Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET ||

[@PhysicsWallah]

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 chapter 7 | Equilibrium | Chemical Equilibrium 01 : Introduction | IIT JEE MAINS / NEET kzbin.info/www/bejne/qXS4mJh5aqZ2rJo Equlibrium | Chemical Equilibrium 02 | Equilibrium Constant Kp and Kc | IIT JEE MAINS /NEET kzbin.info/www/bejne/parVaKRrd9d6e6M&pbjreload=10 Equilibrium | Chemical Equlibrium 03 | Law Of chemical Equilibrium Numericals IIT JEE / NEET kzbin.info/www/bejne/sGOqZmWFlJyhmpY Equlibrium | Chemical Equilibrium 04 | Degree of Dissociation and Observed density IIT JEE / NEET kzbin.info/www/bejne/rmKWfGRvlK-qnbs Equilibrium || Chemical Equilibrium 05 || Le - Chatelier's Principle IIT JEE MAINS / NEET || kzbin.info/www/bejne/hIe9ZX2Ybtl_jpY ----------------- IONIC EQUILIBRIUM ------------- Class 11 chapter 7 | Equilibrium | Ionic Equilibrium 01 | Theories Of Acids and Bases JEE MAINS/NEET kzbin.info/www/bejne/i6LPYpiHfNZsesk Ionic Equilibrium 02 | Ionisation Constant Of Weak Acid and Base | Ionic Product of Water JEE /NEET kzbin.info/www/bejne/epjHq2mYm7eAmsU Ionic Equilibrium 03 || PH Of Solutions | How to find PH | How to calculate PH of any Solution kzbin.info/www/bejne/q6aqnWilbcdmkM0 Ionic Equilibrium 04 || Common - Ion Effect IIT JEE MAINS/ NEET || kzbin.info/www/bejne/rqLUaGt9qLGLiaM Equilibrium | Ionic Equilibrium 05 | Buffer Solutions JEE MAINS/NEET /JEE ADVANCE -Part 1 kzbin.info/www/bejne/gXmTqGiKj9N9l6M Equilibrium | Ionic Equilibrium 06 | Buffer Solutions JEE MAINS/ NEET/ JEE ADVANCE -Part 2 kzbin.info/www/bejne/aWHId3SjbJmqppI Ionic Equilibrium 07 || Salt Hydrolysis IIT JEE MAINS / JEE ADVANCE / NEET || pH of Salts kzbin.info/www/bejne/f2SWc6qjdt9kqbs Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET || kzbin.info/www/bejne/Z6W1lZWjp9Shmac

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sir should you also upload the video of class 12 physics in this year??

[@darshanm8287]

Physics Wallah - Alakh Pandey u r awesome no words u r the best teacher in the world

[@rishavsarkar1877]

Physics Wallah - Alakh Pandey Sir homework wala sawal ka answer option D.) hai.

[@ramanandmall2171]

ans .5×10^-2 h ya volume of solution ka koi use bhi h

[@kashishtiwari0211]

Sir next video in this series??

[@PhysicsWallah]

If you are seeing this to padaku ho tum 😂. Just kidding. Happy Deepawali to all dear students. Be safe and be blessed.

[@harshhd007gaming8]

Thanks sir

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Same tu u and celebrate pollution free Diwali sir. Ji......

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Sir when will u start resonance

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same to u sir!!

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Sir only one question is rotation complete

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The satisfaction after completing the whole series is at an another level 😌😌

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very much true

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Bhai mai ye ch start karna chahta hu kya ye kise ch se relate karta hai plz jaldi bata doo

[@mohit__meena__04]

Bhai mera bhi aaj last lecture h ye 😂

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Yai last lecture hai equilibrium ka

[@anubhavchakraborty5282]

Solution of Hwk First calculate ksp of zns ZnS = 97g Solubility = 0.97 g/L ÷ 97 = 0.01 mol/L Ksp = s×s = 10 ^ -4 Again: 2 mol Zn(No3)2 in 5L soln So solubility = 2/5 = 0.4 mol/L We assume solubity of Zn2+ ion to be 0.4 mol/L Ksp is constant So 10^-4 = S × 0.4 solving S = 2.5 × 10^-4 Option d is correct . Hope it helps 😊

[@aryanjoshi4864]

thank you so much buddy

[@nikhiljoshi3716]

Same here

[@roshanshajijohn886]

Thanks dude 👍

[@08_ankush72]

Thanks buddy

[@cricketl478]

D is correct option 2.5*10^-4

[@Muskan-qu1lu]

1:06 Class start 1:50 solubility and solibility product 7:50 solubility product 14:29 solubility 17:00 relation between solubility and solubility product 25:00 Jee 2008 question 33:20 common Ion effect 36:21 questions 42:12 JEE 2013 question 46:12 homework 47:49 ionic product and pptN 53:55 JEE question Hope it may be helpful.... Padhein krta rho😇😇

[@challenger539]

Thanks

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Thanks

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Thanks

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Thanks

[@footballgazer.]

It's help a lot

[@ayurvedicscience1656]

Now after completing this video I have reached to my equilibrium...

[@bineshkumarhimanshu6342]

me too

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Me too

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Yes

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Very very true 💗

[@mryoutuber7199]

At 28:15 cube root of 8 should be 2 by mistake sir take square root of 8 👍

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Hm

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Yess

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Still answer is correct 😅😁😁

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congratulations on your completing the chapter

[@shobu10]

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@@Study-ez6cf Bhai class mein sab answer bol denge toh tu kya karega, ye cbse ka exam nai hai ki sab ratta marke solve karenge. The teachers want u to think for yourself so that during the real exam u can do it.

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Kyu ke tum sir ke lecture dekhte ho isliye

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Real truth

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You are not big enough to bless him .

[@theoldy98years3]

sol for the hw question:- ZNS - Zn+ S- s(solubility) = 0.97g/l which we will convert to moles per litre 0.97/97= 0.01 or 1*10^-2 ksp for the above dissociation = [s][s] = s^2 = 10^-4 Zn(No3)2 -- Zn+ No3- here 2 moles of zn(no3)2 is given to find concentration = 2moles/5litre = 0.4moles/L ksp = [0.4+s']s' 0.4s'= 10^-4 s'= 10^-4/0.4 s' = 2.5*10^-4

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1:17 must say, you are a very honest person sir and you are the best teacher of my life ... Lot of love to you sir ❤️❤️❤️❤️❤️❤️❤️

[@aryaprajapati806]

Sir, JEE 2008 wale question me "s" ki value for MX2 = 2• 10^-5 aegi. Par koi baat nai, no problem sir 😅😇 You are the best teacher on KZbin ❤️ galti hoti h kavi kavi 😅 v understand sir. But ur efforts r worthy 💯😊✌🏻 Huge Respect to you sir 🙏 Edit : I noticed this comment of mine today. I was in class 10 back then. Now I have already given NEET (UG) 2022 and got AIR 345 (690/720) 😅 [1st attempt] Recalling old vibes when I used to watch Alakh sir's lectures at my home 😊💕

[@adityaagarwal9484]

Yes sir ne Galti se 8^(1/2) kar diya

[@Arinmukherjee]

Hmmm shi kaha vai

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[@shivamandshivangisrivastav52]

Han bro

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Ha Arya prajapati Maine bhi vahi socha

[@varungupta1404]

47:00 Ans I got is option d) 2.5 * 10^-4 First find Ksp of Zns aq = S^2 S of ZnS is given in g/L so convert it in mol/L no. of moles of ZnS = Mass given/ molar mass of of ZnS = 0.97g / 97g = 10^-2 S = 10^-2 mol/L Ksp = S^2 = (10^-2)^2 = 10^-4 S 0f Zn(NO3)2 = 2mol/5L = 0.4 mol/L So after write the equations, Total [Zn2+] = S'+0.4 [SO4 2-] = S' Ksp = Total [Zn2+] [SO4 2-] 10^-4 = (S'+0.4) (S') since S' is very very very small in front of 0.4 as evident from options it's Neglected 10^-4 = (0.4) (S') S' = 10^-4 / 0.4 = 2.5 * 10^-4

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Ok

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Tq

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thanku♥

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Bhai neet clear ho gaya kya aapka

[@shubhransusekharsahu26]

The new solubility of ZnS is 2.5 ×10^-4

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Neet nikle kya bhai apaka

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In the homework question, New solubility of ZnS is 2.5*10^-4 !!

[@jagatsingh7041]

Kaise aayi

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@@jagatsingh7041 bro u can find Ksp from ZnS equation

[@anandmohangupta5301]

@@jagatsingh7041 here, s becomes 10^-2 And Ksp=s^2

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👍👍

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Right ans

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By the end of this video I have completed class 11th physical chemistry syllabus on 3rd November 😀😃😄😀😀😀😀 Thank you so much sir 🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰

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wow yar mai to abhi isi chapter par hu

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@#support TeamTrees i know and 11 ko complete hone me time bhi hai so thanks for your good wish. 😉

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@#support TeamTrees yeet Use laga ek hi book hai 😂😂 Now he edited ...

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@#support TeamTrees I said I have completed physical chemistry syllabus i didn't say that i am done with whole chemistry syllabus. In chemistry there are three tracks in which I have completed one it doesn't matter that whether it is 1st book Or 2nd book just physical chemistry syllabus. Ok i am aware about how many books I have to study and how to study. OK.

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Sir aap great ho aaj ke din bhi aapne video upload kr di ,salute to u and happy diwali

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Watched all videos of this lesson by November 9 And finally equilibrium is attained 👍👍

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COMPLETED THE SERIES :D THESE WHITEBOARD LECTURES ARE ALL TIME BEST MAN!! Tysm alakh sir for this! 🧡

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OMG OMG .. I can do JEE ADVANCED questions from this chapter !!!!!!.. credit goes to Alakh sir.. tanq sir...

[@susargaming]

Sir,29:27 pe jo jee ka ksp wala question solve kiya hai,usme mx2 ki solubility galti se aapne solve karte time cube root ka square root kr diya aur 2root2 aa gya jo sirf 2 hona!

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Bilkul! Adsal likhte likhte Galti ho jati hai!

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kaushal susar tu IIT karega

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Haa sahi ha

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Right!!

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Ha

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I had a lot of trouble understanding Ionic Equilibrium but then I started to watch your videos...I have to tell you that your videos have given me crystal clear understanding and now it has become such a easy topic :) Thanks a lot Sir!!!

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From Lakshya JEE 1.0 2025 As told by Amit Mahajan Sir to revise this concept

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Same

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Same

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Same to same

[@unknown-oe9rf]

Same

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same to same

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Ionic equilibrium ke me teacher pehle din aate hi this Bolte hai ki ye chapter tough h .Isme ho skta h ki aapko kuch bhi smajh na aaye .Lekin aap ye Bolte ho ki ye bhot hi pyaara sa topic hai . 😘😘😘God bless you sir

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True

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Hamme toh kabhi nahi bola

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First of all ek like for alakh sir-Thanks a lot sir....because of you I have finished equilibrium with so many new concepts and understand it Very well.....

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Feels good after completing all the video lectures And thereby completing physical chemistry 😊

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I am falling short of words on how to thank you for finally making me understand ionic equilibrium...My concepts are crystal clear and I have gained a lot of confidence in the topic..Thank you very much Sir🙏🙏

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Congrats sir on 2 millions subscribers, sir i wish that one day u are the biggest channel on KZbin. Thank u for teaching us. 😍hamara channel best hai.

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Sir I am really lucky to have you as my physics and chemistry teacher and also mentor🙏🏻💜♥️

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Who has covered this who lecture series of equilibrium till end with complete understanding in 2020 hit like here

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It took me more than 4 days but i did it

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@@malikazhar4952Delhi U?

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@@doomzday66 me Kashmir I think u covered it very fast coz u may be fresher or repeater

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@@malikazhar4952 nah I'm 12th pass preparing for entrance

[@hariniv5543]

SIR THANKS FOR EXISTING

[@rekhamishra2000]

27:59 cube root of 8=2 not 2√2.

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I know it very well

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Hm exactly

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yeah i have the same prblm over there

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yes and thanks i was finding this comment if any other person has also observed this or not

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Ya it's actually 2

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I wish one day i could attend his lec in classroom(physically) :-)❤

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Sir belated happyy Diwali.....and happyy goverdhan pooja..arreyyy waah sir 500 k subscribers hone waale hain...congratulations... ##**sir aise hi physics chemistry ke video dalte rho...you r the best teacher on you tube. ...and no one else... Thank you

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31:52 Sir looked back in the same manner as regular teachers look back to check out who's talking whe they are teaching.😍😍

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Exactly😁

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28:00 Sir, cube root of 8 is 2 but you have written 2√2

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Satisfaction after completing whole chapter is next level.... That too with full enjoyment..... Thank-you so much Sir.... And I have experienced it 1st time, will try to move on like this further....

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Satisfaction after completing all lectures is another level❤❤😊

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Yes

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Don't have words for gratitude.

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Just in one day complete the whole ionic equilibrium (8 lecture) with full concept from 0 to 100% its difficult but I have completed I am blessed by you sir thank you so much.

[@guggillasrinu4559]

Solubility of ZnS in water is 0.01.So Ksp is 10^-4. solubility of ZnS in Zn(No3) is 2.5 *10^-4

[@mohsin2724]

same answer

[@vishantsharma-ds5lv]

correct

[@gettingit8029]

Pls explain

[@arhan6048]

@@gettingit8029 initial solubility (S) is in the form of g/L , so convert it into moles/L (M) ie; [0.974/97.4÷1]=10^-2 M Then find Ksp =10^-4 Substitute this ksp in equation i,e ; 10^-4=(S'+0.4)(S') 10^-4=0.4S' S'=2.5×10^-4 this is the final answer

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@@arhan6048 how do you get 2.5

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Completed this chapter's lectures within 24 hours.

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Sir, is video mein thoda chota reh gaya "HALLO BACHO", bada wala bhot accha lagta h.... Jo bhi ho aapka explanation bahut achcha hai 👊👊😄😄

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This video is before 4yr ,but still viewers like me is interested to see lecture to alakh sir ❤️🔥

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Happy Diwali Our Ionics Sir

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Those students who are working hard , giving there best out there .... May you crack upcoming competitive exams and get admission in your dream colleges. Keep studying, cause at last hard work pays off 💪

[@rupajha9941]

28:06 "8 ka cube root 2 hai. 2√2 Nahi."

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Your teaching way are very unique sir . Thanks sir .

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A man who knows it all.Respect 😉🙏🙏❤️😗

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my last LECTURE of chemistry finally i complete chmistry by ALAKH SIR MAY ALLAH BLESS YOU sir love from killora shopian kashmir

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Best ever teacher of Physics & Chemistry🤗🤗

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Alakh sir best and great teacher in our country India... Thank you sir for ur help ...🙏🙏🙏🙏🙏may utube sehi dekhr 90 % aya tha 11th me sir ...apki hi video dekhkr ...🙏🙏🤗🤗

[@rahilroy5307]

47:28 H.W Question:- s=0.97g/L converted into s=10^-2 mol/L Ksp = s^2 Ksp = 10^-4 Now, Conc. Of Zn(NO3)2 2 moles/5 L = 0.4M Now again find Ksp Ksp = [Zn] [S] Ksp = [s + 0.4] [s] Assume s = 0 Ksp = [0.4] [s] 10^-4 = [0.4] [s] s = 10^-4/0.4 s = 2.5 * 10^-4 👆👆 Answer

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Well-done uchiha

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my son is growing🤧

[@sweetteddy51]

Mera bhi aa gya 😊

[@vivekpatel7452]

47:32 option d will be right Thank you sir ☺️☺️☺️

[@KeerthiReddy08]

Yes 👍🏻

[@manishayadav7194]

Uh are amazing sir literally!! It' 3:20 AM and m still wd ur videos!! Cant get bored out of yo!! Thanks a lotzzz !! Iloveyou sir♥️♥️♥️♥️♥️♥️♥️♥️

[@Debsar_editz]

Sir apke jaisa koi nshi padasakta hai. You're the best🙏🏼🙏🏼. Pura YT chan-bin kar ke bhi itna accha lecture nehi mila Equillibrium ke topic pr. Salute to this man.🫡🫡

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3 saal pahale kisane socha tha ki, 1alakh naam ka banda ytb channel start karake pure india ke online education pr raj karenga💪😎 Love you alakh sir😍😍

[@Octoberman07]

Oooo sir hamare liye diwali ke din pe bhi padhaya aapne!! salute sir(with red heart)

[@yogitamukati4249]

After completing series of lectures(13) now I reached equilibrium!😎 Thankyou sir!

[@vimalsahu5480]

Are yogita tum😂

[@pradeeppahari2267]

Aapke explanation ke liye mera ek like bahut kam hai sir..... Lots and lots of thanks sir, bahut confusing lagta tha ye chapter, par aapke explanation se sab kuch crystal clear ho gya.....

[@ManishYadav-gx8ce]

Concepts are all correct, little mistake is that from AB2 salt onwards, charge of ions is not balanced in reactions.

[@shagunranaut1431]

Finally finishing equilibrium for Jee mains as a dropper 2023 from sir. All concepts are crystal clear and more than enough, able to solve pyq's just beacuse of alakh sir . I can't describe how much his dedication of teaching fill me with confidence . Thanku so much Alakh sir huge respect🙏🙏🙏🙏

[@Abhi_Tiwarii]

Oh great! so what are you studying currently after completing this ?

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@@Abhi_Tiwarii bartan manjhne ki taiyari...

[@azysgaming8410]

@@g_i_g_a_n_i_g_g_a69 💀

[@adityaagarwal636]

All the best 👍

[@pranshujassal8416]

Thankyou sir for your all efforts in equilibrium chapter. And we did approx 72 numericals acc. To my notes thanks thanks very very thanks

[@godson200]

Really interesting series naa.. This was one of the longest chapters in chemistry... Abhi mein physics ka dekh raha tha.. Electrostatics mein sir ne 160 question karaye h approx...

[@mohdtalib4992]

All the very best baccho padhaii kartae raho 👍

[@krishnakumarlalwani7611]

I'm feeling so Happy that I did that JEE ADVANCE 2013 QUESTION

[@rakeshkumarjangid3536]

Me too😄😄

[@jimhalpert9803]

It was extremely easy. Don't get your hopes high up for nothing. Adv questions aren't really that easy. I did the question in my mind itself

[@vaishaligoel2321]

@@jimhalpert9803 LOL straight up savage bruh! Nice job putting this dumbass in his place

[@prakashthakur6592]

Bhai chemistry ke advance ke bhi questions simple hote h

[@pxnishant]

@@vaishaligoel2321 Do you realize how arrogant and stupid you sound? Try being nicer for once

[@goodwillcreations4097]

Sir for home work question the answer is option d . Firstly we have to convert the given values in terms of mol/lit and proceed by the process Ksp=[zn][s]....nite neglect the conc of zn in sparingly soluble zns for easy calculation.... Hope it helps...

[@chiragbansal3822]

Yes my ans is also option (d) 2.5 x 10^-4

[@Hmx_mrx]

Finally this chapter completed 😌😅😅this Chapter was too long😂😂

[@kuldeepagrahari4345]

Bhai phir magnetism dekh le sb PTA chal jayega 😁😁

[@thalaaschoice5233]

Bhai please reply karna....ki yeh chapter me ab start kar rha hoon....or mere allen k module me jada headings h ...or sir k video thumbnail me kam Jaise ostawalds dilution law nhi dikhai de rha ...to kya wo bbi isme complete ho chuka h videos me ..

[@thalaaschoice5233]

@@kuldeepagrahari4345 bbai reply dena ....mere module me Jaise ostawalds dilution law h par sir k video thumbnail me nhi dukahi de rha h ...to kya wo bhi complete ho gya kya in videos me.. q me chpter start kar rha hoon...or mere pass time nhi h yrr...bhai bata dena yrr

[@devpatel8453]

Beluga here 😀

[@pallavprabhash6679]

@@devpatel8453 Beluga studyng for IIT to impress skittle chan

[@NM-vd9zt]

The answer of new Solubility of ZnS is 2.5 × 10 to the power minus 4 i.e., option (D) is correct. Value of Ksp = 10 to the power minus 4 Concentration of Zn(NO3) whole twice is 0.4 M and g/l into moles/l is 10 to the power minus 2 and final answer, i.e., s'= 2.5 × 10 to the power minus 4. Atomic Mass of Zn = 65 Atomic Mass of S = 32 Molar Mass of ZnS = 97 Fantastic Videos by Alakh Sir On KZbin of not only Equilibrium but also for all the other topics.

[@lokitayadav4560]

First time I found that ionic equilibrium is so easy Nd that's only bcoz of u sir 😊

[@harshrockz1640]

@@vimalsahu5480 aagya tharki😂🤣😏

[@RockySince-ks9nc]

@@harshrockz1640 nar madao ke peeche pagal hai

[@harshrockz1640]

@@RockySince-ks9nc mai nhi chote jisne msg kiya tha usne delete kiya chote dimaag laga be😏🤣🤣

[@saandilyae856]

Solubility of ZnS in water moles per litre mein 0.01M aayegi. Than Ksp find kroge toh 10-⁴ aayegi. If we mix 2 moles of Zn(No3)2 in 5 litres of solution That means 2 moles Zn²+ in 5 litre = 2/5 = 0.4 M of Zn²+ ZnS= zn²+ (S+0.4M) +. S²- (SM) Ksp= (s+0.4) (s) 10-⁴ =( s+0.4)(s) In s+0.4 ..s is small so neglected. Therefore we will only consider 0.4 not s+0.4 Now S= 10-⁴/0.4 = 2.5×10-⁴

[@divakarranjanarya1754]

Sir in NEET 2020 the same conceptual questions has been came and I regret ki Mene Aapka lecture Nahi padha tha...But in second attempt I will surely crack NEET with good marks....123 out of 180 in NEET 2020 it's all from you and I try my best to increase up to 170...

[@tonyjackstarksparrow6829]

Hua kya bhai tumhara

[@VIVEKKUMAR-tn8yd]

You are best teacher in world 🌍🌎🌎🌎🌎🌎🌎🌎🌎🌎🌎

[@annonymous9193]

Answering the question at 47:37 🔥🔥🔥"2.5×10-⁴🔥🔥🔥🔥 Correct if I am wrong😑😑

[@shauncrasta619]

Correct

[@themadhavsharmaphotography7029]

I think its 12.5 × 10‐⁴ Edit:yes yes its 2.5 walla .i by mistake took ksp as 0.05 square ...it has to be taken as 0.01 square

[@AyanKhan-oi3zp]

Plz tell me how was you solved it

[@annonymous9193]

@@themadhavsharmaphotography7029 😅😅

[@themadhavsharmaphotography7029]

@@AyanKhan-oi3zp bro take 0.01square as ksp na and ...s be the new solubility and baaki sab as pichle questions mein kiya

[@sarthak6104]

Best series ever ..for equilibrium...on this universe...must watch .. thank you alakh sir so much...!!!

[@nitinraj3862]

Solubility of ZnS -0. 01M Ksp-10-4 Ksp-(s+0.4) (s) Ksp-0.4s (as 0.4is much greater than s... We consider only 0.4) 10-4 *1/0.4-s s equal to 2.5*10-4

[@sudarshand4027]

Thnxx

[@siyachandel5858]

How we got 0.4 ?

[@promaprotity5103]

Lot of respect sir 🙏🏻🙏🏻🙏🏻 Big fan from Bangladesh 🇧🇩 Got a fully clear conception of solubility watching this whole series 🙏🏻

[@debjitgangopadhyay7713]

Thanks

[@rukaiyahussain2544]

im preparing for NEET , NEET k bacche JEE k ques solve hote h to alag level ka satisfaction milta hai..it's all because of you thanks sir.

[@shubhamwagh4256]

That's right😁😁😁😁😁

[@srushtidussal805]

Hua kya selection?

[@tusharchhajed9870]

at 29.4 cube root of 8 is 2

[@satviktripathi6285]

Sir aapki BHI personal life hogi. To fir aap Diwali ke din BHI kaise video Bana Lete Hain. U r great sir. Aur sir Aapke 500k subscriber hone vale Hain.

[@roboticswitharyan9129]

1.75

[@tiredcat6653]

1.77

[@kaushalkanta766]

1.8

[@rakshitgupta3446]

1.84

[@tanjiro7396]

1.85

[@ezhilmaranm9639]

Best all rounder teacher

[@aminamidhat]

super excellent video!! 😉😊 may Allah almighty bless you with His blessings

[@bharatmodi9841]

Now after completing this chapter I reached my equilibrium !!

[@shantilalsuhagiya9500]

Thank you sir. And the answer is 2.5×10^-4

[@enjoythelifeandnature3844]

How you got ? Please can you say

[@penguin9437]

@@enjoythelifeandnature3844 ksp= {zn} {s} =s^2 First we have to convert solubility into moles/l . That is. 0.97g/97=10^-2 moles per litre.... Put this value in first equation in place of s..we get ksp=10^-4 Now we know that nitrates are highly soluble so.. all zn come from zn(no3)2 .. now new ksp ={s•+0.4} {s} Here neglect {s•} so after solving this by putting value of ksp=10^-4 in eqn 2 we get the value s=2.5×10^-4 Hope you understand 😐👍😊

[@arpitsinha7488]

Kitna bhi saal guzar Jaye Alakh Sir ka lectures best and refreshing lgta hai

[@beginner8178]

2.5×10^-4

[@jatinawasthi2897]

First calculate ksp in water...and then find new solubility.... Because ksp is remains constant...🙏🙏

[@khushiSharma-tl1qe]

Diya Toliya plz tell me again how it will solve

[@beginner8178]

Madhu Sharma question kha H mil nii rha😐

[@khushiSharma-tl1qe]

Diya Toliya see at 47:20 min pr

[@beginner8178]

znS = Zn 2+ + S 2- s' s' s' 1st divide the 0.97/97=10^-2 mol/L then find #ksp=(10^-2)(10^-2)= 10^-4 Zn(NO3)2 = Zn +2 + 2NO3 - 2/5M 2/5M 4/5M ksp (ZnS)= (Zn) (S) 10^-4 = ( s' + 0.4) ( s') 10^-4 × 1/0.4 = s' 2.5 × 10^-4

[@dhairyasharma7782]

47:35 Ans :- New solubility of ZnS = 2.5 × 10^-4 moles/L Option (d)

[@shivangibaranwal5212]

Is this lecture good for neet aspirants?

[@shreyashtiwari8471]

Sir aap is duniya ke Sabse ache teacher hain. 🙏🙏🙏🙏

[@daraabid8972]

H/w: answer S'= 2.5×10‐⁴.( 2024 answer walo rise your hand😂)

[@themadhavsharmaphotography7029]

Equilibrium kya hota hai No one like this ever before:- Alakh sir: AAAAAHHHH chayn ki saans

[@balajiclassesbalajiclasses3076]

You can also visit my channel

[@ishaanroy2436]

Hmm

[@shresthgupta2685]

@@balajiclassesbalajiclasses3076

[@MULTIOBSERVER]

Work is god that clearly seems in you

[@kunaltalukdar429]

Fake fake

[@vineethgoudpyata7940]

Sir u r the real hero of all students