Induced emf and current in a loop moving perpendicular to a current-carrying wire

[@kdivyansh300]

Thing to note is, this emf is at t=0, 6:50 To find more accurate fxn of emf with time, replace r with (r+vt) in the equation of flux, and then take derivative wrt t

[@let_s_do_physics]

Thanks for your comment! Here, r is really r(t), which is a function of time. One could replace r with r_0 + vt (which requires the introduction of an intermediate variable, r_0). One should still get the same final result eventually. Note that the emf should be expressed in terms of the given variables, which does not include t. So this emf is the time-dependent emf, but the time dependency is hidden within r.