Joule Thomson Effect | Inversion Temperature | Explained | J-T Coefficient | Lecture 13

Topic: Joule Thomson effect | Joule Kelvin Effect | Inversion Temprature | Joule Thomson Coefficient | Thermodynamics
A complete explanation for the Joule Thomson effect is provided. Joule Thomson effect is an isenthalpic process, this concept is proven. You will find the concept of inversion temperature and Joule Thomson Coefficient (J-T Coefficient). This video is a part of a video lecture series on Thermodynamics. This is mainly important for BSc physics #BScPhysic, B.Tech Physics.
This video is a part of a video lecture series on Thermodynamics.
You are learning with Dr. Shaw on #PhysicsLearning
Lecture 1: Helmholtz Free Energy
• Helmholtz Free Energy ...
Lecture 2: Gibbs Free Energy
• Gibbs Free Energy | Th...
Lecture 3: Internal Energy and Enthalpy
• Internal Energy | Enth...
Lecture 4: Maxwell's Relations in thermodynamic
• Maxwell's Relations fo...
Lecture 5: TdS equations in thermodynamic
• TdS equations in therm...
Lecture 6: Cp-Cv relationship
• Cp-Cv relations in the...
Lecture 7: Energy equations in thermodynamic
• Energy Equations in th...
Lecture 8: Joule experiment, free adiabatic expansion of perfect gas, Adiabatic heating, and cooling.
• Joule experiment | Fre...
Lecture 9: Magnetic Work done and Dooling by adiabatic demagnetization
• Cooling by adiabatic D...
Lecture 10: Derivation of Clausius -Clapeyron using Maxwell's Relation
• Clausius Clapeyron eq...
Lecture 11: First order phase transition
• First order phase tran...
Lecture 12: Second Order Phase Transition
• second order phase tra...
Link for the important video lecture series
Lecture on the Heat Transfer: conduction of heat
• Heat Transfer: Conduct...
Lecture on Wave motion: Vibration of String
• Wave Motion: Vibration...
Lecture on Wave Optics: Diffraction of Light
• Diffraction of Light

[@AnjuNarwal-dx2qm]

Its really helpful for us ..... each and every thing explained in a very good manner .... keep it up

[@PhysicsLearningwithDrShaw]

Glad to hear that you find it useful.

[@alokkar1682]

Best video among all available on the topic in you tube

[@therewasanattempt1961]

Explained this way better than my professor, thank you

[@PhysicsLearningwithDrShaw]

Thank you and welcome 🙂

[@Dipenderyadav981]

Crystal clear ❤️

[@lipshadhurua4584]

Thank you so very much sir 😊😊😊it's very helpful fr me .

[@rahulnandi9641]

Great explanation ❤

[@jaiprakashshaw6535]

It was very helpful. Every points are explained properly. Thank you Sir.

[@PhysicsLearningwithDrShaw]

Glad to hear that

[@fathimafarsana.n6772]

u made me this topic very easier.wonderful explanation sir

[@PhysicsLearningwithDrShaw]

Glad to hear that it was helpful for you. Thank you

[@muay3493]

Thank you so much for this helpful video.

[@PhysicsLearningwithDrShaw]

Glad to hear that it was helpful. 🙂

[@ramankumar8364]

Best understanding sir and amazing discuss...thanks my BJ sir too such discuss.

[@PhysicsLearningwithDrShaw]

Thank you

[@aryarowan2283]

thank you so much........literally watching this a day before exam. The explanation is very clear.

[@PhysicsLearningwithDrShaw]

You are welcome.

[@charulatabhattacharya5098]

Same

[@methe_crazy_queen]

Super sir it was very helpful.... And superb teaching...

[@PhysicsLearningwithDrShaw]

Thanks and welcome

[@sumiasharminjuthi5598]

It will be helpful to me. Clearly(in perception of speaking too) explained the topic.Thanks a lot..

[@PhysicsLearningwithDrShaw]

Glad to know that it was helpful 😊

[@d.m.fuadhasan2059]

Wow juthi here😍

[@sumiasharminjuthi5598]

@@d.m.fuadhasan2059 arre...😍

[@ohyeah-s7i]

I have a question. We define thermal expansion coefficient as alpha = delV/delT over V, so we can replace delV/delT as alpha times V. Then, according to the last equation you'd derived, for mu to be positive(mu>0), T should be "greater" than 1 over alpha. But, here's inconsistency with your statement at the beginning of this lecture. You said, when initial temperature is "smaller" than maximum inversion temperature, cooling effects accure, which is equivalent to the statment mu >0. I want to know why this kind of inconsistency arise.

[@tanujamarapureddy3891]

It's really useful .. U explained it very clearly.. Thank you nd we want more videos on bsc chemistry

[@PhysicsLearningwithDrShaw]

Thank you

[@sureshmohan4352]

Wow 🤩🤩superb explanation

[@PhysicsLearningwithDrShaw]

Thank you

[@SanjuYadav-pc4ks]

Very good method of learning 🙏🙏🙏sir

[@PhysicsLearningwithDrShaw]

Thanks and welcome

[@17samir]

You are so good in my new clg lecture who is read like ramayan

[@PhysicsLearningwithDrShaw]

Thank you

[@sandeeppatidar1106]

Best explanation

[@PhysicsLearningwithDrShaw]

Glad you think so!

[@sandeepchauhan6836]

Greatly explained

[@PhysicsLearningwithDrShaw]

Thank you

[@anandapatmanabhansu]

Thankyou sir

[@PhysicsLearningwithDrShaw]

Welcome🙂

[@prashanthshetty8857]

It was nice explanation sir

[@PhysicsLearningwithDrShaw]

Glad to hear this. Thank you

[@chetnameena1065]

Wonderful explaination

[@PhysicsLearningwithDrShaw]

Thank you

[@YogeshSingh-pv5xr]

Very good explanation sir 🙌

[@PhysicsLearningwithDrShaw]

Thank you

[@dibakarpal2020]

Very helpful lecture sir🙏

[@PhysicsLearningwithDrShaw]

Glad to hear that it was helpful.

[@tamannarmaurya]

Thank u

[@PhysicsLearningwithDrShaw]

Welcome

[@AdhyayanBot-ej7kh]

Sir, do you put the symbol according to the reference of surrounding? If yes then it is correct i.e work done on the system is-ve and work done by the system us +ve

[@suryamtk4305]

Could you please take more videos on BSc chemistry, and physics. It would be very helpful. Especially the chapters quantum mechanics and waves

[@PhysicsLearningwithDrShaw]

I will try. Thank you

[@aneesurrehman9474]

Brother! the pressure remains nearly constant here. Only temperature and volume changes.

[@tahreemmukhtar7407]

too much lecture your's lecture is very helpful for me thanks

[@PhysicsLearningwithDrShaw]

You are most welcome

[@ManojKumar-cj7oj]

Thanks

[@PhysicsLearningwithDrShaw]

You are welcome.

[@duafatima2095]

Nice sir

[@PhysicsLearningwithDrShaw]

Thanks and welcome

[@AnjuNarwal-dx2qm]

Sir ... can u make a video on joule thomson coefficient and van der Waals Equation of state ... 🙄🙄🥺

[@PhysicsLearningwithDrShaw]

I have already uploaded video JT coefficient and it's calculation for ideal and van der wall gases. kzbin.info/www/bejne/moS6eoKgd7d0ecU

[@ayeshawaseem6402]

Can u kindly remove adds isn’t it necessary to apply a lot of adds🙏

[@nandanak7661]

Work done by the system is -ve right?

[@PhysicsLearningwithDrShaw]

Work done by the systrm is positive whereas work done upon the system is negetive. Sometimes, chemistry people use otherwise. The main things is if system will do some work it will loose energy. How you interpreting this results will decide your sign convension. But it wont change anything in the final step because everything is related to first law of thermodynamics.

[@nandanak7661]

@@PhysicsLearningwithDrShaw ok thanku

[@Fairy733]

Work done by the system is negative

[@IshanYaar]

Work done by system is negative not positive.

[@PhysicsLearningwithDrShaw]

Sign convention are different in the chemistry and physics. In physics, work done by system is positive.

[@Adidthya]

Dear hopeless tutor, P1V1 here is not (-)..It should be positive as the system underwent compression.Your P2V2 should be (-) as it underwent expansion.

[@Adidthya]

Dear hopeless tutor, P1V1 here is not (-)..It should be positive as the system underwent compression.Your P2V2 should be (-) as it underwent expansion.