Intro to Inverse Functions (3 of 4: Restricted domains)

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Eddie Woo

Eddie Woo

Күн бұрын

Пікірлер: 17
@ryanlyle9201
@ryanlyle9201 4 жыл бұрын
It makes me happy that there are teachers this good in the world.
@decorumgun
@decorumgun 5 жыл бұрын
Why can't all the math teachers tie everything into a whole like this?! Thanks so much for filling in the holes for me!
@yassinejrad6997
@yassinejrad6997 6 жыл бұрын
Good lesson , you are a very good teacher, I saw one of your videos and now I'm more curious and I want to discover the world of mathematics :)
@tony91200211
@tony91200211 6 жыл бұрын
I never knew why negative root numbers were imaginary till now
@bobbob1495
@bobbob1495 3 жыл бұрын
Composition of f and its inverse isn't necessarily cOmmutative though! Right 6:30
@sabkhan2409
@sabkhan2409 Жыл бұрын
@EddieWoo thank you for a wonderful explanation, however I have a question: when we restrict the domain of the regular function to x >= 0, we get the inverse function sqrt of x, why can't we restrict the domain of the function to x
@nessadomriv
@nessadomriv 5 жыл бұрын
i love you for this.
@peixuanliu1908
@peixuanliu1908 3 жыл бұрын
This was so helpful! Thanks for helping me understand
@anthonyroper5022
@anthonyroper5022 4 жыл бұрын
Bro this is Amazing
@vishalshakya9218
@vishalshakya9218 3 жыл бұрын
You are awesome!!!!!
@doodelay
@doodelay 3 жыл бұрын
great lectures, but will say that the reason sqrt of x doesnt have a fully symmetric graph like x^2 is because the sqrt of x cannot return negative real numbers (only i values). The way he says it kinda implies that humans restrict the function by convention
@rosepierce9382
@rosepierce9382 Жыл бұрын
Why can't it though? I never really understood it. The square root of 4 should be both positive and negative 2, right?
@aissacasa5898
@aissacasa5898 Жыл бұрын
I think there is a misconception here maybe. From my point of view, we must differenciate the domain of x and the range of f(x). x cannot be negative because taking the square root of a negative number would involve finding a number that, when squared, gives a negative result, and that concept doesn't have a real-number solution in the standard mathematical framework. So, x cannot be a negative number. BUT, even if we cannot find any image of srqt(-4) for instance, this is not the reason why we remove the downside of the function graphically. It is not by restricting the domain, but by restricting the range. Because sqrt(4) is -2 and +2, we could, even with positive values of x, having two values of f(x). I have not finished yet the video of professor Eddie Woo, but we really do not restrict the domain of srqt(x), x>=0 is already the domain of the function f(x)=sqrt(x). What needs to be restricted is actually the range of the function, being R[0 ; +infinity[ instead of ]-infinity; +infinity[. Overall, it is therefore by human convention that we restrict the range in order to make sqrt(x) a function. Maybe someone could corroborate what I am talking about, because I am not confident enough to qualifying my thoughts to be the truth. EDIT: After consulting Quora forums, I fell into this topic that made me clearing everything. I think I was wrong. www.quora.com/Why-is-y-sqrt-x-a-function-if-square-roots-have-two-answers-positive-and-negative-and-a-function-can-only-have-one-output-per-input
@avi12
@avi12 6 жыл бұрын
You should have more subscribers than Vsauce Where are all the missing subscribers?
@theinfernaltoast1810
@theinfernaltoast1810 6 жыл бұрын
avi12 only the positive ones got reflected over
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