Finding the Electron Concentration in a Semiconductor

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Jordan Louis Edmunds

Jordan Louis Edmunds

Күн бұрын

Пікірлер: 39
@emmanuelnyamekeh7313
@emmanuelnyamekeh7313 5 жыл бұрын
Your videos are very nice I've never seen anyone who breaks down solid states like you do kudos my boss
@ninjanothing8343
@ninjanothing8343 4 жыл бұрын
I understood more from these videos than from my whole semester class
@markpascual100
@markpascual100 4 жыл бұрын
:o could it be THE strawberryhacker?
@xturtleparadex
@xturtleparadex 4 жыл бұрын
Bless your soul. Sincerely, A current UCI EECS 170A student lol.
@JordanEdmundsEECS
@JordanEdmundsEECS 4 жыл бұрын
:DDD A fellow anteater! Good luck on finals (if you aren't already done with them).
@RaphiTheOne
@RaphiTheOne 4 жыл бұрын
Those short video are far more understandable than the book that was recommended for my exam. They are very much appreciated and will probably watch them all if some in accelerated.
@neydora2912
@neydora2912 4 жыл бұрын
I am just studying for my defence and wanted to repeat all that stuff again since my university time is now more than 4 years ago - your videos are just amazing! Watching the Semiconductor Physics list :) Thanks a lot!
@BillDemos
@BillDemos Жыл бұрын
1:41 The hand text: "We've Anally done it!". Wow. That must have hurt ahahahahah.... Besides the lough, man already subscribed, TOP NOTCH CONTENT
@陈强-m9s
@陈强-m9s 2 жыл бұрын
Thanks for your video. It's helpful for me to organize my knowledge related to semiconductors. Let me point out a mistake in this video: At 6:15 f(E) should be approximated by exp(-(E-E_F)/kT) instead of exp((E-E_F)/kT)
@kaylo1680
@kaylo1680 2 жыл бұрын
I'm currently being thrust into a course in Semiconductor physics at my university now (to which I and my peers lack some of the required previous knowledge for, because for some reason our program hasn't sorted that blunder out yet) and your series is absolutely saving my ass.
@NicolasSchmidMusic
@NicolasSchmidMusic 3 жыл бұрын
You videos are good and you probably use the same book as in my course (semiconductor physics and devices?), so all the playlist is exactly what I have to learn. Thanks!
@shubhamtanwar5341
@shubhamtanwar5341 4 жыл бұрын
These are some high quality explanation skills! Kudos to you, Sir. I will donate as soon as I start step out of student life
@JordanEdmundsEECS
@JordanEdmundsEECS 4 жыл бұрын
I'll hold you to that :)p Good luck with your studies!
@nostradamus9132
@nostradamus9132 Жыл бұрын
​@@JordanEdmundsEECSin the video you use the fermi energy in the fermi dirac statistic. But I think this is wrong, you should use the chemical potential. They are only the same at 0 K. Can you comment on that so that I know if this assumption of me is correct?
@xandersafrunek2151
@xandersafrunek2151 3 жыл бұрын
In your previous video you define DOS as (4*pi*(2m)^(3/2)/h^3)*sqrt(E), but in this video use (4*pi*(m)^(3/2)/h^3)*sqrt(E). I think maybe this is just a typo? Also, I think the final equation should have an e^-(E-E_F)/(k*T), not e^+(E-E_F)/(k*T)
@dannchan00
@dannchan00 5 жыл бұрын
Hi Jordan, I'm very grateful that u made such videos and for people like me that study biology and has no basis in physic, this is a really good study material for me. Keep the good effort going! However, I found that the formula of DOS , g(E) function 6:07 in this video is not similar to the DOS part 2 video 7:52, ( 8pi m* and the other one is only 4pi m* regardless of the dE)? Why is that so? I'm sorry if I ask a stupid question because my differentiation and integration knowledge is limited and need to be sharpened in the future.
@sazzadhossain3014
@sazzadhossain3014 6 жыл бұрын
please include this video in the playlist
@JordanEdmundsEECS
@JordanEdmundsEECS 6 жыл бұрын
Done! Thanks for letting me know it wasn't in there.
@suniljoshi5315
@suniljoshi5315 Ай бұрын
Sir, how is g(E) zero between Ev and Ec? Isn't the fermi level between them, which would mean the probability of occupancy is 0.5??
@okropiri142
@okropiri142 3 жыл бұрын
Where is density of states g(E) derivation? Should it not be before this video in this playlist? @Jordan Edmunds
@colosolizer2184
@colosolizer2184 2 жыл бұрын
What is the value of the k constant
@xephyr417
@xephyr417 5 жыл бұрын
Great video again! Question, is the density of states function we developed under the assumption of the 3-D infinite potential well still accurate? It is what gave us the n*pi/L that we used to derive that equation. I had assumed that we would need to recalculate that function using the kronig-penney model, but we didn't. Doesn't the spacing in k-space technically change? Or are we assuming that (again) for relatively small variations around k=0 the infinite well model is accurate enough as the KP E-K diagram is approximated by the parabola of the infinite well model?
@JordanEdmundsEECS
@JordanEdmundsEECS 5 жыл бұрын
So the density of states function does indeed originate from the infinite potential well model. The parabolic model is actually the model for a free electron, not that of a quantum well, and that is what allows us to treat the electron dynamics semi-classically. The spacing in k-space will change, and I actually don’t currently know qualitatively how it will change. However, I *believe* that you can use Bloch’s theorem to separate out the effects of the atoms and the effect of the larger quantum well structure and my guess is that it does change it, but doesn’t much change the overall result. Your question goes even deeper than that, though, because I think what you are really asking is *how do we know when to use which physical model*? From what I have learned so far, the answer seems to be this: the simplest model that will give the required accuracy. My guess is that this model happens to do that, but if you figure out exactly why, let me know. I’ll see if I can figure it out.
@nellvincervantes6233
@nellvincervantes6233 3 жыл бұрын
Question sir. Why m* = 2m ? How to derive this equation? From your vid about density of state, g(E) = 4(pi)(2m)^(3/2)(E)^(1/2)/h^3 Then in here, g(E) = 4(pi)(m*)^(3/2)(E-Ec)^(1/2)/h^3 So m* = 2m
@Biologiehilfe
@Biologiehilfe 4 жыл бұрын
Hello there, why exactly did you set f(E) = exp((E-Ef)/kT)? I get the fact, that you approximated f(E) for E>Ef as exp(-(E-Ef)/kT) but why did you then put exp((E-Ef)/kT) as f(E) into n? Great videos by the way :)
@NinjaTommyd
@NinjaTommyd 4 жыл бұрын
Think he just forgot the minus.
@saidteacher3331
@saidteacher3331 3 жыл бұрын
First thankyou so much! . Then, can you please tell more what the effective mass is? oir professor just dropt it from the skies and siad (dont worry u find it in tables) . Thanks!!
@JordanEdmundsEECS
@JordanEdmundsEECS 3 жыл бұрын
Yeah! I actually have a whole video on the subject: kzbin.info/www/bejne/p569Xn2OZr-fpNk
@UsmanKhan-nb4pd
@UsmanKhan-nb4pd 6 жыл бұрын
According to my knowledge, the derivation of f(E), utilized in this lecture, has not been discussed in previous. If it is true and suitable, please include in the playlist.
@JordanEdmundsEECS
@JordanEdmundsEECS 6 жыл бұрын
You are correct, I haven't actually made that video yet, I will add it to this playlist when I make it :)
@codewithlax
@codewithlax 6 жыл бұрын
The DOS funtion value is missing 2me as you have written only me
@sourabhpatil2965
@sourabhpatil2965 5 жыл бұрын
I'm wondering how can Fermi function give a finite probability for an electron to exist in forbidden energy area?
@JordanEdmundsEECS
@JordanEdmundsEECS 5 жыл бұрын
That’s an excellent question, I think the best way to interpret the Fermi function is the *percentage of existing states that will be occupied at that energy*. So your fermi function might be 0.3 (30% of states occupied) within the forbidden region, but the number of states you have is 0. This will be given by the density of states function. 30% of 0 is 0, so you still don’t have any occupied states.
@mitchellmckay5448
@mitchellmckay5448 4 жыл бұрын
@@JordanEdmundsEECS Oh I have been waiting for this answer
@saidteacher3331
@saidteacher3331 3 жыл бұрын
Also our professor use a very weird strategy , he calculated the reciprocal lattice volume and devised on it...i find your method much more forward and logical
@JordanEdmundsEECS
@JordanEdmundsEECS 3 жыл бұрын
Yup that becomes necessary to derive the "density of states" (which I have a couple of videos on), but it's a terrible starting point xD
@xAmiSarahx
@xAmiSarahx 4 жыл бұрын
thank you.......
@hchen854
@hchen854 4 жыл бұрын
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