Keith Norman's Solution to 196 - Integrated Circuit

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Lectures by Walter Lewin. They will make you ♥ Physics.

Ай бұрын

There are only 4 correct solutions

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@MkA8438 Ай бұрын

Greetings from Poland. I really enjoy watching your experiences. Your lectures open minds thanks to their examples. I wish you a lot of health and perseverance.

@ihavefish0 Ай бұрын

Dr. Lewin, I visited MIT a few days ago and found 26-100: the best classroom ever!

@abulkhayer4898 Ай бұрын

Good to see you sir.....I will be in class 9th sir...day after tomorrow..till now in 8th...can you please tell me how to understand Electrochemistry......

@gamerboy7820 Ай бұрын

Dude specialised in physic

@i_am_mistic6688 Ай бұрын

Electrochemistry is the study of electricity and how it relates to chemical reactions. hope this helps🐺

@jessefranckowiak Ай бұрын

Great channel, Dr. Lewin!

@user-gz9kq8fx3d Ай бұрын

Always kind of love for u sir.. ❤

@Rainajunaid Ай бұрын

Greetings sir. I have Neet examination going to held on 5th May this year. It has been around 13 months when i started preparing and it was going smooth until now. But whenever i tried hard for something i always end up messing things up. And the reason is that i lost confidence at last moments and I'm feeling the same this time. From the completion of my 12th exams last year , i gave my everything for this examination whether it time, health etc. Sir please help me out. I am loosing my hold on concepts which i used to have mastered .

@lecturesbywalterlewin.they9259 Ай бұрын

Watch all my 94 MIT course lectures. Start with 8.01, then 8.02, then 8.03. Do all the homework and take all my exams. *I guarantee you that you will then do very well on the Physics portion of any freshman college or JEE exam* You will find all information you need on this channel in three playlists "Homework, Exam, SolutionsY & Lecture Notes". 8.01 & 8.02 will each take about 200 hours, 8.03 about 250 hours.

@avikhatiwada1732 Ай бұрын

Thank you sir

@faintersleet188 Ай бұрын

Hey, I love ur vids

@Blisoo_av Ай бұрын

As a physics enthusiast could you tell me the career options in this field

@surendrakverma555 Ай бұрын

Very good. Thanks 🙏

@hanslepoeter5167 Ай бұрын

Impressive. I should have done the math. The aproximate sign needs to be there as the integration is not perfect. The last page of his solution does not account for the sawtooth signal going below zero as it will in time but that is exactly what the aproximate sign is about. I'll study the math, i'll learn a lot front that ...

@KeithandBridget Ай бұрын

Thanks. One thing that I try hard to do is keep videos short otherwise I would ramble on and on. I now use a stopwatch while recording them. Guess who I copied that idea from!

@John-wx3zn Ай бұрын

Thank you. I hope you are blessed through Jesus Name. Amen.

@lecturesbywalterlewin.they9259 Ай бұрын

who is Jesus?

@michaelbruning9361 Ай бұрын

Assumed Vout = R/L*integral(Vin)dt with Vout = R * i. Then derivation on each side: R * di /dt = R/L * Vin or Vin = L * di / dt. If i look at your first page with the DGL Vin = i * R + L * di / dt, then Vout would be zero ?

@abulkhayer4898 Ай бұрын

I'm in class 8th and I'm having some problems in understanding the Black- Body radiation...can you please explain it to me......

@lecturesbywalterlewin.they9259 Ай бұрын

use google

@a21imanadhikary83 Ай бұрын

@@lecturesbywalterlewin.they9259 😆😅😁 Greatest Reply from The greatest Mam😊❤

@lakshatchoudhary Ай бұрын

Where can we send solutions like this

@The_Green_Man_OAP Ай бұрын

Post a video? He doesn't give out his email to everyone, so that's not an option... Links sometimes work. They did for the problem,but don't here...

@Hamzaaftab1110 Ай бұрын

First hello sir love your lectures

@The_Green_Man_OAP Ай бұрын

One thing I'd like to point out is that I was able to post two links to desmos where I set up interactive charts for both Vin and Vout. Various parameters can be set in the charts, like Vmax, period and so on... I cannot repost the links, so you'd have to check my solution in his previous video showing the problem. Another thing is that I posted the actual equation that you can use the generate Vout. Here it is again: The output of the square wave is a triangular wave (isosceles), with an equation of the form: (2a/π)arcsin(sin(2πt/τ-π/2))+1, for some a. There was a lot in my solution and maybe it was too complicated, so it probably confused someone, but here some conclusions from it: Current out: i'ₖ = (1/L)·ₒ∫⁼ͭ vₖ dt Thus the output voltage is Vout = v'ₖ= i'ₖR = (R/L) ₒ∫⁼ͭvₖ dt For the time t< 1st half- period T₁: Vout =(R/L) ₒ∫⁼ͭvₖ dt =(R/L)vₖ ₒ∫⁼ͭ dt , as vₖ is constant over ½period =(R/L)v₁ t₁, with 0

@shambhusah4272 Ай бұрын

Hello Walter Sir , Since you have crossed your 80's you had lots of experience and incidents that has taught you something. Please Walter sir , make a video explaining all those lessons and what our generation can do to make better life . Please walter sir , this will be life changing video for us .

@amitkumarchejara6042 Ай бұрын

But there is a voltage drop across an inductor, which is proportional to the rate of change of the current passing through it. So, why does Keith take it zero??

@lecturesbywalterlewin.they9259 Ай бұрын

there is no E-field in an ideal inductor. *Thus the integral of E dot dL through the inductor is zero.* However, if you attach a voltmeter over the inductor you read a value minus*dphi/dt bcoz you have now created a new loop which includes the voltmeter and the inductor.

@carultch Ай бұрын

Good question. There is an apparent voltage drop across the inductor as you will measure with your voltmeter, but it it is due to magnetic induction, rather than electrostatic interactions of charges. The field is not conservative, and does not add up to zero around a closed loop. One way to approach the inductor, is to treat its apparent voltage drop, as if it were a real voltage drop, ∆V = L*dꞮ/dt. Or a variant of this formula, ∆V=Ɪ*Z_L, where Z_L is the impedance of the inductor, Z_L = j*ω*L for the Fourier domain and Z_L = s*L in the Laplace domain. You then use it with Kirchhoff's laws, exactly as you would if it were any other kind of circuit. This approach is mathematically correct, but not physically correct. Because this apparent voltage drop across the inductor, isn't really a drop in electric potential. Instead, it is a consequence of a non-conservative electric field, which is more accurately modeled by Faraday's law of induction, rather than Kirchhoff's voltage loop law. A similar comparison of methods (Newton vs D'Alembert) happens for forces in an accelerating environment. One approach is to add up forces and equate them to m*a, which is the more physically accurate way to do it. Another approach is D'Alembert's principle, treating the apparent inertial force (-m*a) as if it were a force, and summing it with the other real forces, to add to zero. Both get you the same result mathematically, one just reflects the physics a lot more accurately.

@amitkumarchejara6042 Ай бұрын

@@lecturesbywalterlewin.they9259 Thank you sir for the clarification! Is it that we have a square wave as an input and for that part of the square wave where we have a constant voltage like for the time T/2 I think, the di/dt for the inductor is zero. Love from India!!

@amitkumarchejara6042 Ай бұрын

@@carultch Thank you sir for the clarification! Is it that we have a square wave as an input and for that part of the square wave where we have a constant voltage like for the time T/2 I think, the di/dt for the inductor is zero.

@carultch Ай бұрын

@@amitkumarchejara6042 The cutoff frequency is R/L, in rad/sec. Also called corner frequency, since this frequency appears as an approximate corner on a Bode plot. At frequencies much lower than R/L, this circuit is a low pass filter, very closely letting the original input voltage through directly. Instead of abruptly alternating like the input, it follows a quick exponential approach, and then settles to match the input. Then, the input abruptly changes again, and it exponentially approaches to the opposite phase of the square wave. At frequencies much higher than R/L, the circuit is an integrator, turning the square wave into a triangle wave. The exponential approach is very close to a diagonal line, and the opposite sloped diagonal line, after the input alternates. The output ultimately is a pattern of alternating exponential approaches, just cut short to look like a triangle wave before curvature can be noticeable. Close in frequency to R/L, and the output clearly appears as exponential approaches of alternating curvature. I call it as a sharkfin wave.

@pradyumansharma5376 Ай бұрын

Matched

@ekamvirsingh193 Ай бұрын

Walter sir!! I want you to start teaching syllabus of JEE Advanced

@xarlition Ай бұрын

thank you

@lecturesbywalterlewin.they9259 Ай бұрын

You're welcome

@a21imanadhikary83 Ай бұрын

Sir I am preparing for JEE 2024. But I can't understand the Topic- *Entropy* and *Gibbs free Energy* from Thermodynamics . I am confused in these topics. Can you tell me in which lecture, have you covered those Topics? It will really help me sir😊❤

@lecturesbywalterlewin.they9259 Ай бұрын

use google

@tashfiyabaig4671 Ай бұрын

I have nearly a week left for my JEE exam and i feel like i am losing the foothold I've gained all 2 years of my 11th and 12th for mastering few topics of physics... More the progressing days, more i feel like i have forgotten everything.... Please recommend me some ways to atleast revise the concept in this week

@lecturesbywalterlewin.they9259 Ай бұрын

@Sanskriti.parihar Ай бұрын

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@AariSh09 Ай бұрын

❤

@anshumishra5610 Ай бұрын

Hello sir I am your big fan I know you have devoted entire life to physics . But I am student of class 8 and how can I get faster in physics tell you something sir

@lecturesbywalterlewin.they9259 Ай бұрын

eat yogurt every day but *never on Fridays* that also worked well for Einstein and for me

@Anewevisual Ай бұрын

@@lecturesbywalterlewin.they9259legend. Replying to comments on a 13 year old video haha

@HackerXReact Ай бұрын

Hello sir ❤

@turan772 Ай бұрын

hello professor Welcome How are you?

@pgraham3760 Ай бұрын

sorry for my ignorance sir.For me ,this seems like a disaster.I wish you well

@Aryan-wy3zy Ай бұрын

Sir take some rest

@muhammadyousuf4248 Ай бұрын

Hi sir.. I am from Pakistan and big fan of you. Sir i study physics but i cannot solve problems myself Can you please guide me how can i good be in solving problems please 🥺

@lecturesbywalterlewin.they9259 Ай бұрын

eat yogurt every day but *never on Fridays* That also worked well for Einstein and for me.

@muhammadyousuf4248 Ай бұрын

@@lecturesbywalterlewin.they9259 sir i eat daily but it made no difference please give proper solution I will be very thankful

@lecturesbywalterlewin.they9259 Ай бұрын

@@muhammadyousuf4248 Watch all my 94 MIT course lectures. Start with 8.01, then 8.02, then 8.03. Do all the homework and take all my exams. *I guarantee you that you will then do very well on the Physics portion of any freshman college or JEE exam* You will find all information you need on this channel in three playlists "Homework, Exam, SolutionsY & Lecture Notes". 8.01 & 8.02 will each take about 200 hours, 8.03 about 250 hours.