Proton NMR Skills (Benzene Derivatives) - Part 1

[@xenrielle1]

This was one of the better NMR videos that I have found so imagine my disappointment when I found that this was your only one!

[@916213]

PLEASE continue making videos! this is the only video that has made sense for me for h nmr

[@rubensbrazilianbrothers]

the ortho, meta and para explanation helped me a lot, thanks.

[@megodzillaudeadable]

Was just about to say the same thing, I wish my prof told it to us like that LOL

[@babiliraq9871]

Please continue the explanation 🙏 I love your method to understand the organic chemistry

[@BungSmuggler]

I have no idea what your talking about, but I really enjoyed you telling me about it!

[@ali.b3104]

Simp lmao

[@BungSmuggler]

@@ali.b3104 I wonder what brought you to this video. I was actually interested in this. You?

[@ali.b3104]

@@BungSmuggler I have a spectroscopy class in university and this was recommended to me!

[@BungSmuggler]

@@ali.b3104 Very good! Yeah maybe I simped out a little 😉🤪

[@ali.b3104]

@@BungSmuggler too bad she stopped making videos 5 years ago :/

[@bigrndahouse]

I was looking for part 2 and couldn't find it. I'm so bummed. You explain it so well.

[@chikeokjr24]

Degree of detail and everything... just so clutch. U got a subscriber, please make more!

[@tixxi10]

thank u sm omg ive been struggling so much until i found this video!

[@katherinecabrera3761]

This was so helpful!!!! Part 2 please!!!

[@MichaelTheThinker]

The broad 1H alcohol exchange peak DOESN'T appear anywhere throughout the entire HNMR spectrum. If you see it in the 10 - 12 ppm range, then it is most likely a carboxylic acid. I found out the hard way after failing the NMR part of my chemistry exam. Thanks a lot Janci.

[@MichaelTheThinker]

You stated such at 3:58

[@kingmikey87]

The ortho, meta, para explanation really helped thanks! It sucks tho cause my nmr exam questions don't have molecular formula given, just need to work it out based on substituents!

[@AlishaMir]

i cant find a part 2 to this?? this was so helpful, please make more!

[@kennedyodiboh6612]

This is SUCH a great explanation video. Thank you so much

[@minkway522]

You are so clear and articulate.

[@lokichinni]

Amazing work. Made it really simple.. Great Job... :)

[@meganchu4816]

It's not easy to find such an amazing video. I learned a lot, please keep it up. Awaiting for your next video. :-)

[@TarikAbdulla]

Well explained,,, this is really the easiest to understand... Thank You Ma'am.

[@samman9478]

Thank you sooooo much, you’re a blessing to all of us 💚💚 thanks again really

[@sotongtian]

Will you do an explanation on phenol in 13C NMR? :)

[@ishmeetsingh1146]

Keep uploading lady Don’t stop

[@xxitsxnadyaxx]

Great video, really connected the dots for me

[@nimeshafernando4724]

This video was really helpful. Thanks alot

[@TiTaN18]

lovely ,great tutorials really awesome

[@alitalinn]

OMG THIS IS AMAZING!! but where is part 2? :(

[@rebeccaairabaliton8136]

this was so helpful i wish there was a part 2

[@MrVorpal1]

Thank you, hoping for more and the mountain goats are great.

[@hadtmagana3273]

You're so good! Please make more videos

[@deogratias948]

There's another formula that calculates the number of double bonds : x - (y/2) + (z/2) + 1 with CxHyNz

[@harunurroshid8840]

Oh my god! You're the real MVP

[@abida1640]

This was very well explained! Thank you

[@akiramenaide6945]

Amazing explanation helped me alot...thank you..

[@Strokemeclockwise]

if only i found you before my ochem final

[@zainabal-bakaa5511]

This really helped, thank you ❤️

[@7_info]

Helpful for 1H. If possible upload 13C, Mass spectrometry, IR etc. Thank you.

[@priyadarshanibandara1151]

video was very helpful for me in my exam.thank you

[@uddhavjaju7412]

Hey thanks for the video.. Where can we see your more videos. Means many videos are private.. 🙁

[@nooranoureldin421]

Nice shirt and even nicer explanation, thank you so much! God bless you ❤

[@mamu7mich]

Thank you so much! when is the part 2 coming?

[@JanciDespainXD]

+mamu7mich i wish i had time.... this semester has been crazy. um..... soon? :)

[@iranirajkonwar1542]

How many signals we get for acetophenone

[@ramihammoud355]

@@JanciDespainXD its been 7 years and still no part two 😭

[@juanjaquezable]

Thank you! this video really helped

[@sharkbait2466]

For para substitution, why is it a doublet of doublet? For one of my labs, the compound I have is para substituted, and just like you said it is a doublet of doublet (also has the distinctive roofing effect). Why isn't it two triplets?

[@JanciDespainXD]

+AWMrocks hmmm, this would be a lot easier to explain in person, or on paper. but i'll do my best. draw a benzene ring with an "X" substituent, and para to X, add a "Y" substituent. let's call the H's adjacent to substituent X, "Ha," and let's call the H's adjacent to substituent Y, "Hb." protons Ha create one signal because they are identical to each other. each one of them has X one one side, and one proton (Hb) on the other side. that one adjacent proton causes splitting into a doublet. likewise, protons Hb create one signal because they are identical to each other. each one of them has Y one one side, and one proton (Ha) on the other side. that one adjacent proton causes splitting into a doublet. the chemical shifts of protons Ha and Hb will likely be different because of the differing electronegativities of substituents X and Y.

[@christopherwitecki6649]

Very helpful, thank you.

[@amnee23]

Very helpful, thank you!

[@muhammadayananwar7912]

Thank you. This was really helpful. I'm a beginner so I just wanted to clarify are the 3 hydrogen environments in a substituted benzene distinct? For e.g in the first compound that you showed. If so then why is the integral considering them all as the same environment?

[@JanciDespainXD]

Good question! On an exam your prof will consider them distinct, but since the signals overlap so much, they'll prob be considered as one on the NMR spectrum.

[@muhammadayananwar7912]

@@JanciDespainXD thank you

[@tiibrahim5714]

Thank u very much for the video. Really helpful

[@bayearegay3314]

Relly good

[@swarx666]

Love u madam.....really helpful.

[@thomaspellegrini-t1y]

Hi, your links are not working

[@charmainelindsay6783]

Thanks you! This really helped

[@RD_Blgs_com]

Can you tell me about the nitrobenzene Spectra

[@alchemical1988]

good..ineed help for you in hmr?

[@Yuki_Matsumoto_7]

Hi. I loved your video! Btw, I have one question. How did you get those red lines of integration to measure and then calculate the integration?

[@JanciDespainXD]

A lot of times you won't need them. You might be given the integrations already calculated (like 2H or 3H) above each signal. Or you might be given calculations of their relative heights below the spectrum. But on the rare occasions you're given integrations in the "curvy line" format, I wanted you to know how to handle it. Hope that helps!

[@Yuki_Matsumoto_7]

@@JanciDespainXD OH, thank you very much. I've seen that integration red line in the book McMurry - Organic Chemistry, now I understand. Btw, I asked because in a database (sdbs.db.aist.go.jp/sdbs/cgi-bin/direct_frame_top.cgi) I looked at the HNMR spectrums and there was no integration red line neither "2H", "3H". There is information of peaks if you search an HNMR spectrum and then click on "peak data"... but I don't know how to interpret that. I think that there's more information of those peaks than peaks themselves... so how can I interpret that? and what is "int."? is it integration or intensity or...? Thank you very much n.n

[@JanciDespainXD]

@@Yuki_Matsumoto_7 Int. would be integration. If they give you numbers, for example, 321, 212, 113. Divide each value by the smallest and round to the nearest whole number.. They usually won't be this obvious and easy to deal with, but the first, 321/113 would be 3H. 212/113 would be 2H. 113/113 would be 1H.

[@Yuki_Matsumoto_7]

@@JanciDespainXD oh, thank you so much. Seriously n.n 😍😍😁😁

[@tiibrahim5714]

Please can u do video on trisub. benzene ring

[@nasyibaharshad5960]

where can i see part 2?

[@abhishekroushan6958]

Ma'am please keep making videoes

[@zeeshankhan3513]

would you please tell me how to prepare meta-nitro toulene.

[@JanciDespainXD]

something tells me i'm REALLY late to this party. benzene, 1. acetyl chloride, AlCl3, 2. HNO3, H2SO4, 3., Clemmensen Reduction

[@dineshkrishna1904]

madam according to u,that is first acylation and then nitration and go for clemmensen reduction we obtain m-nitro ethyl benzene but not m-nitro toluene

[@shivanshtripathi8252]

mam plz make a video on fries rearrangement with detailed Mechanism

[@luisfernandodiazp]

Beautiful and Intelligent... Wow...!!!

[@anilhugoabdulhaqwilliams4613]

Nice and easy.

[@healthawareness6639]

excellent

[@TheRainbow54321]

great help, tq so much!

[@zohaibkamran8609]

Beautiful

[@Raghadnu]

شكرا شرح راىع

[@donajin3761]

where is part 2??

[@hanieamini2561]

great and helpfull

[@jamesprince571]

We want Ur latest chem videos plzzz..

[@SuperMelcior]

nice

[@alley3590]

I came here to learn.. where to add(ortho, meta , para) substituent... But didn't get my answer

[@chbakrr1407]

Thanks 🙆‍♂️🌸

[@notreemchii]

WHERES PART 2???!!!!!!

[@74mackd]

You...Are...Awesome

[@kantamero12]

Thaaank you so much , I was hopeless

[@b46_shashankvishwasdamle66]

thankyou very much

[@sultanalshammari3745]

Thank you that was interesting

[@ghazal9207]

Awesome thanks alot

[@aniahjmary1256]

Why do you say 4 double bonds is for benzene? Doesn’t benzene only have 3 double bonds

[@Cazz313]

thank you!

[@sonuparsad5170]

Give me notes for detection of compond

[@flawiyamore1453]

can you please solve this for me an organic compound having molecular formula C5H11Cl gave following H'NMR data delta1.0(t,3H),delta1.5(s,6H),delta1.8(q,3H) deduce the structure of the compound

[@TraaaangLeee]

THANK YOU SO MUCH :)

[@anadmytrejchuk631]

and ketones???

[@abhishekroushan6958]

Awesome

[@saberhassan1325]

Where is part 2

[@aadityvishavakarma3774]

Pyridine example

[@pamplemousse5546]

You look a a lot like Monica from Friends, even the same voice lol. Great video tho.

[@sianfell8938]

It's 3 double bonds tied up in benzene :/

[@BossManWebbMerica]

yes but 4 DBE since benzene is cyclic. that being said idk why she said "just completely ignore oxygen" or why she specified that the obvious carbonyl would have to be an aldehyde... but I couldn't have done better myself.. I'm way more frustrated by the pervasive inappropriate advances in this comment section :'{

[@billygr183]

Danke schoen^^

[@rajeev181178]

Dbe=(C+1)-(H+X-N)/2

[@kldblded1465]

i wish u could be my proff

[@rishabhtrivedi7184]

Need pretty teacher's like you 😍😍

[@drmarwaabdelazizfergany4462]

thank you so much may you tell me how could i know the number of hydrogens attached to carbon in non-aromatic compounds?

[@raadrawaad1059]

مرحبا ياريت اكو شرح بالعربي

[@Sim-pIe]

your unsaturation formula is wrong, you add nitrogens, and subtract halogens not the other way around.

[@minhyeokko3515]

It's actually tied to () which has minus in front.... you know what it means!

[@ranaemara1388]

thanks u r soo cute 😍

[@mohamedsllam4757]

ترجمه💔😔

[@alil8419]

i love u ..😐

[@upanddownfact5453]

mam You are looking sister of Michal Jackson

[@riksrangmomin4252]

Cant understand😂

[@reko491]

Nice shirt lol 😜😂

[@Isteshhad]

BAWSSS

[@norman9052]

Something about nerdy women; so attractive.

[@v.r.kildaire4063]

tastes like cherry