Another example of a projection matrix | Linear Algebra | Khan Academy

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14 жыл бұрын

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Figuring out the transformation matrix for a projection onto a subspace by figuring out the matrix for the projection onto the subspace's orthogonal complement first
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Пікірлер: 7
@97021840
@97021840 14 жыл бұрын
just great
@debendragurung3033
@debendragurung3033 7 жыл бұрын
9:50. which matrix is valid this one or the ones with two colu,ns?
@yonghuiliew8066
@yonghuiliew8066 4 жыл бұрын
The one in 9:50. he messed up the one with two columns cuz he assumed x2 and x3 to be free variables
@debendragurung3033
@debendragurung3033 7 жыл бұрын
the whole projection has me lost
@yonghuiliew8066
@yonghuiliew8066 4 жыл бұрын
How do you know if x2 and x3 are free variables to begin with? You can't just assume x2 and x3 to be free variables and let them equal to c. Therefore, your transformation matrix A in the beginning is wrong.
@legacies9041
@legacies9041 3 жыл бұрын
This is just an example @Yong Hui Liew and not a proof! Please pay attention!
@MrPeeepe
@MrPeeepe 11 жыл бұрын
Too slow
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