Japanese | Can you solve this ? | Nice Algebra Math Problem

[@SidneiMV]

(9/8)^x + 23(8/9)^x - 10 = 0 (9/8)^x = u u² - 10u + 23 = 0 u = (10 ± 2√2)/2 u = 5 ± √2 (9/8)^x = 5 ± √2 *x = [ln(5 ± √2)]/(2ln3 - 3ln2)*

[@MasterTMathsClass]

Nice one