Linear Algebra 1.2.2 Solution Sets and Free Variables

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Kimberly Brehm

Kimberly Brehm

Күн бұрын

Пікірлер: 56
@existentiol
@existentiol Жыл бұрын
Getting ready for linear algebra next semester by binging this entire playlist and taking notes (the teacher is apparently less than coherent, so I'm trying to get ahead)... these videos are great! Very clear, straightforward, and easy to follow. Thanks for this! I'll pass this along to my classmates if any of them are struggling :)
@azamatkenzhekhan1609
@azamatkenzhekhan1609 4 жыл бұрын
I wish you were my actual prof.
@SawFinMath
@SawFinMath 4 жыл бұрын
You can transfer to Bellevue University!
@jonahp27
@jonahp27 10 ай бұрын
I want to emphasize a point that only one other commenter has mentioned and it is that at 0:59, the matrix depicted is actually in reduced row echelon form (RREF). You mention that because of the -5 and 1, the matrix cannot be in RREF however, the two values are not in pivot columns. The pivots columns of x1 in row 1 and x2 in row 2 do not have any non zero values in them. Also since all other conditions are met, this matrix is in RREF. Just wanted to point that out.
@AbubakarNasir-cs1cz
@AbubakarNasir-cs1cz 7 ай бұрын
she basically mean that it's not in the form but she didn't mean it can't be a RREF it can be but at that situation it's not watch the video before it you will get what i'm saying...
@rahulrathod170
@rahulrathod170 5 жыл бұрын
Honestly, Thank you so much. Felt so lost but this video along with your other ones are helping step by step.
@SawFinMath
@SawFinMath 4 жыл бұрын
Thanks! Glad they were helpful!
@PhotoshopEditing-t9s
@PhotoshopEditing-t9s 2 ай бұрын
Summarizing this video : 1. Pivot element : The first non-zero element of each row when matrix is in echelon form is called pivot element 2. Pivot column : column containing pivot element is called pivot column 3. Basic and free variable : Every variable has its column. if that column is pivot then that variable is basic otherwise it is free variable. 4. If a system has at least one free variable then it has infinite many solutions(Consistent).
@rijaahmed4032
@rijaahmed4032 2 жыл бұрын
best teacher everr!!!!!!
@opufy
@opufy 2 жыл бұрын
12:45 I just use the matrix to get to Reduced echelon form instead of plugging in 3. So its row 1 subtracted by 4 x row2
@thatdecemberguy
@thatdecemberguy 4 жыл бұрын
Found your videos much better than 3blue1brown! Please clarify more on vector spaces and Linear transformation
@SawFinMath
@SawFinMath 4 жыл бұрын
I have videos on each of those topics. Here is the entire playlist: kzbin.info/aero/PLl-gb0E4MII03hiCrZa7YqxUMEeEPmZqK
@ticketpirates
@ticketpirates 4 жыл бұрын
yippee! still following....good teacher step by step! Feeling pumped!
@SawFinMath
@SawFinMath 4 жыл бұрын
Thanks!
@chidochiradza
@chidochiradza 10 ай бұрын
You are saving my life😭
@chuckc3665
@chuckc3665 10 ай бұрын
thank you for this lesson that let me recall what i learned 25 years ago
@denniscarroll1502
@denniscarroll1502 4 жыл бұрын
Your videos are great. What textbook do you use in the linear algebra class?
@SawFinMath
@SawFinMath 4 жыл бұрын
I use David Lay Linear Algebra and Its Applications 5th edition
@sebabatsomonareng7828
@sebabatsomonareng7828 3 жыл бұрын
@@SawFinMath thank you so much!
@laixu-m4k
@laixu-m4k 5 ай бұрын
thanks for your wonderful video, that's so helpful
@xihengli6012
@xihengli6012 2 жыл бұрын
the handwriting form is way better than the ppt. very cool!
@shanikirson2539
@shanikirson2539 4 жыл бұрын
3:52 shouldn't x2= 4+(-6) = -2. Therefore, the solution would be (-29,-2,-6)
@zappist751
@zappist751 2 жыл бұрын
naw
@basdewaal6928
@basdewaal6928 Жыл бұрын
0:59 How is this matrix not in reduced row echelon form? It is, right?
@timkang623
@timkang623 Жыл бұрын
that's what i was thinking as well
@AbubakarNasir-cs1cz
@AbubakarNasir-cs1cz 7 ай бұрын
watch the video before you will understand
@bleached_coral
@bleached_coral 2 ай бұрын
the values above the pivot 1s have to be 0
@mahmoudalbahar1641
@mahmoudalbahar1641 4 жыл бұрын
please answer these two questions: why non pivot columns are free variables? what is the proof of it? I love understanding the rule... not just saving it without understanding. and thanks for your very good videos
@AB-cn5hb
@AB-cn5hb 3 жыл бұрын
I am not sure I understand your question. You only get free variable is pivot value is 0. It's simply saying, we can get the value of other variables by using it as dependent on free variable. (think it as function).
@UnathiGX
@UnathiGX Жыл бұрын
WHat teh hell bra! Now I understand this thing of free variables...
@liamhoward2208
@liamhoward2208 2 жыл бұрын
So their are 2 ways a variable can be free then correct? 1. A column has no pivot 2. A row has all zero values
@ahsanhaq3172
@ahsanhaq3172 5 жыл бұрын
thanks.. helpful !
@SawFinMath
@SawFinMath 4 жыл бұрын
Thank you!
@xbz24
@xbz24 Жыл бұрын
here before this blows up
@SawFinMath
@SawFinMath Жыл бұрын
Hoping it does!
@gewrgia
@gewrgia 2 жыл бұрын
why would we want to write an augemented matrix instead of a coefficent matrix?
@SawFinMath
@SawFinMath 2 жыл бұрын
When you have to solve for the value of the variable, you augment with the constants in the system of equations.
@gewrgia
@gewrgia 2 жыл бұрын
@@SawFinMath thank you
@eternalohyper347
@eternalohyper347 3 жыл бұрын
Kimberly brehm 🔥🔥
@gregdoty9125
@gregdoty9125 4 жыл бұрын
So, any time we wind up with at least one free variable, we will have an infinite number of solutions?
@SawFinMath
@SawFinMath 4 жыл бұрын
Yup. Because you will have a solution for every value of your free variable.
@cavelinguam6444
@cavelinguam6444 3 жыл бұрын
Really helpful! Thanks :)
@SawFinMath
@SawFinMath 3 жыл бұрын
Glad it was helpful!
@edwardjones2851
@edwardjones2851 Жыл бұрын
what if it is a 4x3 matrix and works out where the last row is all 0s and but the other 3 rows have a solution. [[1,0,0:1],[0,1,0:2],[0,0,1:3],[0,0,0:0]]. Is this a unique solution or infinitely many? is the last equation just redundant. Thanks for the video!
@methmurat
@methmurat 2 жыл бұрын
12:00 does x_2 necessarily HAVE to be the free variable? Because couldn't we technically express the solution in terms of x_1 as well: (x_1 = x_1, x_2 = - (1/3)x_1 - (5/3), x_3 = 3)? In this case x_1 is free and x_2 bounded, but isn't this a valid solution as well?
@cooking60210
@cooking60210 Жыл бұрын
You can solve it that way but technically x_2 is the only free variable.
@JuliaZhang-qb1yy
@JuliaZhang-qb1yy 10 ай бұрын
Why is it possible to solve 3 three-variable system with only two equations using matrices? I'm referring to the last problem in this video
@JuliaZhang-qb1yy
@JuliaZhang-qb1yy 10 ай бұрын
Also, how did you know that X2 is a free variable? Assume the last column turns out to be 0 1 0 3, does that mean that X3 is the free variable? Is there a way to prove it?
@-Mohamed_bayan
@-Mohamed_bayan 4 жыл бұрын
Thank you . what is the textbook of this course?
@kenlandon6130
@kenlandon6130 9 ай бұрын
The classic. Lay's 5th edition.
@rachelprojects7590
@rachelprojects7590 3 жыл бұрын
to clarify at around the 13 min mark you started writing x_2 as x^2 was that just a mistake or am i missing something?
@rachelprojects7590
@rachelprojects7590 3 жыл бұрын
nevermind you corrected in the video
@Md.ShifatHossainShishir
@Md.ShifatHossainShishir 9 күн бұрын
Can I get passed my whole semester by completing this playlist?
@feilongish
@feilongish 2 жыл бұрын
Complete
@delt5305
@delt5305 3 ай бұрын
1:19 wtf
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