Interfacing of 8086 with RAM & ROM || Problem-2

[@radhekrishnamishra5371]

I had my paper today of microprocessor in the syllabus ,there was this topic of desinging and interface of 8086, so my friend recommend your video, and i want to say it really helped bcuz same question came in our exam, And i attempted and solve it all bcuz of you, So thanks brother,

[@234_mohinizanje8]

Thanks a lot! You made it so easy. :)

[@aditimehar3834]

Thanks a lot!

[@hritikanajuk9865]

Thanku sir

[@shubh1373]

how did you calculate those 19 18 17 pins for decoder pls exploain i cant understand that part

[@megaraina8542]

design and draw system using microprocessor 8086 having eight switches connected to port b and eight led's connected to port a of 8255.2) 32 gb ram.3) 32 kb eprom.draw flow chart for sensing the switch positions and displaying it using led's. Can u plz help in this prblm

[@darnavik2930]

2 chips of 4k x 8 means 8kb so 2¹³ = 13 address line hoga na?

[@AnkitKumar-sn8hq]

Humko bhi isme confusion hai bhai, Iske pehle wale question me to 32 kb total EPROM tha lekin usme 1 chip ka space jo ki 16 kb se address line nikala tha, uss logic se to 12 hi hoga na??

[@ECQTECHASPIRANTS]

Please make this video with clearing wrong ones

[@user-ho6ii1tv3y]

Interface 2 RAM of size 4Kx8 and 1 ROM of size 8Kx8 with 8086. Answer below questions for this scenario. 1. How many address lines and data lines are needed? 2. Which decoder/multiplexer is more suitable? 3. Draw diagram of interfacing. 4. Find address range of any one device based on diagram. In this question how can I draw mamory map with only 1 ROM

[@deepakkumar-qr3ms]

for 1 rom either you can take for even or odd mapped rom S.A and E.A address as same as we find in the video

[@ECQTECHASPIRANTS]

Essme RAM bhi Two 4k×8 hai = 8KB hona na kyu In case RAM Me sirf 4KB Kiya Gaya hai ja ha par 2^12 liya Gaya hai RAM ke liye uska 2^13 hoga na

[@subhalaxmibisoyi8905]

Hlo bhai apka kuch Mpmc ka full syallbus classes ha toh toha badaiyaga ...I want to join

[@HarshitSingh-hn9sr]

Design an interface between 8086 CPU and two chips of 16K x 8 EPROM and two chips of 32K x 8 RAM. Select the starting address of EPROM suitably. The RAM address must start at F0000H. Can u tell this question . I have a doubt in it

[@vinaymishra12]

Can you please tell in which you are having doubt, wether it is in drawing address map Or in drawing the circuit?

[@subhankarkarmakar2650]

ram aur rom ta starting address ulta nahi hoga ? ROM - 00000h se aur RAM niche se ????

[@vinaymishra12]

Nhi bhai , 8086 case me physical address for BIOS jo ki rom ka part hai FFFF0 H hota hai. i.e. Rom end at FFFFF H