Introduction to Rate Laws - AP Chem Unit 5, Topic 2

[@user..98763]

helped me more in 11 mins more than my chem teacher ever did in a month🙏🙏

[@JeremyKrug]

Thanks for watching! Sometimes it helps to see a quick summary of something to put it all in perspective.

[@posatok273]

Actual lifesaver over here

[@JeremyKrug]

Glad I'm able to help!

[@craftseasy9521]

Thank you so much for your lifesaving videos!!

[@JeremyKrug]

You're very welcome. And thank you for watching!

[@bluepee8242]

Thank you for explaining this! we took notes on this in class but this explained it better and now I understand

[@JeremyKrug]

I'm glad my video helped you understand this concept. Thanks for watching!

[@aryanrao823]

god bless these videos they will save my AP chem grade 🙏

[@JeremyKrug]

I'm so glad my videos are helpful to you. And thanks so much for watching and commenting!

[@jackramirez9900]

For the rate law experiment at the start, what is the third column, the initial rate of what, the cio2 or the oh or the rate of appearance of one of the profucts

[@JeremyKrug]

Excellent question! We usually calculate the initial rate in terms of whatever substance has a coefficient of 1. This isn't always clear in most textbooks, but in this case it would be the rate of appearance of ClO3-, the rate of appearance of ClO2-, etc, or the rate of disappearance of hydroxide divided by 2, etc. This open-source textbook demonstrates this better than most that I've seen: chem.libretexts.org/Bookshelves/General_Chemistry/Chemistry_1e_(OpenSTAX)/12%3A_Kinetics/12.04%3A_Rate_Laws

[@FrenchFries879]

In the last question where you got 120 i got a 116.67 from my calculator, does that still count as correct as long as i show my steps and calculations ( revised them like 10 times 😭 ).

[@JeremyKrug]

Yes, my answer is 120 because the answer in this case should have only 2 significant figures.

[@MariamMohamed-h6k]

2:38 how did the rate inc by 9??

[@laurastevonkova3499]

bcs 0.248/0.00276= approx 9

[@selmabahy9027]

I love you Mr Krug

[@JeremyKrug]

Thanks!

[@corbinbiology]

the math is a little tricky in kinetics... ln, log, e. if only I was good at math, I get the concept but the math here is super tricky. do future unit's get harder with the math?

[@JeremyKrug]

The kinetics unit is about as ‘mathematical’ as it gets. Thanks for watching, and best wishes in your chemistry course!

[@HabbiLabbu]

what would you do if in all 3 experiments, the initial molarity of an element is never the same

[@keshkeeper14]

You divide rate laws

[@Christluvstt]

Mr Krug what would you do if they didn't keep one of the concentrations constant and changed both instead

[@JeremyKrug]

Personally I'd call it a poorly-written question. However, the question can still be solved, as long as one of the concentrations stays constant for at least one of the reactants at one point. For example, if there are two reactants, both are doubled, and the rate quadruples, this could mean two possible things: (1) one reactant is 2nd order while the other is 0th order, or (2) both reactants are 1st order. We'd need a little more information to pin down which is which. I hope this helps!

[@rodrigoduenas346]

Very very helpful video but how did you get 120, i've tried so many times but i keep getting like 116.66

[@JeremyKrug]

Thanks! And excellent question. I rounded off to 2 sig figs

[@rodrigoduenas346]

@@JeremyKrug ah i see, thank you

[@Bella-vc9fi]

for the last question how did we get s-1?

[@JeremyKrug]

Since the time in this problem is measured in seconds, we need to express our rate in 'change in concentration per second' and our rate constant k in s-1 so the units cancel out.

[@jana-fy1kb]

mr krug u need to make a patreon ill donate my life savings to you

[@JeremyKrug]

Thanks for the kind words! A Patreon might be in the works in the upcoming couple of months.

[@Playstation4444-u1i]

why is m cubed?

[@JeremyKrug]

On the right side of the equation we have (0.020 M) squared times (0.030 M) to the first power. M squared times M gets us M cubed. Thanks for watching!

[@jana-fy1kb]

my goattttttt

[@JeremyKrug]

Thank you!

[@aduggan8952]

If I defeat you in battle would I gain your knowledge of chemistry and pass the ap test

[@JeremyKrug]

lol I don't think so, but I'm always glad to share my knowledge and help you pass either way!

[@susoka6725]

thx i got 95 in chem

[@JeremyKrug]

Congratulations! You've got this!