Interesting Olympiad Math Problem | Can you solve ?

[@yurenchu]

5:03 No, you actually used "-1 x 49" in both cases, and never used the "-49 x 1" option. Moreover, in the first calculation you assumed a-7 > 7-b , in the second calculation you assumed a-7 < 7-b , and in the third calculation you assumed a-7 > 7-b again; why? And what if (a-7) = -7 and (7-b) = 7 ? You never address that special case, even though it is present among the listed options.

[@ChidexOnlineMathClass01]

Because of the factors of - 49

[@olagbajuakeju5536]

I enjoy it but it should have a single solution that can satisfy the equation Ie expect you to utilize (a+ b)2 a2 +b2 + 2ab Then bring then square up the original equation on both side and that will lead you to a+ b

[@ChidexOnlineMathClass01]

@@olagbajuakeju5536 Can l see your solution in full ?

[@モハメドイブラヒム-k8f]

the first thing to spawn to my head was to come of an example and the first was 1/14 + 1/14 = 1/7 so one of the solutions is 28. too easy hah😅

[@ChidexOnlineMathClass01]

@@モハメドイブラヒム-k8f Yes exactly

[@MrMajeed7]

You mentioned that you have reasons for introducing 49, but you never said why you did that

[@ChidexOnlineMathClass01]

@@MrMajeed7 For factorization

[@Sekar-888]

7(a+b)=ab 7a+7b-ab=0...

[@ChidexOnlineMathClass01]

Where is full solution ?

[@pavloslav]

1/8+1/56 = 1/7 8+56=64

[@ChidexOnlineMathClass01]

Nice, that's one of the solutions

[@sahandsadeghzadeh568]

only if a,b∈ Z

[@ChidexOnlineMathClass01]

Yes