CMOS Example [Inv(A+B*C)*C+D]

In this video I am going to solve a CMOS question.

[@ThecrazyGaer]

4 hours of lectured explained in like 14 minutes thanks dude :)

[@leonard-riccardowecke2773]

I believe that he forgot to mention why he left the bar over the nmos logic away. If the logical equation for the NMOS part gives TRUE then the output on the CMOS is LOW. He implemented that by leaving out the bar over the Nmos part(double negation of cmos logic). Therefor the equation for the Cmos part is implemented. In Mnemonics: Task: Cmos("given logic") != High Rule(that he didnt mentioned): NmosLogic=True => CmosOutPut=Low => IF Nmos = false THEN Cmos=True

[@siliconforestry4508]

Thank you

[@ashishgautam5989]

This is one of the best ways to learn something!

[@Adam-gp3ij]

Because of you I understood the entire chapter ! I appreciate your explanation

[@robertwitt1276]

seriously such an awesome two videos dude. I watched 3 lectures and was lost, now I am about to watch them again and understand what is going on. Thank you so so so so much keep up the good work

[@achrafelkhandouli]

thnx

[@nkululekostefaans1579]

This just summed the whole topic in less than 8 mins.. thank you.. SUBSCRIBED!

[@JoshTronicsECE]

This is more understandable and clear than what I've been taught. Thank you for your lecture. Keep it up!

[@mrohitsingha1615]

daam!!!!!! this guy makes everything easy

[@tamannachowdhury2306]

This really helped me alot. Thanks..

[@ajmaln2387]

litterly a week of being lost in lectures. All done in 2 vids... THank you!

[@vaishnavipalyam8628]

Thanks for the detailed explanation. It helped me a lot

[@TheFullcharge13]

Really good video, easy to follow. Great job

[@mindylee5023]

Thank you so much for posting this video. You save my life !!!

[@zerap8158]

Your video really helped me! 🧡 (It's much better than what my teacher taught 😂

[@thetruthabr9879]

how do u know whether or not the inverted D in the PUN goes right above the PDN under the circuit you drew or above it right under +Vdd?

[@hemanthar4974]

Very well explained 🔥

[@mervatarafat2578]

You are the best keep omving on♥️♥️♥️

[@loki-qd4zp]

U save my whole interview session

[@zorkan]

Excellent

[@rohantyagi5279]

Totally confused here isn’t n-mos transistor a pull up network as it pulls the signal from ground?

[@jamesblooom8670]

amazing job mate

[@javariababar3616]

Best video great 🙌

[@markharrisllb]

Brilliant, thank you.

[@shaikrehman3236]

Your video is very helpful thank you sir

[@phamhuutri1996]

what if the function is not inverted? let say just like this [(A+B*C)*C+D]. how do i slove this ?

[@javismc7099]

Thanks for this helpful video

[@bloe2603]

Hello sir, is it okay if i contact you personally regardings the designs of the CMOS circuits? Need help

[@Play4fuNNNNNnn]

Can you make video on how to design a 3-times NOR-Gatter and a 2 Times AND-Gatter by using NMOS technology? i d be really thankfully.

[@rohittanwar1946]

thanks you so much 😍😍😍😍 for explaing this topic very easly 😊😊😊

[@cubeyd27]

Thank you bro 3 hours like 7 minutes 👏👏

[@Parth.Deshpande]

Awesome bro , thanks

[@manasbohat6883]

can we simplify the function by boolean algebra and then implement?

[@katlegomotaung3955]

fvckin smart!! This helped me a lot!!

[@MS-qh3iz]

Thank you!!

[@mohamedhossam3645]

Thank you !

[@mengxili3731]

First thankyou so much for making this video. It helps a lot. Then I have a question in when you drawing the D-PMOS into the pull up network. Does it matter if I draw D bellow where it will not be connected Vdd later but with output. Actually those two different position where D can be placed later will influenced the stick diagram. So if the position of D does a matter here and also in stick diagram, then do you have any tip for deciding the position of D_

[@bommenavishwateja7468]

its a series configuration doenst matter where you place it

[@joelrcc]

@@bommenavishwateja7468 no, error. when is PULL, for example AB, in down position is A, when is DOWN, in down position is B

[@bommenavishwateja7468]

@@joelrcc I don't think so buddy

[@joelrcc]

@@bommenavishwateja7468 Well. At end, is not neccesary but by standar is in this way

[@ali99_82]

Thank you ❤️

[@samiya877]

its really helpful.thank u

[@koray_kara]

Thank you very much sir.

[@habibunnabeea.rahman7024]

Thanks a LOT!!!

[@domulko44]

thanks a lot :) really useful video

[@jinggenikannimane]

you are the legend

[@amkel1661]

thank you sir!

[@AhmedAshraf-ed9kq]

that is amazing thanks alot.

[@AhmadTalkss]

Nice got the idea

[@eunicechiu8798]

in my understanding, did u just ignore the inv(the bar) over the logic equation? what is the difference between the layout of [Inv(A+B*C)*C+D] and (A+B*C)*C+D ? Anyway, steps are clear. Thanks!

[@tarcisiojosedearaujopereir664]

Eunice Chiu same question, but as i remember the cmos always inv normally, u can think in the basics inv nand and nor

[@moustafahammoud4129]

check morgan theorem

[@leonard-riccardowecke2773]

I believe that he just forgot to mention why he left the bar over the nmos logic away. If the logical equation for the NMOS part gives TRUE then the output on the CMOS is LOW. He implemented that by leaving out the bar over the Nmos part(double negation of cmos logic). Therefor the equation for the Cmos part is implemented. In Mnemonics: Task: Cmos("given logic") != High Rule(that he didnt mentioned): NmosLogic=True => CmosOutPut=Low => IF Nmos = false THEN Cmos=True

[@usrakhan975]

HE ADDED AN INVERTER WHILE DESIGNING XOR and XNOR BUT Y DID HE NOT ADD AN INVERTER HERE . THIS EQUATION HAS ALSO GOT WHOLE BAR

[@arkanjo7509]

excelente

[@ananthukrishnan9236]

extremely useful

[@luminarin]

thank you!!!

[@Hamza-dx5hz]

thank you sir

[@happilyevernever4289]

Is this the 2 step implementation of cmos or single step?

[@neamohamed5258]

good maths equations

[@aidensmith1110]

Hey. You;re a good boy.

[@wahidhamidy6886]

you are legend

[@absolute___zero]

so.... the pull up and pull down networks are just joined together by wires and that's it ???? Are you sure this joined circuit can't be simplified any further?

[@wahidhamidy6886]

thanks

[@stanleerubio]

thanks bro :)

[@abidr9116]

❤❤❤

[@lakshyarana67]

what about that bar !!!!

[@ChimotanaJugadora]

Thanks for the video! very helpful !

[@YoO161]

how isnt your pmos wrong? shouldnt it be (a*(b+c)+c)*d? so the same you got, without the negated variables? i cant see how your pmos is right, as you create the pmos by taking your function f(a,b,c,d) and turn it to f(!a,!b,!c,!d).

[@zombiedude347]

When Negating, AND/OR also switch, in addition to the inputs being negated.

[@govinddeshmukh4571]

Why do is taken upper

[@josealmanza6840]

Could you do Y=((A'+B)*C')+D'

[@axlearyakia]

I fucking love you so much

[@ayamgoreng1150]

I wanna know the truth table as well🤧

[@SANJAY-ve9ub]

Can anyone explain how this entire process happens in real time?

[@zombiedude347]

The example logic should be simplified as (A | B & C) & C is equivalent to (A | B) & C.

[@hihat4347]

X1. 25 speed

[@caesarxi1303]

Thank you so much. I finally got it. Actually, PMOS performs the operation. NMOS configuration is only for activating GROUND. PMOS does the job by negating the expression. BUT when the expression is true, its negation is false, and then PMOS configuration needs to activate GROUND, so it wont deliver VDD to the output. If the expression is false, PMOS output is true, and it needs to deactivate the GROUND. To activate/deactivate the ground, we need the OPPOSITE configuration on NMOS, which is responsible for delivering the GROUND signal. To activate GROUND, NMOS must evaluate the expression as true. To deactivate GROUND, NMOS must evaluate the expression as false. I did this with the NAND port, so I could visualize it better, since it has an easier configuration. 2 PMOS in paralel = NAND 2 PMOS in series = NOR 2 NMOS in paralel = OR 2 NMOS in series = AND NAND needs an AND to activate/deactivate GROUND.

[@caesarxi1303]

The input signal for PMOS comes from above. The input signal for NMOS comes from below.

[@BrutalGames2013]

In my opinion the title should be [Inv((A+B*C)*C+D)] rather [Inv(A+B*C)*C+D], since the complete term is inverted

[@desifishOriginal]

Thanks a lot!