Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET ||

[@PhysicsWallah]

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 chapter 7 | Equilibrium | Chemical Equilibrium 01 : Introduction | IIT JEE MAINS / NEET kzbin.info/www/bejne/qXS4mJh5aqZ2rJo Equlibrium | Chemical Equilibrium 02 | Equilibrium Constant Kp and Kc | IIT JEE MAINS /NEET kzbin.info/www/bejne/parVaKRrd9d6e6M&pbjreload=10 Equilibrium | Chemical Equlibrium 03 | Law Of chemical Equilibrium Numericals IIT JEE / NEET kzbin.info/www/bejne/sGOqZmWFlJyhmpY Equlibrium | Chemical Equilibrium 04 | Degree of Dissociation and Observed density IIT JEE / NEET kzbin.info/www/bejne/rmKWfGRvlK-qnbs Equilibrium || Chemical Equilibrium 05 || Le - Chatelier's Principle IIT JEE MAINS / NEET || kzbin.info/www/bejne/hIe9ZX2Ybtl_jpY ----------------- IONIC EQUILIBRIUM ------------- Class 11 chapter 7 | Equilibrium | Ionic Equilibrium 01 | Theories Of Acids and Bases JEE MAINS/NEET kzbin.info/www/bejne/i6LPYpiHfNZsesk Ionic Equilibrium 02 | Ionisation Constant Of Weak Acid and Base | Ionic Product of Water JEE /NEET kzbin.info/www/bejne/epjHq2mYm7eAmsU Ionic Equilibrium 03 || PH Of Solutions | How to find PH | How to calculate PH of any Solution kzbin.info/www/bejne/q6aqnWilbcdmkM0 Ionic Equilibrium 04 || Common - Ion Effect IIT JEE MAINS/ NEET || kzbin.info/www/bejne/rqLUaGt9qLGLiaM Equilibrium | Ionic Equilibrium 05 | Buffer Solutions JEE MAINS/NEET /JEE ADVANCE -Part 1 kzbin.info/www/bejne/gXmTqGiKj9N9l6M Equilibrium | Ionic Equilibrium 06 | Buffer Solutions JEE MAINS/ NEET/ JEE ADVANCE -Part 2 kzbin.info/www/bejne/aWHId3SjbJmqppI Ionic Equilibrium 07 || Salt Hydrolysis IIT JEE MAINS / JEE ADVANCE / NEET || pH of Salts kzbin.info/www/bejne/f2SWc6qjdt9kqbs Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET || kzbin.info/www/bejne/Z6W1lZWjp9Shmac

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sir should you also upload the video of class 12 physics in this year??

[@darshanm8287]

Physics Wallah - Alakh Pandey u r awesome no words u r the best teacher in the world

[@rishavsarkar1877]

Physics Wallah - Alakh Pandey Sir homework wala sawal ka answer option D.) hai.

[@ramanandmall2171]

ans .5×10^-2 h ya volume of solution ka koi use bhi h

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Sir next video in this series??

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If you are seeing this to padaku ho tum 😂. Just kidding. Happy Deepawali to all dear students. Be safe and be blessed.

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Thanks sir

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Same tu u and celebrate pollution free Diwali sir. Ji......

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Sir when will u start resonance

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Sir only one question is rotation complete

[@ayurvedicscience1656]

Now after completing this video I have reached to my equilibrium...

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me too

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Me too

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Yes

[@shoobhecchasingh8082]

🤣🤣

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Means

[@anubhavchakraborty5282]

Solution of Hwk First calculate ksp of zns ZnS = 97g Solubility = 0.97 g/L ÷ 97 = 0.01 mol/L Ksp = s×s = 10 ^ -4 Again: 2 mol Zn(No3)2 in 5L soln So solubility = 2/5 = 0.4 mol/L We assume solubity of Zn2+ ion to be 0.4 mol/L Ksp is constant So 10^-4 = S × 0.4 solving S = 2.5 × 10^-4 Option d is correct . Hope it helps 😊

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[@roshanshajijohn886]

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[@08_ankush72]

Thanks buddy

[@cricketl478]

D is correct option 2.5*10^-4

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The satisfaction after completing the whole series is at an another level 😌😌

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Same bro😇

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very much true

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Bhai mai ye ch start karna chahta hu kya ye kise ch se relate karta hai plz jaldi bata doo

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Bhai mera bhi aaj last lecture h ye 😂

[@suxain_official8648]

Yai last lecture hai equilibrium ka

[@Muskan-qu1lu]

1:06 Class start 1:50 solubility and solibility product 7:50 solubility product 14:29 solubility 17:00 relation between solubility and solubility product 25:00 Jee 2008 question 33:20 common Ion effect 36:21 questions 42:12 JEE 2013 question 46:12 homework 47:49 ionic product and pptN 53:55 JEE question Hope it may be helpful.... Padhein krta rho😇😇

[@challenger539]

Thanks

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Thanks

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Thanks

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Thanks

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[@shobu10]

*Saare teachers class mein easy questions kara dete hain but assignments aur tests mein tough question dete hain... but Alakh sir hi class mein har variety ke questions solve karaate hain* ... *Thank you so much Sir*

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@@debu6157 kuch bhi !!! Mene concepts aur question practice ke baare me bola ki ye sab bhot kam karate hai class me aur idar sir free me itna acha question aur concepts in depth padhate hai ....ye thodi bola ki ratta marke exam me likho Par jo sikhaya hi nhi woh kaise likhe exam me itna time bhi hota hai kya sochneka exam likte waqt kuch bhi kya bolra hai bro

[@littlechamp8623]

Can anyone help me in solving doubt of equilbrium mains level

[@theoldy98years3]

sol for the hw question:- ZNS - Zn+ S- s(solubility) = 0.97g/l which we will convert to moles per litre 0.97/97= 0.01 or 1*10^-2 ksp for the above dissociation = [s][s] = s^2 = 10^-4 Zn(No3)2 -- Zn+ No3- here 2 moles of zn(no3)2 is given to find concentration = 2moles/5litre = 0.4moles/L ksp = [0.4+s']s' 0.4s'= 10^-4 s'= 10^-4/0.4 s' = 2.5*10^-4

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[@mryoutuber7199]

At 28:15 cube root of 8 should be 2 by mistake sir take square root of 8 👍

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Hm

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Yess

[@SHUBHAMSHARMA-gy6xe]

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Still answer is correct 😅😁😁

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[@varungupta1404]

47:00 Ans I got is option d) 2.5 * 10^-4 First find Ksp of Zns aq = S^2 S of ZnS is given in g/L so convert it in mol/L no. of moles of ZnS = Mass given/ molar mass of of ZnS = 0.97g / 97g = 10^-2 S = 10^-2 mol/L Ksp = S^2 = (10^-2)^2 = 10^-4 S 0f Zn(NO3)2 = 2mol/5L = 0.4 mol/L So after write the equations, Total [Zn2+] = S'+0.4 [SO4 2-] = S' Ksp = Total [Zn2+] [SO4 2-] 10^-4 = (S'+0.4) (S') since S' is very very very small in front of 0.4 as evident from options it's Neglected 10^-4 = (0.4) (S') S' = 10^-4 / 0.4 = 2.5 * 10^-4

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thanku♥

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[@aryaprajapati806]

Sir, JEE 2008 wale question me "s" ki value for MX2 = 2• 10^-5 aegi. Par koi baat nai, no problem sir 😅😇 You are the best teacher on KZbin ❤️ galti hoti h kavi kavi 😅 v understand sir. But ur efforts r worthy 💯😊✌🏻 Huge Respect to you sir 🙏 Edit : I noticed this comment of mine today. I was in class 10 back then. Now I have already given NEET (UG) 2022 and got AIR 345 (690/720) 😅 [1st attempt] Recalling old vibes when I used to watch Alakh sir's lectures at my home 😊💕

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The new solubility of ZnS is 2.5 ×10^-4

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Bhai neet clear ho gaya kya aapka

[@rahilroy5307]

47:28 H.W Question:- s=0.97g/L converted into s=10^-2 mol/L Ksp = s^2 Ksp = 10^-4 Now, Conc. Of Zn(NO3)2 2 moles/5 L = 0.4M Now again find Ksp Ksp = [Zn] [S] Ksp = [s + 0.4] [s] Assume s = 0 Ksp = [0.4] [s] 10^-4 = [0.4] [s] s = 10^-4/0.4 s = 2.5 * 10^-4 👆👆 Answer

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Mera bhi aa gya 😊

[@manshuvkafle6392]

In the homework question, New solubility of ZnS is 2.5*10^-4 !!

[@jagatsingh7041]

Kaise aayi

[@anandmohangupta5301]

@@jagatsingh7041 bro u can find Ksp from ZnS equation

[@anandmohangupta5301]

@@jagatsingh7041 here, s becomes 10^-2 And Ksp=s^2

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👍👍

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Right ans

[@anandgautamsingh4839]

By the end of this video I have completed class 11th physical chemistry syllabus on 3rd November 😀😃😄😀😀😀😀 Thank you so much sir 🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰

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@#support TeamTrees yeet Use laga ek hi book hai 😂😂 Now he edited ...

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@#support TeamTrees I said I have completed physical chemistry syllabus i didn't say that i am done with whole chemistry syllabus. In chemistry there are three tracks in which I have completed one it doesn't matter that whether it is 1st book Or 2nd book just physical chemistry syllabus. Ok i am aware about how many books I have to study and how to study. OK.

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@#support TeamTrees sorry bro don't mind.

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Ionic equilibrium ke me teacher pehle din aate hi this Bolte hai ki ye chapter tough h .Isme ho skta h ki aapko kuch bhi smajh na aaye .Lekin aap ye Bolte ho ki ye bhot hi pyaara sa topic hai . 😘😘😘God bless you sir

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True

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[@susargaming]

Sir,29:27 pe jo jee ka ksp wala question solve kiya hai,usme mx2 ki solubility galti se aapne solve karte time cube root ka square root kr diya aur 2root2 aa gya jo sirf 2 hona!

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From Lakshya JEE 1.0 2025 As told by Amit Mahajan Sir to revise this concept

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Same

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Same

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Same to same

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Same

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same to same

[@HangingQueen]

Watched all videos of this lesson by November 9 And finally equilibrium is attained 👍👍

[@avinashbhagat5784]

First of all ek like for alakh sir-Thanks a lot sir....because of you I have finished equilibrium with so many new concepts and understand it Very well.....

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COMPLETED THE SERIES :D THESE WHITEBOARD LECTURES ARE ALL TIME BEST MAN!! Tysm alakh sir for this! 🧡

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This video is before 4yr ,but still viewers like me is interested to see lecture to alakh sir ❤️🔥

[@rekhamishra2000]

27:59 cube root of 8=2 not 2√2.

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I know it very well

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Hm exactly

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yeah i have the same prblm over there

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yes and thanks i was finding this comment if any other person has also observed this or not

[@akshatmehta9776]

Ya it's actually 2

[@HealthWithDrSBT]

In 28:11 it will be 2×10^-5. Just to help others. I'm not mocking sir. Everyone is human and can make mistakes. I pointed just to help others 🙏

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Sir, is video mein thoda chota reh gaya "HALLO BACHO", bada wala bhot accha lagta h.... Jo bhi ho aapka explanation bahut achcha hai 👊👊😄😄

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3 saal pahale kisane socha tha ki, 1alakh naam ka banda ytb channel start karake pure india ke online education pr raj karenga💪😎 Love you alakh sir😍😍

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Sir aap great ho aaj ke din bhi aapne video upload kr di ,salute to u and happy diwali

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31:52 Sir looked back in the same manner as regular teachers look back to check out who's talking whe they are teaching.😍😍

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Exactly😁

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Feels good after completing all the video lectures And thereby completing physical chemistry 😊

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Satisfaction after completing all lectures is another level❤❤😊

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Yes

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I had a lot of trouble understanding Ionic Equilibrium but then I started to watch your videos...I have to tell you that your videos have given me crystal clear understanding and now it has become such a easy topic :) Thanks a lot Sir!!!

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Sir I am really lucky to have you as my physics and chemistry teacher and also mentor🙏🏻💜♥️

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Yaaaa

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I am falling short of words on how to thank you for finally making me understand ionic equilibrium...My concepts are crystal clear and I have gained a lot of confidence in the topic..Thank you very much Sir🙏🙏

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28:00 Sir, cube root of 8 is 2 but you have written 2√2

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I wish one day i could attend his lec in classroom(physically) :-)❤

[@annonymous9193]

Answering the question at 47:37 🔥🔥🔥"2.5×10-⁴🔥🔥🔥🔥 Correct if I am wrong😑😑

[@shauncrasta]

Correct

[@themadhavsharmaphotography7029]

I think its 12.5 × 10‐⁴ Edit:yes yes its 2.5 walla .i by mistake took ksp as 0.05 square ...it has to be taken as 0.01 square

[@AyanKhan_1234-d]

Plz tell me how was you solved it

[@annonymous9193]

@@themadhavsharmaphotography7029 😅😅

[@themadhavsharmaphotography7029]

@@AyanKhan_1234-d bro take 0.01square as ksp na and ...s be the new solubility and baaki sab as pichle questions mein kiya

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Congrats sir on 2 millions subscribers, sir i wish that one day u are the biggest channel on KZbin. Thank u for teaching us. 😍hamara channel best hai.

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Alakh sir best and great teacher in our country India... Thank you sir for ur help ...🙏🙏🙏🙏🙏may utube sehi dekhr 90 % aya tha 11th me sir ...apki hi video dekhkr ...🙏🙏🤗🤗

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im preparing for NEET , NEET k bacche JEE k ques solve hote h to alag level ka satisfaction milta hai..it's all because of you thanks sir.

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That's right😁😁😁😁😁

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Hua kya selection?

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SIR THANKS FOR EXISTING

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I'm feeling so Happy that I did that JEE ADVANCE 2013 QUESTION

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Me too😄😄

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It was extremely easy. Don't get your hopes high up for nothing. Adv questions aren't really that easy. I did the question in my mind itself

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Bhai chemistry ke advance ke bhi questions simple hote h

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Thank you Sir ❤. For making my NEET 11th Physical Chemistry so easy and clear in my vital drop year. The journey from the first to last was expectional. Lots of Respect and Love to you.❤🎉❤

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A man who knows it all.Respect 😉🙏🙏❤️😗

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Finally finishing equilibrium for Jee mains as a dropper 2023 from sir. All concepts are crystal clear and more than enough, able to solve pyq's just beacuse of alakh sir . I can't describe how much his dedication of teaching fill me with confidence . Thanku so much Alakh sir huge respect🙏🙏🙏🙏

[@Abhi_Tiwarii]

Oh great! so what are you studying currently after completing this ?

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@@Abhi_Tiwarii bartan manjhne ki taiyari...

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@@g_i_g_a_n_i_g_g_a69 💀

[@adityaagarwal636]

All the best 👍

[@guggillasrinu4559]

Solubility of ZnS in water is 0.01.So Ksp is 10^-4. solubility of ZnS in Zn(No3) is 2.5 *10^-4

[@mohsin2724]

same answer

[@vishantsharma-ds5lv]

correct

[@gettingit8029]

Pls explain

[@arhan6048]

@@gettingit8029 initial solubility (S) is in the form of g/L , so convert it into moles/L (M) ie; [0.974/97.4÷1]=10^-2 M Then find Ksp =10^-4 Substitute this ksp in equation i,e ; 10^-4=(S'+0.4)(S') 10^-4=0.4S' S'=2.5×10^-4 this is the final answer

[@chotu5784]

@@arhan6048 how do you get 2.5

[@NM-vd9zt]

The answer of new Solubility of ZnS is 2.5 × 10 to the power minus 4 i.e., option (D) is correct. Value of Ksp = 10 to the power minus 4 Concentration of Zn(NO3) whole twice is 0.4 M and g/l into moles/l is 10 to the power minus 2 and final answer, i.e., s'= 2.5 × 10 to the power minus 4. Atomic Mass of Zn = 65 Atomic Mass of S = 32 Molar Mass of ZnS = 97 Fantastic Videos by Alakh Sir On KZbin of not only Equilibrium but also for all the other topics.

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Those students who are working hard , giving there best out there .... May you crack upcoming competitive exams and get admission in your dream colleges. Keep studying, cause at last hard work pays off 💪

[@akul_07]

Sir belated happyy Diwali.....and happyy goverdhan pooja..arreyyy waah sir 500 k subscribers hone waale hain...congratulations... ##**sir aise hi physics chemistry ke video dalte rho...you r the best teacher on you tube. ...and no one else... Thank you

[@multinod1088]

Just in one day complete the whole ionic equilibrium (8 lecture) with full concept from 0 to 100% its difficult but I have completed I am blessed by you sir thank you so much.

[@Abcs-d1t]

How?????

[@HealthWithDrSBT]

47:37 Home work answer : New solubility of ZnS= 2.5×10^-4 (d) . Reply to my message if anyone needs solution steps

[@sam-cr8dp]

Brother i need

[@lushithelab3037]

Kota se ho? ​@@sam-cr8dp

[@lushithelab3037]

​@@sam-cr8dpAllen?

[@devashishyadav1926]

​@@sam-cr8dp if that was difficult to understand use this Solution of Hwk First calculate ksp of zns ZnS = 97g Solubility = 0.97 g/L +97 = 0.01 mol/L Ksp sxs = 10^-4 Again: 2 mol Zn(NO3)2 in 5L soln So solubility = 2/5 = 0.4 mol/L We assume solubity of Zn2+ ion to be 0.4 mol/L Ksp is constant So 10^-4 = S × 0.4 solving S = 2.5 × 10^-4 Option d is correct

[@sam-cr8dp]

@@devashishyadav1926 thankyou 🫂

[@ZAKIRHUSSAIN-os4sf]

my last LECTURE of chemistry finally i complete chmistry by ALAKH SIR MAY ALLAH BLESS YOU sir love from killora shopian kashmir

[@satviktripathi6285]

Sir aapki BHI personal life hogi. To fir aap Diwali ke din BHI kaise video Bana Lete Hain. U r great sir. Aur sir Aapke 500k subscriber hone vale Hain.

[@roboticswitharyan9129]

1.75

[@tiredcat6653]

1.77

[@kaushalkanta766]

1.8

[@rakshitgupta3446]

1.84

[@tanjiro7396]

1.85

[@Hmx_mrx]

Finally this chapter completed 😌😅😅this Chapter was too long😂😂

[@kuldeepagrahari4345]

Bhai phir magnetism dekh le sb PTA chal jayega 😁😁

[@thalaaschoice5233]

Bhai please reply karna....ki yeh chapter me ab start kar rha hoon....or mere allen k module me jada headings h ...or sir k video thumbnail me kam Jaise ostawalds dilution law nhi dikhai de rha ...to kya wo bbi isme complete ho chuka h videos me ..

[@thalaaschoice5233]

@@kuldeepagrahari4345 bbai reply dena ....mere module me Jaise ostawalds dilution law h par sir k video thumbnail me nhi dukahi de rha h ...to kya wo bhi complete ho gya kya in videos me.. q me chpter start kar rha hoon...or mere pass time nhi h yrr...bhai bata dena yrr

[@devpatel8453]

Beluga here 😀

[@pallavprabhash6679]

@@devpatel8453 Beluga studyng for IIT to impress skittle chan

[@lokitayadav4560]

First time I found that ionic equilibrium is so easy Nd that's only bcoz of u sir 😊

[@harshrockz1640]

@@vimalsahu0202 aagya tharki😂🤣😏

[@RockySince-ks9nc]

@@harshrockz1640 nar madao ke peeche pagal hai

[@harshrockz1640]

@@RockySince-ks9nc mai nhi chote jisne msg kiya tha usne delete kiya chote dimaag laga be😏🤣🤣

[@umaagarwal5607]

Me after watching this lecture: JEE ADVANCE me itne easy ques aate hai😄

[@ganeshdharaka1603]

😂🤫

[@sumannaresh4805]

Yes bro i am also thinking same

[@Deepak-gr2xm]

Nahi bro sir concept sikhane kai liye easy pick kartai hai

[@umaagarwal5607]

@@Deepak-gr2xm lekin question to advance ka hi tha na

[@doreamon450]

Same

[@vivekpatel7452]

47:32 option d will be right Thank you sir ☺️☺️☺️

[@KeerthiReddy08]

Yes 👍🏻

[@beextraordinary5113]

Satisfaction after completing whole chapter is next level.... That too with full enjoyment..... Thank-you so much Sir.... And I have experienced it 1st time, will try to move on like this further....

[@amanmoon3003]

What a coincidence, here i am watching this brilliant lecture, just 2 days before diwali.

[@BimanManna-zl6rg]

47:34 correct option d

[@divakarranjanarya1754]

Sir in NEET 2020 the same conceptual questions has been came and I regret ki Mene Aapka lecture Nahi padha tha...But in second attempt I will surely crack NEET with good marks....123 out of 180 in NEET 2020 it's all from you and I try my best to increase up to 170...

[@tonyjackstarksparrow6829]

Hua kya bhai tumhara

[@promaprotity5103]

Lot of respect sir 🙏🏻🙏🏻🙏🏻 Big fan from Bangladesh 🇧🇩 Got a fully clear conception of solubility watching this whole series 🙏🏻

[@debjitgangopadhyay7713]

Thanks

[@pragyantripathi8301]

Don't have words for gratitude.

[@anmol348]

Kyaa sir...Diwali pe toh chod dete...apki video ate hi Mann karta hai dekhlun..khuch Naya sikhne Ko milega😅😅😂😂.....akhir apki vajah se hi..mein apni class mein Physics mein 2nd rank laya Hun😋😋....love ur videos sir...and yess...Happy Diwali sir😊😊

[@ayushchoubey9996]

Sir inhe chod do aap dewali pe

[@anmol348]

Ayush choubey Kyaa Banda hai yaar😂😂....abey Etna pakadu Hota toh Diwali pe dekhta...aaj kyun Dekh Raha hai...Phaltu time khoti bass Karni hai

[@jasmehta4546]

pateli kaam maara karo kya kisine aapse poocha ki aap konse rank late ho

[@rifhatyounis630]

First ku ni aye

[@gaurigupta3880]

Chal jhutta

[@possesseddemon1206]

If someone has disliked the video just shame on them, dude ye teacher responsibility to nibha hi raha teaching ke sath me life lessons bhi deta hai, bhai we teacher small se small calculations bhi karta hai, 🙏🙏🙏🙏🙏 thanks sir for everything and sir next year I will be joining Lakshya batch of yours

[@ushabansode6337]

All concept are clear only on 1 channel 😊...Thank you sir 🙏

[@radhekrishna888azm]

Completed this chapter's lectures within 24 hours.

[@ayush6570]

Best ever teacher of Physics & Chemistry🤗🤗

[@manishayadav7194]

Uh are amazing sir literally!! It' 3:20 AM and m still wd ur videos!! Cant get bored out of yo!! Thanks a lotzzz !! Iloveyou sir♥️♥️♥️♥️♥️♥️♥️♥️

[@dhairyasharma7782]

47:35 Ans :- New solubility of ZnS = 2.5 × 10^-4 moles/L Option (d)

[@yogitamukati4249]

After completing series of lectures(13) now I reached equilibrium!😎 Thankyou sir!

[@vimalsahu0202]

Are yogita tum😂

[@bharatmodi9841]

Now after completing this chapter I reached my equilibrium !!

[@saandilyae856]

Solubility of ZnS in water moles per litre mein 0.01M aayegi. Than Ksp find kroge toh 10-⁴ aayegi. If we mix 2 moles of Zn(No3)2 in 5 litres of solution That means 2 moles Zn²+ in 5 litre = 2/5 = 0.4 M of Zn²+ ZnS= zn²+ (S+0.4M) +. S²- (SM) Ksp= (s+0.4) (s) 10-⁴ =( s+0.4)(s) In s+0.4 ..s is small so neglected. Therefore we will only consider 0.4 not s+0.4 Now S= 10-⁴/0.4 = 2.5×10-⁴

[@Debsar_editz]

Sir apke jaisa koi nshi padasakta hai. You're the best🙏🏼🙏🏼. Pura YT chan-bin kar ke bhi itna accha lecture nehi mila Equillibrium ke topic pr. Salute to this man.🫡🫡

[@musicalgroove101]

29:55 Sir in this question (8) to the power 1/3 you wrote 2root2 but it’s 2 na sir however final order is correct sir..

[@dilipmahato5745]

Happy Diwali Our Ionics Sir

[@MULTIOBSERVER]

Work is god that clearly seems in you

[@kunaltalukdar429]

Fake fake

[@saroj01566]

4 Hr me exam hey sir Ionic kuch nai samajh raha tha .. Abhi sarey doubt or concept clear ho gaye😊. Thank you so much🙏

[@Octoberman07]

Oooo sir hamare liye diwali ke din pe bhi padhaya aapne!! salute sir(with red heart)

[@daraabid8972]

H/w: answer S'= 2.5×10‐⁴.( 2024 answer walo rise your hand😂)

[@pranshujassal8416]

Thankyou sir for your all efforts in equilibrium chapter. And we did approx 72 numericals acc. To my notes thanks thanks very very thanks

[@godson200]

Really interesting series naa.. This was one of the longest chapters in chemistry... Abhi mein physics ka dekh raha tha.. Electrostatics mein sir ne 160 question karaye h approx...

[@chandrabhardwaj3582]

After seeing this lectures I thought PW sir not only a teacher but he also a good concept clearing teacher.He explaine everything with logically concept 🙏🙏👍👍👍👍.

[@themadhavsharmaphotography7029]

Equilibrium kya hota hai No one like this ever before:- Alakh sir: AAAAAHHHH chayn ki saans

[@balajiclassesbalajiclasses3076]

You can also visit my channel

[@ishaanroy2436]

Hmm

[@shresthgupta2685]

@@balajiclassesbalajiclasses3076

[@shuchisaxena7858]

Successfully watched all lectures of Equilibrium. Thanks to you sir 🔥❤️

[@nitinraj3862]

Solubility of ZnS -0. 01M Ksp-10-4 Ksp-(s+0.4) (s) Ksp-0.4s (as 0.4is much greater than s... We consider only 0.4) 10-4 *1/0.4-s s equal to 2.5*10-4

[@sudarshand4027]

Thnxx

[@siyachandel5858]

How we got 0.4 ?

[@balrajsingh1738]

Sir l never seen a teacher like you amazing sir🙂🙂🙂😊😊

[@shantilalsuhagiya9500]

Thank you sir. And the answer is 2.5×10^-4

[@enjoythelifeandnature3844]

How you got ? Please can you say

[@penguin9437]

@@enjoythelifeandnature3844 ksp= {zn} {s} =s^2 First we have to convert solubility into moles/l . That is. 0.97g/97=10^-2 moles per litre.... Put this value in first equation in place of s..we get ksp=10^-4 Now we know that nitrates are highly soluble so.. all zn come from zn(no3)2 .. now new ksp ={s•+0.4} {s} Here neglect {s•} so after solving this by putting value of ksp=10^-4 in eqn 2 we get the value s=2.5×10^-4 Hope you understand 😐👍😊

[@AkashSharma-fx8cq]

This is the first time .. I have completed ionic equilibrium without any doubt .. this is one of the best lecture on ionic equilibrium.. thank u and luv u so much sir ❤️💙

[@sameermaurya957]

Bro app ne jee dia tha?

[@AkashSharma-fx8cq]

@@sameermaurya957 yup bro .. I am currently pursuing electrical engineering from college BIT SINDRI, Dhanbad

[@sameermaurya957]

@@AkashSharma-fx8cq congratulations bro may God bless you . I am class 11th student and preparing for jee

[@aminamidhat]

super excellent video!! 😉😊 may Allah almighty bless you with His blessings

[@ashishboora4387]

Your teaching way are very unique sir . Thanks sir .