Kernel and Range

[@indumathikrishnappa379]

Thank u very much mam. Very beautifully explained the concept of range and null space

[@drpriti30]

Thank you very much

[@ZOE-ft6yv]

Hi, question(a) seems wrong, the result is not equal to (0,0,0) and thus (0,3,-3) is not within the kernel.

[@drpriti30]

It is a typing mistake . The point is (0, -3 , -3). Sorry for that.

[@kothakalvamurali7577]

4:22 how it solvable madam please show it

[@pritibajpai2700]

We form an augmented matrix [A:B] by writing all the coefficients of LHS and RHS and then use Gauss elimination method and reduce the matrix to REF form . In the question here we reduced to REF form the last row has all zeros which means system is solvable . When the rank of A = rank of [A:B] we say system is solvable

[@coc_heart]

The 1st question is incorrect....

[@pritibajpai2700]

It's typing error. The point is. ( 0, -3,,-3). Sorry guys

[@drpriti30]

Sorry it is a typing error. The point is (0, -3, -3).