Interatomic Forces & Energy Curves {Texas A&M: Intro to Materials}

[@onyangoachieng9178]

What an instructor! This is superb. Kenya

[@odstknight00]

This video is so help full, you are saving my intro to strengths grade, thank you and please keep the content coming.

[@droyprimechoudhary1802]

Thanks Very Much Helpful I Was Confused And Was Curious To Understand Deeply about Elasticity In Terms Of Interatomic force.

[@hungdo4611]

This presentation is completely correct. Nothing is wrong here!

[@LonDanDoc]

Prof you are a life saver . Owe you a cold one 👍🏾

[@mr.rachetphilanthrophist601]

very very very nice explanation ,very knowledgeable teacher you are , i have always been confused in these two curves now you made it clear ........thank you

[@davysong9488]

thank you so much! this is absolutely helpful even for my gen chem class!

[@the_lord7961]

Thank you so much for making these videos. Everything makes sense now oml

[@samgu1930]

THANK YOU SO MUCH !!! It is really aid for me so much

[@BaldurKhr]

Such an easy to grasp lecture. Thank you! I imagine atoms as small balls and the electric forces as a compressed spring that tries to split them apart and a tensioned elastic rubber passing right through the middle of the spring which opposes the spring and holds the atom not to depart. Because of the elasticity of the spring and rubber, the atoms are also vibrating. Though i don't quite understand, when fire its taking place, why CO2 gains so much speed after recombination?...

[@fozansharfulhaque1973]

Wow such an amazing lecture thank you prof

[@ahmedtareq3787]

Very informative, Thanks professor 💯

[@hugom6388]

They could add on those energy graphs the point (or distance) at which the material changes state.

[@monicasenese2839]

Amazing lecture, thank you so much

[@iengineer.1686]

Crystal-clear to understand, but I have a question about the Force-radius curve. Why does the force-radius curve start from positive force to negative force. While other literatures draw starting from the negative force to positive?

[@vijay6543211]

Helped me in knowing about fundamental topics.

[@anashayajneh9510]

you are way better than my teacher👍

[@KLCII88]

Very clear video, just like the others. Thank you so much for the effort you put into these.

[@wolf.of.scbd14]

thank u mister it's helpful for my study

[@aakaspokhrel9254]

Thank you myan for this

[@Scruffyx56]

thank you for the explanation.

[@ashuemmanuel2019]

Thanks sir you've been helpful

[@toughguy9886]

Big thanks Dr.

[@serisingh]

I was hoping he would derive the modulus from the force gradient! My homework asks for the complete derivation, and of course it wasn't covered in my lecture.

[@MakeMeScientific]

Excellent explanation sir. #makemescientific

[@nicholasmerino9608]

There’s a variable involving (x) Assume x is a variable rate f(y) X simply would assume a y constant How’s that… y is the dividend

[@lostinthoughts13]

So as we approach zero,we will need to put more and more energy in order to seperate atoms,but ther is a point where we will actually get energy when atoms are seperated (that is when repulsive forces overcome attractive forces) is this correct ?

[@sivakumar-ns7pk]

What about the magnitude of bonding energy with respect to the potential well?

[@DoctoreDoom]

Amazing thanks for uploading X)

[@nicholasmerino9608]

And If y is the divider nf

[@drscott1]

Is not the Coulomb force 1/r squared?

[@siddharthvyas3078]

He is talking about Coulombic potential energy not the force, energy is = (force x distance), so the formula is correct

[@drscott1]

Siddharth Vyas now I see he wrote V and not E. Thanks

[@shashikantmishra4460]

From india❤

[@pinkybananas1]

thank you

[@pingwin2740]

oftentimes

[@nicholasmerino9608]

Of a another X(Y) derivative

[@nicholasmerino9608]

There would be a magnitude

[@nicholasmerino9608]

Calculus

[@nirupamanaik1207]

Tkh

[@mrgreatdude2]

The force curve seems to be incorrect

[@mochfakhrizal1478]

i think so. cause at r approach to zero it must be up curve. am i right?

[@naziajasmeen4203]

YAP!

[@pjshamberger]

Howdy! While energy has an absolute scale (lower energy is more stable), force depends on your coordinate system and on whether you're looking at the force of 'A on B' or 'B on A'. As I did not define the picture completely, and identify **which** force we're talking about, this could either be as shown, or with the sign of force reversed. For this reason, at the level of this video, it's easiest to think about this in terms of "attractive" or "repulsive" force, as labeled (at ~7:40).

[@김치킨-c2e]

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[@youngsukkim881]

This explanation is just imaginary. Although interatomic forces between atoms are not zero, the explanations given in this video show that the interatomic forces between atoms are zero when the interatomic distrance is set at equilibrium. In fact, it seems to remain unclear what determines the magnitude of interatomic forces acting between atoms in solids.

[@aricirwin7631]

Good presentation and great information but you said "Uh" or "Um" 15 times in the first 3 minutes. Huge distraction and all i could do is count crutch words. Sorry

[@zacherywalker5647]

oh ungrateful ass

[@glacieg2640]

thank you sir