Japanese l can you solve this Exponential Logarithmic Problem?? X=?

[@mashabali786]

❤❤❤

[@bigjobbies]

what you can do with logs never ceases to amaze me

[@michaeldoerr5810]

The answer is x = 10. I thought that I needed a sanity check and I am goad that I was able to check. I shall use that for practice!!!

[@prollysine]

10^(logx*log27) + 10^(logx*log9) = 36 , (10^(logx*log3))^3 + (10^(logx*log3))^2 = 36 , let u=10^(log3*logx) , u^3 + u^2 +/- u -36=0 , (u-3)(u^2+4u+12)=0 , u=3 , 10^(log3*logx)=3 , log3*logx=log3 , +1 -3 logx=1 , x=10^1 , x=10 , / for complex , u^2+4u+12=0 , / +4 -12 test , x=10 , 10^log27+9^log10 = 27+9 = 36 , OK , +12 -36=0 , solu , x=10 ,