Japanese | A Nice Math Olympiad Problem

Japanese | A Nice Math Olympiad Problem

[@jokeb0t114]

You can also just use the sum of a goemetric progression formula: (a(r^n-1))/(r-1) where a = 9, r = 9, n = 5. (9(9^5-1))/8 = 66429

[@kalitovskiwra4997]

you still have 9^5

[@katielarmore498]

this might be a stupid question but why wouldn't you just multiply and add them

[@AutistizJiznaku]

I think you are not allowed to have calculator

[@patrikvrba647]

Because it saves time (it is likely a time based competition because the problem is not difficult) but I would personally stop at (81)(82)(10)+9 because you can calculate that very fast in your head