Inverse Laplace of Complex-Conjugate Poles

[@robruble9]

was not expecting this to help but it definitely did

[@TEST22xD]

thanks from Puerto Rico!!!

[@limnasainudeen4885]

U saved so much of my time..thanks

[@MazanLabeeb]

thanks great bhai bcha lya kal k 3 number to pkay kra dya well explained

[@OasiszGaming]

There are 2 conjugates, each of which with j being negative and positive. For beta how do u know which one to pick, ie, the negative value of beta or the positive value? Thank you.

[@sherifsaid4927]

Thank You, you really helped me

[@FlibertTheEpic]

Thank you very much. Very useful video

[@StephenLongofono]

Correction: In the time-domain form, alpha should be positive, not negative. If the value of alpha is positive, that indicates an unstable system, which would end up with an exponentially growing response as t approaches infinity. If the value of alpha is negative, that indicates a stable system, and there will be an exponentially decaying response as t approaches infinity.

[@altuber99_athlete]

The video is correct from what I saw (5:09, 8:48). I didn’t hear him saying that alpha should be negative, but if he said that, he’s correct. The man in the video wrote the denominator as “s + alpha -+ j beta”. Because a root of the denominator has the form “(s - p)”, it follows the pole is “p = - alpha +- j beta”. So the corresponding exponential factor will have “- alpha” as coefficient of the exponent. If such coefficient is positive (“- alpha > 0”), the sistema is stable / the signal is bounded; hence this occurs when “alpha < 0”, which is what the video correctly states.

[@luyla1]

can u show us how u do it in the calculator? thx

[@raxx9084]

Thank you 💚❤️

[@wintergu8952]

i don't understand cause when i press calculator, i get a whole number root instead of complex root. explain pls

[@Omarkhaled19997]

obviously explained.

[@meriemel5028]

Thank u so much

[@robs7527]

Thank you!

[@Abdurrahimmm]

Can it be solved at 4th degree?Thanks

[@dr.t6034]

shouldn't it be cos(Bt-theta)?

[@Retotion]

A year late so you probably don't care anymore but cosine is an even function so the sign of theta doesn't matter

[@yagizgencer7559]

@@Retotion but theta is not alone in cosine. Do you mean cos(bt- theta) = cos(bt+theta) everywhere?

[@gib6427]

How did you calculate the sqrt of -27, I get a math error message on my calculator

[@bubbles12350]

We cannot take √-27 in calculator it's give math error

[@bubbles12350]

So,we put the equation on calculator after press=,press shit and = it give imaginary number and real numbee

[@thierrydufour4652]

In complex notation, i squared is -1, thus sqrt(-27) = sqrt(i^2 27) = i sqrt(27)

[@FoodandFeelingss]

how did you derive f(t) from f(s)? reply asap pls

[@raoufdamine851]

laplace

[@mookitty2396]

this exam saved my ass thank you so much

[@adamal-varad4503]

very well explained but wrong answers but thank you

[@SaninSelimovic-zh8eq]

can you solve this task?

[@SaninSelimovic-zh8eq]

F(s)= s^2+2s+1 / s(s^2+2s+5)

[@fawzial-tawil1643]

a lot of thx

[@julliegengastardo6547]

Sir, didn't you finish all the chapters in the book of Hayt you are using? Until Two port networks and Frequency Response? That's on the last chapters. If not, please upload videos sir. Thank you.