Possibly a stupid question: how do you get the full conditional proportionality first shown at 9:39? How do we "make it proportional to the target distribution of interest"?
@NuclearSpinach2 жыл бұрын
Same question at 14:47
@NuclearSpinach2 жыл бұрын
Is it as simple as p(theta k given everything else) = p(theta, alpha, beta | y) / p(theta_{-k}, alpha, beta | y)? I.e., is it simply using f(x|y) = f(x,y)/f(y), and here the constant would be f(y)?
@jaradniemi2 жыл бұрын
@@NuclearSpinach Yes, that's it!
@GaryMirams9 жыл бұрын
Really helpful - thanks. Any chance you could provide/link to the bladder cancer dataset and the code you discussed?
@valerioguarrasi72036 жыл бұрын
Where can we find the code and the dataset? Thankyou