Correction at 11:38 The two prime Implicants which I have mentioned ( m1, m5 and m9, m13) are in fact Implicants. And instead of that there will be a prime implicant, which consists of all 4 minterms. ( m1, m5, m9 and m13). That prime implicant is non-essential prime implicant and that's why it was not included in the final minimal solution.
@valerian2768 Жыл бұрын
Thank you sir, this is really helpful.
@_Mohammad_Muzamil_Bhat8 ай бұрын
after searching all day on youtube and google,i found this video as crystal clear,easy and more accurate relative to others.best for understanding i,pi,epi.(thank you).
@SpringySpring048 ай бұрын
I'm very thankful for your channel and explanations, but it's honestly sad that I have to resort to this since my professor doesn't bother to explain this concept very well, leaving most of us students including myself lost and confused. This video is a lifesaver.
@edgarleiva21445 ай бұрын
Same for me bro
@tsci5628 ай бұрын
Amazing explaination saved my grade!!! My TA struggled to explain the concept. You are the best!
@Maybemiles_C2 жыл бұрын
quality of animation and explanation is too good sir. Thank you sir.
@muhammad878510 ай бұрын
Thanks a lot brother from BD, the way you describe it, take all my confusion although my exam was bad but your video is a gem that I missed, I am just a bit late in here
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@argonicapple5 ай бұрын
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@paranormaledits95262 жыл бұрын
14:36, how can this be non-essential prime implicant if two of it's minterms are not included in any other group? Isn't it also an Essential prime implicant?
@ALLABOUTELECTRONICS2 жыл бұрын
The other prime implicant m12, m13, m14, m15 is not shown here. But the remaining two minterms are covered by that. That's why it is non-essential prime implicant. I hope, it will clear your doubt.
@luca_xvi6057 Жыл бұрын
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@shreyanshgangwar7797 Жыл бұрын
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@parthpagar66443 ай бұрын
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@AfhamAdian4 ай бұрын
best on the topic
@VenujanSritharАй бұрын
14:24 , (m12,m13,m8,m9) or (m12,m13,m15,m14) should be EPI. isn't it ? otherwise we cant get minimalized prime implicant ryt ? what is the reason for that ?
@TalaashDotCom Жыл бұрын
Thank you for such a great content
@bruhbruh4137 Жыл бұрын
very nicely explained ,thank you sir
@anch952 жыл бұрын
14:32 But why would be call that Non-Essential PI? Once we remove one of the 2 Non-Essential, isn't the other one becoming Essential?
@ALLABOUTELECTRONICS2 жыл бұрын
The condition for calling any prime implicant as the essential prime implicant is that, it should have atleast one minterm, which is not being covered by any other prime implicant. And while selecting that, you should consider all the prime implicants of the function. In this case, that condition is satisfied only for two prime implicants. We just can't ignore any of the prime implicant of the given function while making the decision. I hope, it will clear your doubt.
@devenderdagar2987 Жыл бұрын
I think, You are correct, request if anyone can explain if this statement is wrong.
@huiwencheng458511 ай бұрын
I think it IS also prime implicant in that boolen function. Same as your viewpoint
@boyar30335 ай бұрын
Thank you for doing a video lile this !
@HB-Tube. Жыл бұрын
best explanation thanks
@jamesheo106 Жыл бұрын
Thank you so much. This helped a lot.
@mayurshah91312 жыл бұрын
Just superb
@Maha-ro2uz2 жыл бұрын
Tq very much Umake my learning Easy👍
@sutopasarkar497 Жыл бұрын
In 5:26, why we take m9&m13 as prime implicant? It is not clear to me. Sir please reply
@ayushman19407 ай бұрын
because m9 cannot be covered if you dont take it as prime implicant.
@umutguloglu67482 жыл бұрын
Sir, at 11:39, does not m1,m5,m9,m13 form a prime implicant instead of two different implicants (m1,m5, and m9,m13)? Thank you.
@ALLABOUTELECTRONICS2 жыл бұрын
Yes, you are absolutely right !! m1, m5,m9, m13 will make a prime implicant. It's a mistake from my side. Thanks for pointing it out 👍🏻
@abhijitcreation6 ай бұрын
Nice explanation ❤
@poojashah61832 жыл бұрын
Beat explanation 👌🏻👌🏻👍🏻
@Yumiiiii-n7k7 ай бұрын
14:32 is it possible to make an essential prime implicant group of two with (m12 and m13) instead of making the non essential group of four with (m12,m13,m8 and m9) ? If it’s not then why so ?
@ALLABOUTELECTRONICS7 ай бұрын
m12 and m13 is not even prime implicant. Because it is being covered by other two groups. (m12, m13, m14, m15) and (m12, m13, m8 and m9)
@kaifulimaan3021 Жыл бұрын
nice explanation thanks
@张凯德8 ай бұрын
Thank you sir!
@itsaj2109 Жыл бұрын
فدوة لقلبك ♥
@KalaniChen5 ай бұрын
thank you so much
@MycodingsАй бұрын
so how many total prime implicants and essential prime implicants in last example.?? 14:36
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@electronicslecturesbygulsh37992 жыл бұрын
sir in 11.35 u r saying 2 more PI Which is wrong because it's 1 "vertical Quad" ...it can't violate priority of higher order group in PI formation
@ALLABOUTELECTRONICS2 жыл бұрын
Yes, you are right. I have already mentioned that in the pinned comment.
@ajiteshkumar58412 жыл бұрын
Sir if we group (m12 , m13 , m15 , m14) and (m12 , m13 , m8 , m9) simultaneously then both will be Non-Esp but if we group only one at a time then both group will be Esp . Suppose we have grouped only (m12 , m13 , m15 , m14) and not (m12 , m13 , m8 , m9) group then m12 and m13 are not covered by any other prime implicant , therefore (m12 , m13 , m15 , m14) group should be Esp. I hope you understood what i want to say.
@amitarc7530 Жыл бұрын
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@AnonymousUser17059 Жыл бұрын
at 14:21 why the group of [m12, m13, m15, m14] or [m12, m13, m8, m9] is not a essential prime implicant? the minterms m12 and m13 are grouped once either in the group.
@ALLABOUTELECTRONICS Жыл бұрын
If you consider [ m12, m14, m13, m15] then all the minterms are covered by other prime implicants. m12,m13 is also covered by ( m12, m13, m8 , m9)
@HelloWorld40408 Жыл бұрын
Thank you sir
@fareedabegamnadaf8557 Жыл бұрын
Thanku sir ....❤️🙌
@dhiabenaicha Жыл бұрын
sir when you add non-epi to the equation does they prevent glitchs ?
@joanitarzzalwango6392 Жыл бұрын
Thank you
@Kmoney200210 ай бұрын
good video
@structgameplay50232 жыл бұрын
thank you sir
@tlsan8282 Жыл бұрын
Sir. At 10:07 why isnt m0 an essential prime implicant?
@ALLABOUTELECTRONICS Жыл бұрын
It is a part of an essential prime implication. If you closely observe, (m0, m2, m8, m10) forms an essential prime implication. And it is also shown in the image.
@tlsan8282 Жыл бұрын
Understood sir thank you 😊
@tlsan8282 Жыл бұрын
And thank you for the reply.most educational youtubers wont respond when you ask a question
@dhanushh21715 ай бұрын
in the video at 5.34 only 3 prime implicants only come group 2 is irredundant actually
@ALLABOUTELECTRONICS5 ай бұрын
The second group shown in yellow color is not redundant one. It will be required to cover the minterm m9 and m12.
@iibtech86932 жыл бұрын
in 14:35 why m12,m13,m8,m9 doesn 't essential prime implicant ?.thank you
@ALLABOUTELECTRONICS2 жыл бұрын
Because, minterms m12, and m13 are also covered by the other prime implicant m12, m13, m14 and m15. Thats why it is non essential prime implicant. I hope, it will clear your doubt.
@AnonymousUser17059 Жыл бұрын
@@ALLABOUTELECTRONICS But you said either of these m12, m13, m8, m9 or m12, m13, m14, m15 are non essential prime implicant.
@aziza7806 Жыл бұрын
😢 What happens when all the groups are separate ie doesn’t overlap with any other implicants eg: minterms(0,2,4,5,10,11,13,15) . Will essential PI will be al the PI or thre is 0 Essential PI?
@ALLABOUTELECTRONICS Жыл бұрын
In that case, all those non-overlapping groups are essential prime implicant. It means, you need to include them for minimizing the Boolean function.
@electronicslecturesbygulsh37992 жыл бұрын
non essential PI and SELECTIVE PI are same and the definition is those PIs which r neither EPI nor RPI is SPI
@pemmakavijaykumarreddy58522 жыл бұрын
at 10.22 why don t we comsider 0 position as a esp
@ALLABOUTELECTRONICS2 жыл бұрын
Because here the minimization is being done for the Boolean expression which is in SOP form (Sum of Product Form). For POS form (Product of Sum) form of expression, the 0s in the K-map are combined. I hope, it will clear your doubt.
@ALLABOUTELECTRONICS2 жыл бұрын
For more info, also check this example. kzbin.info/www/bejne/kJLcoIiKnpenqaM
@xxhun12 Жыл бұрын
sir ,at 11:13 isn't blue circle non essential since all the 1's are covered other prime implicants as well?
@ALLABOUTELECTRONICS Жыл бұрын
Yes, you are right. It is being covered by other other prime implicants. So, it is non essential. But to cover all minterms, it needs to be included during minimization.
@muzamilsoomro61847 ай бұрын
at 5:27 why we use the red one as a prirme implicant bcz all the ones that are covered before so whats the reason of making the red one..
@ALLABOUTELECTRONICS7 ай бұрын
It is prime implicant. But it’s not essential prime implicant. Because all the 1s are getting covered by other prime implicants. It is prime implicant because all the 1s are not getting covered by other group at a same time. I hope it will clear your doubt. You may watch the video again to understand the concept.
@nadeemasif2406 Жыл бұрын
Sir what is non prime implicant in kmap
@hiramahiram-d5i Жыл бұрын
i don't understand why m0 is not ESPI. Only one prime implicant cover just like m10
@ALLABOUTELECTRONICS Жыл бұрын
Would you please mention where you are referring to in the video ??
@hiramahiram-d5i Жыл бұрын
@@ALLABOUTELECTRONICS it's at 10:07
@ALLABOUTELECTRONICS Жыл бұрын
@@hiramahiram-d5i m0 is a part of the prime implicant, (m0, m2, m8, m10) And as you can see, it is already ESPI.
@linterrupt2 жыл бұрын
what program do you use for drawings?
@RahulKumar-fk7ln Жыл бұрын
At 8:48 how green box is ESP
@ALLABOUTELECTRONICS Жыл бұрын
The minterm m9 is not being covered by any other prime implicit. That’s why it satisfy the condition of ESP.