Introduction to Bond Enthalpies

[@NASCARCUP22FAN]

This is a really cool channel. Wish I was this smart.

[@barta5ot-395]

UR THE ULTIMATE CHEM TEACHER. KEEP IT UP

[@Chemteacherphil]

You don't need to multiply the O=O bond by two because for 5 moles of oxygen, you are breaking 5 moles of O=O bonds. With CO2, breaking 1 mole of bonds in CO2 requires breaking two moles of C=O bonds (as there are two C=O bonds per CO2 molecule). The same holds for water, with 1 mole of water containing 2 moles of H-O bonds.

[@Amer-rt2xe]

you helped me more than a university prof

[@shehrozbabar8648]

Thanks alot dude,it might help me in my exam after 1 hour from now😁😙

[@rahulmaik362]

thank u so much , it was neatly ecplained and it helped a lot

[@rr-cp3iw]

thanks so much you really helped me for my test tomorrow

[@gardeninginthenortheast6220]

thank you so much for this .

[@wasifjalal6965]

how the f do you know i've gotta quiz tomorrow!!!! btw thanks alot, and heres my upvote

[@CassDiGiovanni]

thank youu!!!! :)

[@armylesle]

Great video! Thank you.

[@xtraxearthling]

This was beautiful

[@ijazhidhayathullah3624]

thanks alots

[@ryooma31]

Thannk yoou very much

[@sharifaaloraibie4803]

Thanks! helped me a lot :)

[@antoniusbrown4153]

Why is it that 5 was not multiplied to get 10 But you multiplied 3 times 2 to get 6 and 4 times 2 to get 8? I am confused on that part. Phillip Cook

[@ridaanjum2130]

In calculating bond enthalpy, a double bond will be considered the same value as a single bond.This is seen as he counts the C-O bond for 3CO2 as not 3*4 but 3*2.

[@bishwajitdas6242]

hiii

[@rahulmaik362]

explained*

[@asantewaopoku]

Hey I got -2104 for the end result wht did I do wrong