JEE: Sequences & Series L7 | Relation between Means | Unacademy JEE | Maths | Sameer Chincholikar

[@UnacademyJEE]

Follow Sameer Chincholikar Sir on Unacademy App: unacademy.onelink.me/081J/50f44dde

[@hksfiregaming7844]

Question ka solution kaise sochte haii

[@Moscow.369]

@@hksfiregaming7844 😭😭😭

[@sanjaykumardas5372]

Thanks for sharing

[@saifhasan.1]

AMAZING SESSION... ❣️

[@AbhishekSrivastava-o5q]

1:24:06 revise the question again

[@AbhishekSrivastava-o5q]

1:24:07 📌📌📌📌📌📌📌📍📍📍📍📍📍📍📍📍📍📍📍📍📍📍📍

[@AbhishekSrivastava-o5q]

1:44:41 📌📌📌📌📌📌📌📌🕑🕑📌

[@Birendra887]

53:20 sir we can also split the numerator to get the expression - a/b + b/a+ c/a + a/c + c/b + b/c Now we can apply am gm inequality for these six fractions. We get - (Req. Expression)/6 >= [a/b*b/a*c/b*b/c*a/c*c/a]^(1/6) (Req. Expression)/6 >= 1 Therefore req expression >= 6 So minimum value of req expression is 6. I feel this is the better way.

[@bhaiharjotsinghbhaiharpree7133]

Yes this is also a very good solution by the way.

[@naughtyorwhat8697]

Main ne bhi yehi kiya

[@SatyamSingh-ef8sj]

Yes this is also a right approach . Thanks for sharing it

[@arkusgigantia5403]

Very 👍

[@shreejithk5041]

Smart

[@ntclasses6432]

❤❤❤❤

[@sakshikushwah8488]

55:59 Just split whole expression into 6 terms (b/a+C/a+C/b+a/b+a/c+b/C) /6>=1

[@Sky_infy]

1:44:17 another approach...a²+b²≥2ab and x²+y²≥2xy and then ax+by/2≥ (axby)^1/2. Use these equations answer 1

[@Prathamesh-hx2dz]

Kisine pucha?

[@GoldiSharma__03]

1:30:27 pr kaise solve huaa😢

[@SatyamSingh-ef8sj]

2:16:34 hw q

[@Sky_infy]

@1:30:15 be careful... Sir uss samay aage soch rahe the. Sir ne dimag me hi solution kar liya tha isiliye Aisa sab ho gaya. Answer sahi tick kiye

[@GoldiSharma__03]

53:44 Wale question me . Am greterthan hm se bhi to ho raha hai sir directly when a,b,c are positive number 😅

[@sidd5672]

At 1:50:50 wow sir 😁😁😁😁😁😁

[@a-man3460]

Sir at 1:31:33 me ≤ka sign hoga na tabhi toh hum a2b3c4ka maximum value likh payengey

[@kiranshakya2029]

Yes exactly 💯

[@itn2055]

53:00 sir is question ko to ham direct bhi kar sakte the sabko open karke

[@NeerajkumarDas_337]

2:16:00 finished

[@sushiladevi1638]

At 5:16 lecture fired

[@aryakichetan3351]

Dear students, short trick for sum at 1:17:02 is.......take a=2, b=2, c=2 so ab+bc+ca =12 so abc is 8 hence greatest value of abc is 8😊

[@utkarshbelieve8062]

Love u sir

[@fagaming9591]

start from here 5:22

[@OmSonar-ef7nq]

excellent

[@anirudhkumar3500]

I love you sir gi because I think you are my ❤️

[@srikrishnaaditya7692]

1:31:17 minimum value is d

[@TanmayMathur-kb7gt]

💗💕🔥💞👑🌟♥️pro really good techer with amazing content

[@CHANDANIKUMARI-lo1du]

Sir 1:30:30 me inequality wrong hai n

[@v3nom619]

Sir at 1:31:07 par inequality ki sign ulti hogi

[@garvit_bansal]

13:00 lecture

[@bikram091]

Thank you 🙏 sir

[@pritampramanik8854]

56:55

[@aryakichetan3351]

Dear Students, Short trick for sum at 1:20:23 is take a = 1/3, b = 1/3 , and c = 1/3 then a + b+ c = 1 and 1/abc is 27 so minimum value of 1/abc is 27 😊

[@adityakumar-c5m1l]

sir we are unable to download the lecture notes please allow access for notes download

[@harshjangid5267]

1:30:30 sir , made a mistake in inequality sine .....

[@ayanbhar987]

Yesssss

[@vijaysathvik7858]

56:00 we could split (b+c)/a =b/a+c/a and similarly (c+a)/b=c/b+a/b And (a+b)/c =a/c+b/c and use AM>GM.

[@vinodchouhan7406]

sir apology in advance....you are a great teacher but... at time 1:31:25....the answer we found for a^2.b^3.c^4 is greater than equal to 2^19 x 3^3 and we wanted to to find max value of the same ..... i think this is not the max value according to this answer.....actually there are mistakes in some previous steps of this ans as you dint reversed the inequality

[@dilkiawazpoetry6598]

1:31:03 you didn't change the sign of inequality and also it is 2^1/9 not 2^9

[@cosmosapien5505]

yup broo @Dil ki awaz ( poetry) ...sir committed a small mistake there....agreeeeeeeeeee

[@evil8022]

Sir speaking right doing little mistake in writing as place of 1/9 he wrote 9 .Either everything is right even inequality

[@jakhegiboys3855]

​@@evil8022bro inequality bhi wrong ha a²b³c⁴/2²3³4⁴

[@GREEN-vo8js]

Nicee............

[@redarmy9548]

1:31:06 sir aapne inequality galat laga di hai

[@Sky_infy]

@50:40 Another way... Simplest numbers (you will be blown away 😂). Take three numbers a,b,c and use AM>HM, proceed further, you will have answer 9-3=6

[@topapexpredators4373]

Really great lecture. Helped me greatly in this concept... Thanks alot sir 😊

[@nanipanyu8653]

Pata nai ki ap comments prte ho ki nai, bs ye kena chata hun ki, sir ap kya mst teacher ho,itna acha parate hai wo bi free mai,aur gusse bi nahi krte, brna koi sir to nakre dikatae hae free mae parane ke💙💙

[@arunpareek7]

sir SEPT 2020 JEE KE Q ME MAINE A1,A2,A3 3 TERMS IN GP CONSIDER KER LE AND USSSE EEK HE ANSWER AA RAHA HAI D WALA OPTION KA SIR IS HE METHOD SE ME DOOSRA CASE KESE FIND KARU

[@mdzaid594]

same doubt

[@KhushalKotendra-pu8ok]

sir your voice😍

[@aryansingh9537]

1:59:40

[@riddhi1512]

12:58 video starts

[@thewillstar3941]

😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮😮

[@adiishri]

bestt

[@satpalkhandey]

Super 🥰

[@shubhamdivakar618]

Thnk U so much sir 🙏 ❤

[@sunilbharatindu4400]

Thanks sir

[@stutisingh2118]

Best lecture 👍

[@SaketK11]

NIMCET wala hai koi ?

[@funclub7129]

GM and HM

[@adityatg7452]

Is lecture me bacche ro diye 🤣🤣🤣🤣

[@11__11__]

Sir aap bahoot acche se padathe

[@JEE-oq1me]

sir you truly care about us, you value our time which will never come back and you help us make the most of it i think that's the best thing a teacher can do, not only do you just provide wonderful teaching you provide it concisely and in a simple manner so we can all understand it, just wanted to say thank you for that ❤. you and NV sir made math more enjoyable than it already is

[@VershaSri21]

Wtf is wrong with people in the comment section? He is literally teaching for free with the best quality available on yt. My message to people in comment section he doesn't owe you anything. He literally gave his best if you cant appreciate then get lost asap.

[@sujeet1662]

Sir ne toh Pura film hi dikha Diya bap re bap 🙏🙏🙏❤️❤️❤️

[@Y-THE-KING]

Sir please explain weighted means because you had left the topic

[@manishasinha6065]

Nice lecture😀😀😀😀😀😀😀😀😀😀😀😀😀 sir on inequality..........

[@rose7833]

Hw question By careful observation ek term 2n+1 dikh rhi hai jo 1+2+3+...+2n =2n(2n+1)/2 Se aaskti hai, so now we have a starting point and that's the series 1,2,3..,2n Now if we consider a GP=2power0+2power1+...+2power2n we might get our answer because Gm mei he terms multiply hongi and 1+2+...+2n create hoga, so let's find the AM and GM if this geometric sequence we made by mere observation, AM=(2power(2n+1)-1)/(2n+1) and GM =2power(n) Now AM>GM zindabaad and we get the desired result

[@user-xn1jo6oz3c]

Sir aap plus pr 1.5hr padhate ho, yt pr 2.30 hr 😂, thoda strange hai ¡¡

[@kalashtrivedi4327]

Thats what revolution is

[@therandomguy21]

Bhai wo plus h ye yha multiply chll rha h 🙂😂..srry for pj

[@strenzfactz-fi3pf]

True

[@raoparikshit7413]

😂😂😂

[@raoparikshit7413]

Systummm 😂😂

[@vishnubishnoi4621]

1:33:22 galat nhi hoga kya beause -1>-3 and 2>-1 but (-1)(2) is not > (-3)(-1) agr koi mera doubt solve kr skta h to comment karo

[@cosmosapien5505]

@Vishnu Bishnoi...bro when you multiply -1 with 2 and -3 with -1 the inequality sign changes ie. It will become 3 > -2; which is absolutely correct 💯 😀 WHENEVER YOU MULTIPLY OR DIVIDE WITH NEGATIVE NO.S YOU HAVE TO CHANGE THE INEQUALITY SIGN IT'S A RULE ! HOPE YOU GET IT 🙏🙏🙏

[@DipanshuChauhan14dp]

​@@cosmosapien5505 Ok then tell me how it is correct 2>-3, 2>-1, when I multiply both inequality and changes the sing of their resultant then tell me how it is justified 4

[@DipanshuChauhan14dp]

Yes you are correct

[@parvatigupta8106]

ax+by=1

[@Thewinnersaway]

Heart 💖💖💖 touching words by Mr. Sameer sir at 02:17:30

[@sumitsingh3874]

revision done jee 2022

[@debdutmondal642]

Thank You Everyone

[@vedanshi9421]

such a hardworking teacher!!!! Totally an inspiration!!! Thank you sir!!❤

[@AnmolSah27]

Sir please make a telegram group as Ashwani sir. 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@sarojpandey7906]

Thanku sir sir.aapki mai jitni tatif kro utni kam aur unacademy jee team ka

[@AbhishekYadav-ot7fo]

Sir in last question if we have to provee for integer greater than 1 why we included 1 in A. M.

[@prabhatkumarsahu9159]

Solution to hw Question Take the numbers 1,2,2^2,2^3,.......,2^(2n+1) Then, AM>=GM of the above numbers to get to the result

[@safiyakhan3826]

Excellent work

[@redarmy9548]

When I study mathematics by seeing your lectures I dont study.... I feel mathematics ❤

[@vedanshhi6616]

Bestie

[@abhishekmahajan4300]

a^2b^3c^4≤2^193^3 sir inequality galat laga rhe ho.

[@roshankumar1794]

Bhagwan kare ki apko duniya ki har ek khusi prapt ho mai ye wish karta hu apke liye bhagwan ji se .loving and enjoying your session .❤️❤️

[@mauryashiva060]

Sir inequilty kalat hai

[@Rohitkumar-ng4bt]

0.05

[@harshbharti1089]

In reciprocal first question when a^3 = 27 => a =+- 3. Please reply if anyone reading This

[@Sky_infy]

Pahle toh ye batao ki tumne ye padha kaha se ki a^3=27 ka solution ± 3 aata hai??? Kuchh bhi... Reverse chack bhi kiya Karo ki kya bole hai. Recheck kar phir bolo

[@harshdhanuka5712]

Bhai -3 ka cube -27 hota h...27 nhi

[@hasanattly4094]

Legend watch this live 😂😂😂

[@jeevi23]

143

[@kalashtrivedi4327]

Ultra legends watch in 2× and save time 😎🥸

[@crackjeeadvphysicalchemist7943]

Hidden Legend dekh tau Lete live but aap log priyanshi vishwakrama jiase logo ko backlog khatm krne ke tips de rhe th tau isiliye nhi dekha

[@crackjeeadvphysicalchemist7943]

@Definitely 😂😂

[@crackjeeadvphysicalchemist7943]

@@priyanshivishwakarma2592 sorry tau Jo chat me chal rha th usse shayad backlog nhi jee me totally rejected hone ka certificate milita hai Gajab bezzati hai

[@Amansingh-hy9gl]

Opppppppp

[@universe_710]

Thanks sir..❤ It was really the most useful session..❤ even after years....😊❤ Amazing explanation sir 😊❤ Thanks a lot sir...❤ Hare Krishna 💕😊

[@jee2524]

Fun-fact: This was the longest lecture of Sameer sir ever. Edit: Infact, the longest lecture of 3.O

[@sachiniitd26]

No longest lecture was of 12 hrs. Continuously last year bro. Edit: don't say but it was combined lecture bcz lecture is lecture ok ab badh lo

[@believelifestudy215]

Very very thanks sir 😊❤️ aapse study krne se mera school 🏫 me maths me 99 marks aaye hai a lot of thanks your help

[@AnuragSingh-hl9zz]

Revision done sir jii ❤️ ........I can't say that it's the fabulous lecture coz it wil being partiality with other lecturers......bcoz your all lecturers are above than faboulous it's unexplainable.....at last like every time .....sir maza agaya🤩❤️

[@ajvishwakarma1083]

Kon se class mein ho

[@AnuragSingh-hl9zz]

@@ajvishwakarma1083 11th....

[@pendyalasaisrichandanaasle3149]

Great Session Sir. Thank You.

[@ShakuntlaDevi-xg5qu]

Hats off to you...sir maja aa gya lecture dekh kr....sabhi questions bahut interesting hai

[@sachinpandey1297]

Sir u are real hero for me bcoz u r providing full length syllabus of mathematics in easy way 😀😀😀

[@rocketgenius9848]

Sir I was trying to solve from a problem but ultimately found that none of the types you taught worked out ...here is the question "If a,b,c,d are positive integers with a maximum sum of 63. Then find the maximum value of ab+bc+cd

[@rocketgenius9848]

Aur isko tab maine mera sir ko diya vo bola ki jo repeat honevale numbers he usko maximum value de or jo non repeat kar rahe he usko minimum de ....he told to take since b and c are repeating take either b=31 ,c=30 or b=30 ,c=31 and a =d=1 .and finally answer aagaya 991

[@rocketgenius9848]

Iske alava aur koi method he ya nahi sir plz aap classroom pe discuss kijiye 🙏

[@vedanshhi6616]

Op

[@dhruvdengada2266]

sir I am in 10th standard kaya hame 11th standard ke study chalu karne chahiye kya sir?

[@mayankgupta3377]

Aage bro jyada achha hoga 10 ka achhe se cover kro

[@sachiniitd26]

@sameer_iitr sir please more jpp plz need more practice sessions with you after all love you sir

[@rose7833]

Awesome lecture poori dekhi and ek bhi baar bore nahi hua

[@subhamsinghrajpoot7146]

Great lecture sir g thanks for teaching

[@jayeshb9323]

Op lecture sir ...maza aagaya, sare concepts clear hogaye

[@shreyeshmishra4692]

SORRY SIR GAAND KI SPELLING GALAT HAI

[@sanjitkondekar5290]

sanj_iitk

[@anirudhkumar3500]

I love you sir gi because I think you are my ❤️

[@pranavprabhu1600]

2:00:00