Inverting op-amp circuit

[@mouhamethfadalmarabyaidara4935]

Excellent and neat Explanation . My Universitary Teacher was absolutely UNABLE to break down for us the concept of amplifiers and its variants. Thanks a Lot Sir You saved me !

[@amiraliaali]

Let's change color so we won't get bored; What a true legend...

[@germas369]

10:40 removing half of the formula makes it really satisfying. idk why :D

[@etopowertwon]

Nice. Though it seems asserting that (Vo/A)=0 around 6:09 would cut calculations in half

[@santiagoolmos2423]

that is just what I was thinnking

[@Suspect42]

At that point you don't know whether you'll end up multiplying that expression by by A later on. It's not always safe to do the approximation until the end.

[@jyotijoshi98]

I believe its because he said that he was going to do it the hard way with all the algebra in case someone doesn't understand if he skips steps.

[@blockhet]

Suspect42 Yes it is. Standard calculus.

[@brightchinaka]

He chose to make life complicated lol

[@special-delivery]

Very clear video! But unnecessarily lengthy.

[@dark8759]

Very clear explanation!

[@agstechnicalsupport]

Great explanation for inverting op-amp circuit basics.

[@Griffindor21]

I finally understood🤣 Do you have other electronics tutorials or a playlist?

[@snowjunkie3673]

Thank you for this video! very helpful.

[@bravomarco2419]

아저씨 덕분에 시험문제 풀고감 감사감사. thank you.

[@PranavPandey]

Thanku

[@samuthuo]

if you multiply the top with A don't you need to do the same to the bottom? 6:34

[@gonzafernan]

He multiply both terms.

[@xhelixshotx]

Multiplying to a fraction only multiplies numerators together, and denominators together. A is only a numerator (with denominator technically 1), so it must be only multiplied to the top.

[@stormz4040]

great explanation

[@UCh-cv7ls]

why is V+ =0 (2:14)

[@usmanriaz8396]

3:19 can anybody please explain why Vr1 = Vin - v(-) ?

[@ujjwalb1729]

Hey bro how are u, the ans is 2^2. Thank you. Have a nice day.

[@gerardbuurman9170]

Very nice to hear your voice! Could you tell something about Input Offset Voltage of an Opamp PLS

[@jazbaebee]

Gerard Buurman

[@Cassius609]

Thank you!

[@graham8316]

Why can't we see r1 and r2 as a voltage divider?

[@ChrisLuigiTails]

Those videos helped me understand how to work with those, but we do things differently and our technique is easier. since (v+ - v-) = 0 and v+ = 0, that means v- = 0. That would make things much easier

[@akmal8673]

can you explain the inverting op amp in the easy method ?

[@osamahafez1232]

it is explained in the virtual ground video

[@realaxis2562]

dear please check this. I hope it will help u kzbin.info/www/bejne/hIqTqXdmrLuHocU

[@parthyadav3177]

No it's not !!

[@TeamRocketFan098]

Can't you just cross out V- since in an ideal op-amp V- = V+ and V+ is already confirmed to be zero, so V- would also be zero. That would eliminate a lot of steps...

[@jyotijoshi98]

I believe its because he said that he was going to do it the hard way with all the algebra in case someone doesn't understand if he skips steps.

[@rajwardhansagare2075]

flightlesssky you cant cance out zero to a zero its just like multiplying both sides by zero and saying LHS =RHS

[@thomaswarcup1567]

at 4.10 you substitute (V-)-(Vo) for VR2. I don't understand how.

[@jerrynonofbss2588]

Voltages across R1 and R2, based on the direction of i, so the voltage across R2 is VR2= (v-) - (Vo)

[@fernandohood5542]

Where is the real word example?

[@brightchinaka]

This could be solved in a much easier step: we know from an Ideal amp that V- = 0 so therefore every where there there is V- substitute with 0. And then just cross multiply to get Vnot. Ganz einfachhh(german (: )

[@lathap.k1610]

where is the denominator 'A' while taking LCM before grouping terms of v0 and vin

[@acad6140]

Latha P.K both equation seperated by equal sign will have A as denuminator so you can just cancel them out

[@mechanicclemont4799]

You should write as Vout... Since you wrote Vo, it is confused with V0...

[@halvulcan2842]

old but gold

[@olliesaxton901]

It confuses me why you say the gain is huge, then proceed to say the gain of the circuit is the ratio of the resistors, which could be anything even a small ratio, otherwise good explanation :)

[@yuhao9074]

where is the video with easy way

[@santiagoolmos2423]

Does a negative voltage imply that the current is going to the op-amp on the output?

[@omarsameer1254]

it means there's a 180 phase shift between the input and the output

[@qzorn4440]

ok ok... wait... i am going for some popcorn... this is my covid19 movie fix...:/ while waiting for wonderwoman and 007 to come out... Mmm, they should make a movie together...:) thanks

[@parthyadav3177]

What's the easy way??

[@gonzafernan]

In the "Virtual ground" video.

[@CopticCitzen]

you're amazing

[@phranklyn]

Thanks Norm MacDonald

[@TheAbeer99]

I must say this seems like Nicholas Cage doing the VC

[@osemudiame123]

just take v not out as a factor

[@jacobrandall4891]

Dope

[@Rjgc1991.1]

Why cant you use the correct symbols of a circuit?

[@adityasharma-sc7zo]

I can't find the video explaining the easy way.

[@shauryashekhar]

ADITYA sharma see the video inverting op amp with virtual ground

[@realaxis2562]

please try this. i hope it will help u kzbin.info/www/bejne/hIqTqXdmrLuHocU

[@NguyenMinh-bb8hz]

F.you

[@belleluze]

11:23 should have said that from the beginning!!!! What a waste of time!!! Thanks anyways Luck to all

[@gvcallen]

I think you completely missed the point of this video :D

[@telephono3448]

ASMR

[@youssefel-shabasy833]

WTF

[@fairoozzahin4414]

u made this extremely lengthy... this could have been done more easily

[@jyotijoshi98]

I believe its because he said that he was going to do it the hard way with all the algebra in case someone doesn't understand if he skips steps.

[@realaxis2562]

please check this dear kzbin.info/www/bejne/hIqTqXdmrLuHocU

[@xhelixshotx]

He literally just said that he did the easy way in another video.

[@LEON-zo7ce]

Too confusing …

[@LiuLou-o9o]

i cooked