Introduction to Function Notation

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Күн бұрын

Пікірлер: 21

@davidcabreramartinez4892 4 жыл бұрын

it's very very helpful, in my country they don´t understand this stuff very well, however they try to teach it, but it´s wrong and that leads to a lot of misconceptions in this formal math language. thanks ill teach others that don´t understand neither English and maths, for sure.

@TheMathSorcerer 4 жыл бұрын

@rviit2056 Ай бұрын

I'm preaparing for iitjee , and my teacher does not teach in this way . The explanation was very simple and good now all doubts are clear Thanks maths sorcerer❤

@RamanShrikant 2 жыл бұрын

thank you brother! lol im in grade 10 during the summer but i dont mind getting ahead with videos like this to make me more prepared!

@jeffrey8770 4 жыл бұрын

Hi thanks for the vid it cleared up some concepts for me. But i'm a bit confused because i think i've seen some cases where say, people write ln(x) : R --> R Wouldn't this be incorrect notation because we need every element in the domain (R) needs to be mapped to something in the codomain but obviously since ln(x) only takes positive inputs this is impossible? So would this mean that ln(x) isn't a function from R --> R but actually R>0 --> R (positive reals to reals only) ? Thanks!

@TheMathSorcerer 4 жыл бұрын

You are correct yes

@TheMathSorcerer 4 жыл бұрын

You're welcome😄

@narendra4114 4 жыл бұрын

Awesome

@ian.ambrose 3 жыл бұрын

Hi, thanks for useful video. I have question, is it allowed for function *f* to output Range instead of Codomain?

@animolwrites6909 Жыл бұрын

Sir I need advanced set theory book solution author is Charles c Pinter. can you help me

@chocolatte7736 Жыл бұрын

Function f will always have a codomain of real numbers. Instead, range is determined by the rule of function f. ex: f: R→R, f(x)=2x+1 interpretation: “Function f such that domain maps onto codomain (all real numbers), f of x equals 2x+1” 2x+1 determines the range, however the domain that is mapped onto the codomain will always be R.

@ian.ambrose Жыл бұрын

@@chocolatte7736 Thank you.

@user-amanfeildconvecture 2 жыл бұрын

Sometimes i found definition like there is unique element in B for each A,,,i wants justification that, should 'unique' be there.?

@user-lb3ex6yh9u 6 ай бұрын

If f is a function from A to B then each element of A assigns itself uniquely with an element of B. However that doesnt mean each element of A has a different relation with B. Say A= {2,-2,3} and B= {1,2,3,4,5,6,7,8,9} . So a function from A to B f(x)=x² in roster form is given by f={(2,4),(-2,4),(3,9)} Notice 2 things Every element of set A has a relation or allignment with some element of B. The elements of A +2 and -2 are related with same element 4 of B. In this case , f: A->B is a *Many to one* function. But look how no element of A is alligned with 2 elements of B.