this much for my course but how sir explains is really impressive even not being in math background i understood about 60-80% of what he's saying
@rohanagarwal1166
@rohanagarwal1166 7 жыл бұрын
Error at 51:52 It should be z= r(cos(y)+i*sin(y)) not z=r*cos(y)+i*siny
@Jkfgjfgjfkjg
@Jkfgjfgjfkjg 6 жыл бұрын
Yeah, he missed the parentheses.
@JEEFHARDY2XTREM
@JEEFHARDY2XTREM 8 жыл бұрын
Why is the image of the exponential function e^z of the vertical line x=x0 is a circle? Shouldn't it be half a circle since the image of the real axis in the function could only be the +ve axis?
@Jkfgjfgjfkjg
@Jkfgjfgjfkjg 6 жыл бұрын
It's a circle because the modulus of the image, given by e^(x_0), is fixed. It's a complete circle because the y values determine the angle; and increasing y from y_0 to y_0 + 2 pi gives one complete revolution of the circle. The reason we only got the +ve axis as the image of the whole real axis is because e^x is always positive.
@jilitkhonarzihary5260
@jilitkhonarzihary5260 4 жыл бұрын
Sir say properly I cannot concentrate
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