Japanese | Can you solve this ? | Nice Math Olympiad Algebra Problem

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[@janobdrzalek5635]

Easier is it in the exponential form: -1=exp(iп ), so 4th square of-1 is exp(iп/4)=cos(п/4) + i sin(п/4)

[@cosmolbfu67]

Why +-√(+-2i) no solution?

[@sandytanner9333]

√(2i) can be simplified to 1+i

[@fano72]

Very nice, the approach and extraction of I. Most of the calculation is identical on both sides, you can reduce some work.

[@jamalsaber6903]

M= racine carrer de (_2) ou racine carrer de 2.et faire un verefication

[@eugen2495]

Я бы посмотрел и проверочное решение

[@michaelpurtell4741]

I think maybe your approach is not the simplest or the preferred approach: consider m= +/-root i times root 2.This is +/-(e^ipi/4times root 2) This is +/- (1/root2+i/root2)root2 or +|- 1+/-I Or am I wrong ?

[@salimkaaggeliki854]

Χαίρομαι πολύ τα βίντεο σου!!!!!!!!!!!! ❤❤❤❤❤❤❤

[@learncommunolizer]

Thank you very much ❤️❤️❤️

[@rodicacojoc3636]

Corec tot ! Nu îmi place însă că linia de fracție e pusă aiurea . Corect ar fi ca aceasta, linia de fracție, să fie trasată între liniuțile semnului egal.

[@user-qj3wt2qk7j]

Корень квадратный из 2i

[@marceloboda9953]

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