Intel Analog Question Part II

This is the second part of the previous question. Tried my best to explain it.

[@saurabhtrivedi6181]

Post Script: The charging and discharging slopes are shown to be of opposite nature. Please correct it in your notes. Thanks

[@amitbar7266]

I think the discharge and charging current are different so in negative half cycle the Vx will be less than 0.5 volts Please correct me if I am wrong !!

[@VikramSingh-hp2sn]

@10:05, 0.4Volt increment when Vleft_in= 0, it shouldn't be that way. 0.5 volt is the steady state value, so how is it able to achieve 0.1+0.4= 0.5 in very less time ( RC>> T/2).

[@ayushgaur2930]

yes this solution is probably faulty... at steady state, average voltage across the capacitor would be 0 with some ripples around it.

[@vimakuma]

concept is correct but the waveform is wrong. it's curvature shape should be opposite just like the normal charging and discharging of capacitor.

[@mayankjha7756]

Wrong waveform

[@SUSMITRUDRA]

yes bhaiya, the slopes are opposite.

[@analogeasy-peasy7559]

Yes agree that the slopes which are convex needs to be concave while the concave needs to be convex. Nice observation. Thanks :)