Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET ||

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3)PDF Notes of each class.
4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.
5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.
6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)
7)In case you missed a live class, you can see its recording.
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10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.
****Test Series for XI & XII****
We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.
Class 11 chapter 7 | Equilibrium | Chemical Equilibrium 01 : Introduction | IIT JEE MAINS / NEET
kzbin.info/www/bejne/qXS4mJh5aqZ2rJo
Equlibrium | Chemical Equilibrium 02 | Equilibrium Constant Kp and Kc | IIT JEE MAINS /NEET
kzbin.info/www/bejne/parVaKRrd9d6e6M&pbjreload=10
Equilibrium | Chemical Equlibrium 03 | Law Of chemical Equilibrium Numericals IIT JEE / NEET
kzbin.info/www/bejne/sGOqZmWFlJyhmpY
Equlibrium | Chemical Equilibrium 04 | Degree of Dissociation and Observed density IIT JEE / NEET
kzbin.info/www/bejne/rmKWfGRvlK-qnbs
Equilibrium || Chemical Equilibrium 05 || Le - Chatelier's Principle IIT JEE MAINS / NEET ||
kzbin.info/www/bejne/hIe9ZX2Ybtl_jpY
----------------- IONIC EQUILIBRIUM -------------
Class 11 chapter 7 | Equilibrium | Ionic Equilibrium 01 | Theories Of Acids and Bases JEE MAINS/NEET
kzbin.info/www/bejne/i6LPYpiHfNZsesk
Ionic Equilibrium 02 | Ionisation Constant Of Weak Acid and Base | Ionic Product of Water JEE /NEET
kzbin.info/www/bejne/epjHq2mYm7eAmsU
Ionic Equilibrium 03 || PH Of Solutions | How to find PH | How to calculate PH of any Solution
kzbin.info/www/bejne/q6aqnWilbcdmkM0
Ionic Equilibrium 04 || Common - Ion Effect IIT JEE MAINS/ NEET ||
kzbin.info/www/bejne/rqLUaGt9qLGLiaM
Equilibrium | Ionic Equilibrium 05 | Buffer Solutions JEE MAINS/NEET /JEE ADVANCE -Part 1
kzbin.info/www/bejne/gXmTqGiKj9N9l6M
Equilibrium | Ionic Equilibrium 06 | Buffer Solutions JEE MAINS/ NEET/ JEE ADVANCE -Part 2
kzbin.info/www/bejne/aWHId3SjbJmqppI
Ionic Equilibrium 07 || Salt Hydrolysis IIT JEE MAINS / JEE ADVANCE / NEET || pH of Salts
kzbin.info/www/bejne/f2SWc6qjdt9kqbs
Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET ||
kzbin.info/www/bejne/Z6W1lZWjp9Shmac

[@PhysicsWallah]

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 chapter 7 | Equilibrium | Chemical Equilibrium 01 : Introduction | IIT JEE MAINS / NEET kzbin.info/www/bejne/qXS4mJh5aqZ2rJo Equlibrium | Chemical Equilibrium 02 | Equilibrium Constant Kp and Kc | IIT JEE MAINS /NEET kzbin.info/www/bejne/parVaKRrd9d6e6M&pbjreload=10 Equilibrium | Chemical Equlibrium 03 | Law Of chemical Equilibrium Numericals IIT JEE / NEET kzbin.info/www/bejne/sGOqZmWFlJyhmpY Equlibrium | Chemical Equilibrium 04 | Degree of Dissociation and Observed density IIT JEE / NEET kzbin.info/www/bejne/rmKWfGRvlK-qnbs Equilibrium || Chemical Equilibrium 05 || Le - Chatelier's Principle IIT JEE MAINS / NEET || kzbin.info/www/bejne/hIe9ZX2Ybtl_jpY ----------------- IONIC EQUILIBRIUM ------------- Class 11 chapter 7 | Equilibrium | Ionic Equilibrium 01 | Theories Of Acids and Bases JEE MAINS/NEET kzbin.info/www/bejne/i6LPYpiHfNZsesk Ionic Equilibrium 02 | Ionisation Constant Of Weak Acid and Base | Ionic Product of Water JEE /NEET kzbin.info/www/bejne/epjHq2mYm7eAmsU Ionic Equilibrium 03 || PH Of Solutions | How to find PH | How to calculate PH of any Solution kzbin.info/www/bejne/q6aqnWilbcdmkM0 Ionic Equilibrium 04 || Common - Ion Effect IIT JEE MAINS/ NEET || kzbin.info/www/bejne/rqLUaGt9qLGLiaM Equilibrium | Ionic Equilibrium 05 | Buffer Solutions JEE MAINS/NEET /JEE ADVANCE -Part 1 kzbin.info/www/bejne/gXmTqGiKj9N9l6M Equilibrium | Ionic Equilibrium 06 | Buffer Solutions JEE MAINS/ NEET/ JEE ADVANCE -Part 2 kzbin.info/www/bejne/aWHId3SjbJmqppI Ionic Equilibrium 07 || Salt Hydrolysis IIT JEE MAINS / JEE ADVANCE / NEET || pH of Salts kzbin.info/www/bejne/f2SWc6qjdt9kqbs Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET || kzbin.info/www/bejne/Z6W1lZWjp9Shmac

[@kiranprakash1663]

sir should you also upload the video of class 12 physics in this year??

[@darshanm8287]

Physics Wallah - Alakh Pandey u r awesome no words u r the best teacher in the world

[@rishavsarkar1877]

Physics Wallah - Alakh Pandey Sir homework wala sawal ka answer option D.) hai.

[@ramanandmall2171]

ans .5×10^-2 h ya volume of solution ka koi use bhi h

[@kashishtiwari0211]

Sir next video in this series??

[@PhysicsWallah]

If you are seeing this to padaku ho tum 😂. Just kidding. Happy Deepawali to all dear students. Be safe and be blessed.

[@harshhd007gaming8]

Thanks sir

[@sonajain8820]

Same tu u and celebrate pollution free Diwali sir. Ji......

[@harshhd007gaming8]

Sir when will u start resonance

[@kumardeepaksahu34]

same to u sir!!

[@vedantprajapati4307]

Sir only one question is rotation complete

[@kirantripathi8878]

Now I'm going to complete my half yearly syllabus and I have watched only ur videos....😘😘😘😘

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Bhai kitne chapter Hoge physics men tere

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Teacher like u born after centuries I wish I talk to u face to face

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Work is god that clearly seems in you

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Fake fake

[@amanmoon3003]

What a coincidence, here i am watching this brilliant lecture, just 2 days before diwali.

[@prasannakabra5133]

Finally completed this beautiful series with alakh sir....thank you so so so much sir.....can't express my happiness😊😊😊

[@ShakilAhmed-tv5de]

Finally completed whole series' very satisfied..all concepts are cleared ..thank you so much sir❤

[@ScrollWithSoham]

47:37 Home work answer : New solubility of ZnS= 2.5×10^-4 (d) . Reply to my message if anyone needs solution steps

[@sam-cr8dp]

Brother i need

[@lushithelab3037]

Kota se ho? ​@@sam-cr8dp

[@lushithelab3037]

​@@sam-cr8dpAllen?

[@devashishyadav1926]

​@@sam-cr8dp if that was difficult to understand use this Solution of Hwk First calculate ksp of zns ZnS = 97g Solubility = 0.97 g/L +97 = 0.01 mol/L Ksp sxs = 10^-4 Again: 2 mol Zn(NO3)2 in 5L soln So solubility = 2/5 = 0.4 mol/L We assume solubity of Zn2+ ion to be 0.4 mol/L Ksp is constant So 10^-4 = S × 0.4 solving S = 2.5 × 10^-4 Option d is correct

[@monicagupta1258]

Sir please release your next lecture on Solubility product, as you promised at the end🙏

[@ShivamSharma-yc8mh]

Jee wallah pe chle jaao

[@aditirangari10]

The satisfaction after completing the whole series is at an another level 😌😌

[@gettingit8029]

Same bro😇

[@eddy18457]

very much true

[@ember6263]

Bhai mai ye ch start karna chahta hu kya ye kise ch se relate karta hai plz jaldi bata doo

[@mohit__meena__04]

Bhai mera bhi aaj last lecture h ye 😂

[@suxain_official8648]

Yai last lecture hai equilibrium ka

[@ayurvedicscience1656]

Now after completing this video I have reached to my equilibrium...

[@bineshkumarhimanshu6342]

me too

[@Nothing-ly6bt]

Me too

[@PankajKumar-vh9ld]

Yes

[@shoobhecchasingh8082]

🤣🤣

[@fanningclub6821]

Means

[@mryoutuber7199]

At 28:15 cube root of 8 should be 2 by mistake sir take square root of 8 👍

[@SHUBHAMSHARMA-gy6xe]

Hm

[@angelbajaj5326]

Yess

[@SHUBHAMSHARMA-gy6xe]

@@angelbajaj5326 hm

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Still answer is correct 😅😁😁

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These type of comments should be at top ..... 🙄🙄🙄

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Sr aapke lacture dhekne k liye PHYSICS WALLAH dalne ki jarurat ni hoti h top pr aapki hi video millti h ...😉😘😘

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Bilkul sahi mere bhai

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Ya right

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shaurya prajapat

[@skp5330]

Truely 👍agreed

[@aaradhyanagar5127]

Very very true 💗

[@anubhavchakraborty5282]

Solution of Hwk First calculate ksp of zns ZnS = 97g Solubility = 0.97 g/L ÷ 97 = 0.01 mol/L Ksp = s×s = 10 ^ -4 Again: 2 mol Zn(No3)2 in 5L soln So solubility = 2/5 = 0.4 mol/L We assume solubity of Zn2+ ion to be 0.4 mol/L Ksp is constant So 10^-4 = S × 0.4 solving S = 2.5 × 10^-4 Option d is correct . Hope it helps 😊

[@aryanjoshi4864]

thank you so much buddy

[@nikhiljoshi3716]

Same here

[@roshanshajijohn886]

Thanks dude 👍

[@08_ankush72]

Thanks buddy

[@cricketl478]

D is correct option 2.5*10^-4

[@sumitnagar8367]

Sir topic search krne k baad physicwallh likhne ki jarurat hi nahi padti..Aap ki vedio hi sabse phele Aati he ..

[@fedodedo9212]

He was my popular then

[@NaitikSrivastava1]

👍

[@dj_7118]

Kyu ke tum sir ke lecture dekhte ho isliye

[@armanlasker4037]

@@dj_7118 are nahi meine pehli bar inka class kar raha hu phirvi age dikh raha hain

[@dj_7118]

@@armanlasker4037 power of physics wallah🙌

[@Muskan-qu1lu]

1:06 Class start 1:50 solubility and solibility product 7:50 solubility product 14:29 solubility 17:00 relation between solubility and solubility product 25:00 Jee 2008 question 33:20 common Ion effect 36:21 questions 42:12 JEE 2013 question 46:12 homework 47:49 ionic product and pptN 53:55 JEE question Hope it may be helpful.... Padhein krta rho😇😇

[@challenger539]

Thanks

[@fact4science750]

Thanks

[@Kiteretsu_fan]

Thanks

[@adityaagarwal636]

Thanks

[@footballgazer.]

It's help a lot

[@malikazhar4952]

Who has covered this who lecture series of equilibrium till end with complete understanding in 2020 hit like here

[@doomzday66]

It took me more than 4 days but i did it

[@malikazhar4952]

@@doomzday66 where from u r

[@doomzday66]

@@malikazhar4952Delhi U?

[@malikazhar4952]

@@doomzday66 me Kashmir I think u covered it very fast coz u may be fresher or repeater

[@doomzday66]

@@malikazhar4952 nah I'm 12th pass preparing for entrance

[@daraabid8972]

H/w: answer S'= 2.5×10‐⁴.( 2024 answer walo rise your hand😂)

[@aryaprajapati806]

Sir, JEE 2008 wale question me "s" ki value for MX2 = 2• 10^-5 aegi. Par koi baat nai, no problem sir 😅😇 You are the best teacher on KZbin ❤️ galti hoti h kavi kavi 😅 v understand sir. But ur efforts r worthy 💯😊✌🏻 Huge Respect to you sir 🙏 Edit : I noticed this comment of mine today. I was in class 10 back then. Now I have already given NEET (UG) 2022 and got AIR 345 (690/720) 😅 [1st attempt] Recalling old vibes when I used to watch Alakh sir's lectures at my home 😊💕

[@adityaagarwal9484]

Yes sir ne Galti se 8^(1/2) kar diya

[@Arinmukherjee]

Hmmm shi kaha vai

[@madhurammodi31]

haa sahi kaha

[@shivamandshivangisrivastav52]

Han bro

[@ashapravinkumarbarot6531]

Ha Arya prajapati Maine bhi vahi socha

[@VaradDandawate]

From Lakshya JEE 1.0 2025 As told by Amit Mahajan Sir to revise this concept

[@Suparna29]

Same

[@maroofnazar3196]

Same

[@BOtGaming-ff6vm]

Same to same

[@unknown-oe9rf]

Same

[@satyavatisoni6316]

same to same

[@shobu10]

*Saare teachers class mein easy questions kara dete hain but assignments aur tests mein tough question dete hain... but Alakh sir hi class mein har variety ke questions solve karaate hain* ... *Thank you so much Sir*

[@sankulkunjara7607]

Han aisa Hi hota hai 🥺🥺

[@Study-ez6cf]

Ha😔 Itna kam concepts aur bakwas question karate hai class me Par exam me kuch aur hi ata hai

[@debu6157]

@@Study-ez6cf Bhai class mein sab answer bol denge toh tu kya karega, ye cbse ka exam nai hai ki sab ratta marke solve karenge. The teachers want u to think for yourself so that during the real exam u can do it.

[@Study-ez6cf]

@@debu6157 kuch bhi !!! Mene concepts aur question practice ke baare me bola ki ye sab bhot kam karate hai class me aur idar sir free me itna acha question aur concepts in depth padhate hai ....ye thodi bola ki ratta marke exam me likho Par jo sikhaya hi nhi woh kaise likhe exam me itna time bhi hota hai kya sochneka exam likte waqt kuch bhi kya bolra hai bro

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Can anyone help me in solving doubt of equilbrium mains level

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Me after watching this lecture: JEE ADVANCE me itne easy ques aate hai😄

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😂🤫

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Yes bro i am also thinking same

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Nahi bro sir concept sikhane kai liye easy pick kartai hai

[@umaagarwal5607]

@@Deepak-gr2xm lekin question to advance ka hi tha na

[@doreamon450]

Same

[@manshuvkafle6392]

In the homework question, New solubility of ZnS is 2.5*10^-4 !!

[@jagatsingh7041]

Kaise aayi

[@anandmohangupta5301]

@@jagatsingh7041 bro u can find Ksp from ZnS equation

[@anandmohangupta5301]

@@jagatsingh7041 here, s becomes 10^-2 And Ksp=s^2

[@rangnathkendre4778]

👍👍

[@doreamon450]

Right ans

[@susargaming]

Sir,29:27 pe jo jee ka ksp wala question solve kiya hai,usme mx2 ki solubility galti se aapne solve karte time cube root ka square root kr diya aur 2root2 aa gya jo sirf 2 hona!

[@kingshukbanerjee3983]

Bilkul! Adsal likhte likhte Galti ho jati hai!

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kaushal susar tu IIT karega

[@omprakashrana667]

Haa sahi ha

[@aakankshajain8988]

Right!!

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Ha

[@shubhransusekharsahu26]

The new solubility of ZnS is 2.5 ×10^-4

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Neet nikle kya bhai apaka

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congratulations on your completing the chapter

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without u i would have fail in this chapter... people in coaching think we know everything u are the only one who teach from basic to advance MAY GOD BLESS YOU

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100 % correct....idiotic caoching centre

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Real truth

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Why talking like "ELDERS" Wait a minute who are you to bless him... BTW you do not deserve

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@@आयुष-न5ब Right 💯 brother

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You are not big enough to bless him .

[@varungupta1404]

47:00 Ans I got is option d) 2.5 * 10^-4 First find Ksp of Zns aq = S^2 S of ZnS is given in g/L so convert it in mol/L no. of moles of ZnS = Mass given/ molar mass of of ZnS = 0.97g / 97g = 10^-2 S = 10^-2 mol/L Ksp = S^2 = (10^-2)^2 = 10^-4 S 0f Zn(NO3)2 = 2mol/5L = 0.4 mol/L So after write the equations, Total [Zn2+] = S'+0.4 [SO4 2-] = S' Ksp = Total [Zn2+] [SO4 2-] 10^-4 = (S'+0.4) (S') since S' is very very very small in front of 0.4 as evident from options it's Neglected 10^-4 = (0.4) (S') S' = 10^-4 / 0.4 = 2.5 * 10^-4

[@gursheenks]

Thank you so much!!

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Ok

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Tq

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Thank you it helped 😇🤗🤗

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thanku♥

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Your physical chem lectures are awesome i m loving it😍😍

[@rekhamishra2000]

27:59 cube root of 8=2 not 2√2.

[@uttamtripathi2707]

I know it very well

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Hm exactly

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yeah i have the same prblm over there

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yes and thanks i was finding this comment if any other person has also observed this or not

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Ya it's actually 2

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Who is getting annoyed from Chauhan sir ki

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Dimag kharab ho gaya hai chauhan sir ki guide se

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Ha 😂😂😂😂😂😂

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Exactly

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sir physics mai plzzz plzzz jo PDF dalte ho na usme board par likha huva mat hatao plzzz sir plzz....revision mai bohot help hoga plzz 🙁🙁🙁🙁

[@StalkingPeopleHmm]

Mujhe aur nhi dikha raha

[@anandgautamsingh4839]

By the end of this video I have completed class 11th physical chemistry syllabus on 3rd November 😀😃😄😀😀😀😀 Thank you so much sir 🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰

[@goldensiddiqui]

wow yar mai to abhi isi chapter par hu

[@anandgautamsingh4839]

@#support TeamTrees i know and 11 ko complete hone me time bhi hai so thanks for your good wish. 😉

[@goldensiddiqui]

@#support TeamTrees yeet Use laga ek hi book hai 😂😂 Now he edited ...

[@anandgautamsingh4839]

@#support TeamTrees I said I have completed physical chemistry syllabus i didn't say that i am done with whole chemistry syllabus. In chemistry there are three tracks in which I have completed one it doesn't matter that whether it is 1st book Or 2nd book just physical chemistry syllabus. Ok i am aware about how many books I have to study and how to study. OK.

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@#support TeamTrees sorry bro don't mind.

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Is this lecture good for neet aspirants?

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Kon kon ye videos neet 2024 ke liye dek rha hai

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Mai Nepal se hu sir ka vedio dekh raha hu

[@sportzmania992]

Sir,namaste....sir wo jo jee 2008 wallah sawaal hai.....wahan 8 ka cube root to 2 hoga naaa....2root2 kese❤❤❤❤❤

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I am watching this lecture 1 month before jee 2024

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Hope you get the best result bro🎉

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Same lol

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​@@tanuupadhyay9024 it's reason is pw vidyapeeth, because there's no quality teacher is present 😢. They wasted my dropyear.

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I think every offline institute have same condition😐

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@sunandakokitkar4959 Are yaar 300 student me top 3 me hamesa aata hu wo bhi 130 marks ke under,to isme bhi hum 300 student ki hi galti hai , concept hi nahi clear karate , class boring kar dete hai ,1 bhi advance ka question khud teacher solve nahi kar pate ye bhi hamari galti hai😒

[@annonymous9193]

Answering the question at 47:37 🔥🔥🔥"2.5×10-⁴🔥🔥🔥🔥 Correct if I am wrong😑😑

[@shauncrasta619]

Correct

[@themadhavsharmaphotography7029]

I think its 12.5 × 10‐⁴ Edit:yes yes its 2.5 walla .i by mistake took ksp as 0.05 square ...it has to be taken as 0.01 square

[@AyanKhan-oi3zp]

Plz tell me how was you solved it

[@annonymous9193]

@@themadhavsharmaphotography7029 😅😅

[@themadhavsharmaphotography7029]

@@AyanKhan-oi3zp bro take 0.01square as ksp na and ...s be the new solubility and baaki sab as pichle questions mein kiya

[@sangeetha-do5lm]

OMG OMG .. I can do JEE ADVANCED questions from this chapter !!!!!!.. credit goes to Alakh sir.. tanq sir...

[@Hmx_mrx]

Finally this chapter completed 😌😅😅this Chapter was too long😂😂

[@kuldeepagrahari4345]

Bhai phir magnetism dekh le sb PTA chal jayega 😁😁

[@thalaaschoice5233]

Bhai please reply karna....ki yeh chapter me ab start kar rha hoon....or mere allen k module me jada headings h ...or sir k video thumbnail me kam Jaise ostawalds dilution law nhi dikhai de rha ...to kya wo bbi isme complete ho chuka h videos me ..

[@thalaaschoice5233]

@@kuldeepagrahari4345 bbai reply dena ....mere module me Jaise ostawalds dilution law h par sir k video thumbnail me nhi dukahi de rha h ...to kya wo bhi complete ho gya kya in videos me.. q me chpter start kar rha hoon...or mere pass time nhi h yrr...bhai bata dena yrr

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Beluga here 😀

[@pallavprabhash6679]

@@devpatel8453 Beluga studyng for IIT to impress skittle chan

[@CareerFlux]

Sir aap great ho aaj ke din bhi aapne video upload kr di ,salute to u and happy diwali

[@notmything889]

How many of you completed Equilibrium do like👇👇👇👇👇👇👇👇

[@ShiviSinha-tm9kg]

28:00 Sir, cube root of 8 is 2 but you have written 2√2

[@laxmankhorwal9052]

I wish one day i could attend his lec in classroom(physically) :-)❤

[@divyansh1391]

Sir you are amazing person teaching in front of camera is very difficult with this much interest. I pray to God to keep you healthy.... 👏🙏🙏🙏🙏🙏🙏🙏🙏

[@Priya-tl2cu]

Bhai neet clear ho gaya kya aapka

[@saandilyae856]

Solubility of ZnS in water moles per litre mein 0.01M aayegi. Than Ksp find kroge toh 10-⁴ aayegi. If we mix 2 moles of Zn(No3)2 in 5 litres of solution That means 2 moles Zn²+ in 5 litre = 2/5 = 0.4 M of Zn²+ ZnS= zn²+ (S+0.4M) +. S²- (SM) Ksp= (s+0.4) (s) 10-⁴ =( s+0.4)(s) In s+0.4 ..s is small so neglected. Therefore we will only consider 0.4 not s+0.4 Now S= 10-⁴/0.4 = 2.5×10-⁴

[@rupajha9941]

28:06 "8 ka cube root 2 hai. 2√2 Nahi."

[@satyendrakumarsingh889]

Sir, is video mein thoda chota reh gaya "HALLO BACHO", bada wala bhot accha lagta h.... Jo bhi ho aapka explanation bahut achcha hai 👊👊😄😄

[@satviktripathi6285]

Sir aapki BHI personal life hogi. To fir aap Diwali ke din BHI kaise video Bana Lete Hain. U r great sir. Aur sir Aapke 500k subscriber hone vale Hain.

[@roboticswitharyan9129]

1.75

[@tiredcat6653]

1.77

[@kaushalkanta766]

1.8

[@rakshitgupta3446]

1.84

[@tanjiro7396]

1.85

[@rahilroy5307]

47:28 H.W Question:- s=0.97g/L converted into s=10^-2 mol/L Ksp = s^2 Ksp = 10^-4 Now, Conc. Of Zn(NO3)2 2 moles/5 L = 0.4M Now again find Ksp Ksp = [Zn] [S] Ksp = [s + 0.4] [s] Assume s = 0 Ksp = [0.4] [s] 10^-4 = [0.4] [s] s = 10^-4/0.4 s = 2.5 * 10^-4 👆👆 Answer

[@animeVIP-i4w]

Well-done uchiha

[@Asinine_37]

my son is growing🤧

[@sweetteddy51]

Mera bhi aa gya 😊

[@theoldy98years3]

sol for the hw question:- ZNS - Zn+ S- s(solubility) = 0.97g/l which we will convert to moles per litre 0.97/97= 0.01 or 1*10^-2 ksp for the above dissociation = [s][s] = s^2 = 10^-4 Zn(No3)2 -- Zn+ No3- here 2 moles of zn(no3)2 is given to find concentration = 2moles/5litre = 0.4moles/L ksp = [0.4+s']s' 0.4s'= 10^-4 s'= 10^-4/0.4 s' = 2.5*10^-4

[@utkarshyadav916]

Kisko pata tha voh solubility product ka dusra lecture kabhi nahi aayega. RIP - Ksp lecture 02 😂😂😂

[@tusharchhajed9870]

at 29.4 cube root of 8 is 2

[@gamingwitharjun4869]

COMPLETED THE SERIES :D THESE WHITEBOARD LECTURES ARE ALL TIME BEST MAN!! Tysm alakh sir for this! 🧡

[@physicswallahfun440]

1:17 must say, you are a very honest person sir and you are the best teacher of my life ... Lot of love to you sir ❤️❤️❤️❤️❤️❤️❤️

[@ajaykumarbantu3122]

Anyone from February... Come on we are on path.. We can do this❤❤❤❤❤

[@adityaprakashgupta4536]

Yes 👍

[@spandanp5723]

Which class are u in now

[@spandanp5723]

@@adityaprakashgupta4536 which class r u innow

[@mohammedowais4812]

march

[@sangita1553]

@@mohammedowais4812 me too completing ionic equilibrium

[@guggillasrinu4559]

Solubility of ZnS in water is 0.01.So Ksp is 10^-4. solubility of ZnS in Zn(No3) is 2.5 *10^-4

[@mohsin2724]

same answer

[@vishantsharma-ds5lv]

correct

[@gettingit8029]

Pls explain

[@arhan6048]

@@gettingit8029 initial solubility (S) is in the form of g/L , so convert it into moles/L (M) ie; [0.974/97.4÷1]=10^-2 M Then find Ksp =10^-4 Substitute this ksp in equation i,e ; 10^-4=(S'+0.4)(S') 10^-4=0.4S' S'=2.5×10^-4 this is the final answer

[@chotu5784]

@@arhan6048 how do you get 2.5

[@ScrollWithSoham]

In 28:11 it will be 2×10^-5. Just to help others. I'm not mocking sir. Everyone is human and can make mistakes. I pointed just to help others 🙏

[@parmodsiyag3884]

Ionic equilibrium ke me teacher pehle din aate hi this Bolte hai ki ye chapter tough h .Isme ho skta h ki aapko kuch bhi smajh na aaye .Lekin aap ye Bolte ho ki ye bhot hi pyaara sa topic hai . 😘😘😘God bless you sir

[@shelly0938]

True

[@exosujunct4932]

Hamme toh kabhi nahi bola

[@TawrinJenifer-wd2dh]

2024😂👇

[@HangingQueen]

Watched all videos of this lesson by November 9 And finally equilibrium is attained 👍👍

[@yashmaurya665]

1:22 watching on diwali 12/11/2023 this is called perfect timing 😀✌

[@hariniv5543]

SIR THANKS FOR EXISTING

[@aayushjoshi3681]

31:52 Sir looked back in the same manner as regular teachers look back to check out who's talking whe they are teaching.😍😍

[@adithyabaliga893]

Exactly😁

[@jokernevermind8900]

Absolutely crct

[@shashwatvaish5009]

😍😍😍

[@shwetabharade2254]

Completed whole series.... Now I'm in equilibrium...😂😂

[@akanshasrivastav6821]

Feels good after completing all the video lectures And thereby completing physical chemistry 😊

[@HamzaMahar-xx6vm]

It's awesome 😮😊😊😊

[@radhekrishna888azm]

Completed this chapter's lectures within 24 hours.

[@akul_07]

Sir belated happyy Diwali.....and happyy goverdhan pooja..arreyyy waah sir 500 k subscribers hone waale hain...congratulations... ##**sir aise hi physics chemistry ke video dalte rho...you r the best teacher on you tube. ...and no one else... Thank you

[@scak37]

2023 students here

[@sweetteddy51]

47:34 d) 2.5 × 10-4 😎

[@renunag9718]

Congrats sir on 2 millions subscribers, sir i wish that one day u are the biggest channel on KZbin. Thank u for teaching us. 😍hamara channel best hai.

[@TrayambTripathi]

8 ka cuberoot 2 hoga sir 28:20

[@ashokram4491]

Satisfaction after completing all lectures is another level❤❤😊

[@39anuragroy9f7]

[@ramramramramramramramramram7]

Yes

[@priyankachakraborty8353]

Ans for hw - d)2.5 x 10^-4

[@arifkhan9026]

Same here

[@musama5098]

Sir love from pak🤝❤️

[@aasmaminhaj7557]

Us you from?

[@nanu9424]

KYA KARU COACHING JAANE KA DIL NHI HOTAA........ 😥😥😥😥😥😥😥😥😥😥😥😥😥😥

[@vedanshisharma392]

Bhai ek lakshya tai karo.. Newton ko bhi class me jaane ka mann nai karta tha but now who doesnt know who newton is ....😌

[@SaurabhKumar-iz1ce]

Bhai me 2 yr

[@MukeshSingh-wk5bj]

Issac Newton very true

[@shivanshshukla3292]

To Kai baap k rupiya uda diye coaching m

[@lazycat8348]

@@shivanshshukla3292 ha🤣

[@titan_x564]

Sir aapne Next questions wala lecture dala hi nahi Ab kya kare hum...?

[@rekhakholiya210]

47:33 Home work Answer : Option 4- 2.5 × 10^-4 moles / litre

[@salikbashir]

Bro can you explain a bit, i am getting different answer

[@krishnakumarlalwani7611]

I'm feeling so Happy that I did that JEE ADVANCE 2013 QUESTION

[@rakeshkumarjangid3536]

Me too😄😄

[@jimhalpert9803]

It was extremely easy. Don't get your hopes high up for nothing. Adv questions aren't really that easy. I did the question in my mind itself

[@vaishaligoel2321]

@@jimhalpert9803 LOL straight up savage bruh! Nice job putting this dumbass in his place

[@prakashthakur6592]

Bhai chemistry ke advance ke bhi questions simple hote h

[@code_what]

@@vaishaligoel2321 Do you realize how arrogant and stupid you sound? Try being nicer for once

[@manishayadav7194]

Uh are amazing sir literally!! It' 3:20 AM and m still wd ur videos!! Cant get bored out of yo!! Thanks a lotzzz !! Iloveyou sir♥️♥️♥️♥️♥️♥️♥️♥️

[@DShreyRay]

Sir : Aapne shayad ye padh rakha ho... Me: No sir...sb aapse hi padh rhe h pahli baar!

[@dominuscosmicus4477]

sir jab aap aaj padne ke bare mein bol rahe thain papa ne sun liya unka mooh bandh ho gaya phir puure din shaant rahien someone watching this with me??? if yes pls reply or like What a coincidence, here i am watching this brilliant lecture, just 2 days after diwali.

[@beginner8178]

2.5×10^-4

[@jatinawasthi2897]

First calculate ksp in water...and then find new solubility.... Because ksp is remains constant...🙏🙏

[@khushiSharma-tl1qe]

Diya Toliya plz tell me again how it will solve

[@beginner8178]

Madhu Sharma question kha H mil nii rha😐

[@khushiSharma-tl1qe]

Diya Toliya see at 47:20 min pr

[@beginner8178]

znS = Zn 2+ + S 2- s' s' s' 1st divide the 0.97/97=10^-2 mol/L then find #ksp=(10^-2)(10^-2)= 10^-4 Zn(NO3)2 = Zn +2 + 2NO3 - 2/5M 2/5M 4/5M ksp (ZnS)= (Zn) (S) 10^-4 = ( s' + 0.4) ( s') 10^-4 × 1/0.4 = s' 2.5 × 10^-4

[@multinod1088]

Just in one day complete the whole ionic equilibrium (8 lecture) with full concept from 0 to 100% its difficult but I have completed I am blessed by you sir thank you so much.

[@mhj.xd7]

sir jii im little confused with the last question how K(ip)=[Ca]*[F]2 ?? i think it must be K(ip)=[Ca]*[2F]2 ????

[@mdsaleemamdsaleemabegum8975]

Video released at 7th Nov Thala for a reason💛

[@mohanlale677]

Vaise to aap 1 ghanta padhate ho.lekin ham hai hoshiyar..... Aadhe ghante mai hi padh Lete hai😁😅

[@meetpatel4905]

speed * 2

[@themadhavsharmaphotography7029]

Equilibrium kya hota hai No one like this ever before:- Alakh sir: AAAAAHHHH chayn ki saans

[@balajiclassesbalajiclasses3076]

You can also visit my channel

[@ishaanroy2436]

Hmm

[@shresthgupta2685]

@@balajiclassesbalajiclasses3076

[@ArjunSingh-jv8iy]

School : 😰😰😰😨😨 Common ion effect oh noooo. PW : yessssss common ion effect 😊😊😊😊 ab maja aye ga

[@tiwaristudystudio3397]

Who is here from session 2022-2023??

[@anushkasingh016]

28:02 cube root of 8 is 2 🙂

[@smarikamalviya57]

I agree 👍

[@KhushiKumari-ef4cg]

Yes

[@vibhavyadav2167]

Sir how ans is correct right order must be MX>MX2>M3X

[@Lakshmijagadeeshchannel]

Chota chota mistake hota hay

[@anirudhgupta8985]

Yeah I also thought something was wrong there

[@DrJ-cq8en]

Next lecture kab upload hoga solubility ka?

[@iamme7991]

This video is before 4yr ,but still viewers like me is interested to see lecture to alakh sir ❤️🔥

[@hvtopvlogs9633]

Sir we miss white board ye video sbse best hai

[@harshavardhanvatti8501]

Sir ³√8=2 not 2√2

[@wizardfromgryffindor8148]

Sir I am really lucky to have you as my physics and chemistry teacher and also mentor🙏🏻💜♥️

[@VickyChaturvedi180]

Yaaaa

[@IndiLores709]

Answer of home work question is (d) - 2.5 × 10^4

[@rakeshkumarshukla9007]

Kaise solve kiya?😐

[@shikharmehar3388]

Tell me how u solved

[@rakeshkumarshukla9007]

@@shikharmehar3388 are yarr galt samjh gaya tu🙄 Maine to solve karne ko bal raha tha kyo ki mera answer galt aa raha tha😀

[@sudarshanmundhe5666]

Right

[@archanaagrawal4924]

Correct

[@lptpapna993]

THANK YOU SIR!!!!!!!!!!!

[@pulkitupadhyay3621]

Welcome

[@manvendrasingh4369]

Who is watching this in 2021