CSAT 2023 | Answer Key | UPSC CSE | Detailed Analysis in Tamil

[@chan_18520]

Excellent in your explanations sir. Very useful for my preparations. Thank you sir.

[@aravintharena7766]

Very good explanation. Thank you very much sir

[@viswanathanpr9443]

No wonder if some of these questions may come in next group 1!!!!!!!

[@GMouriyaprasanth]

Very Excellent Teacher but going Fast, Your Hard work is Amazing 👏

[@surendermaths2939]

Sir screen theliva show agala sir

[@gayatheri.m07]

Sir 14 question p=7 and c=10 how its satisfies the first condition can u explain me

[@jemimahj7204]

Thank you so much sir

[@dhivyab216]

It's very useful thank u soo much sir

[@SakthiSakthi-z8b]

Wonderful explanation sir....

[@anumathiyazhagan2325]

Sir, 10th question if we take 108/9=12& diff is 7 and 7 is one of the option

[@yogalakshmi2765]

For the 49th question .. One can do the actual calculation that is 10000000000÷7 One can observe that the remainder cycle repeats every 6th time ... Means.. finding the remainder of the rest 4th cycle gives the actual remainder that is 4 which falls on Thursday

[@DKeerthanaUPHDevakeerthana]

I need the UPSC questions papers sir...

[@KanchanaKarthikeyan]

29 question.ans.946?

[@sakthi0079]

Class is super sir, kindly share the fees structure.when will you start new csat batch ?

[@chamuloke6623]

How sir 945÷4 is 1 ... Sir can you please explain it how?

[@meshu6602]

That's remainder theorem dude

[@MyJANA55]

Thanks ji

[@thulasimuthu6797]

🎉❤

[@aadivasisamskruthi4686]

English medium available

[@Iamashwin.18]

945 ÷ 4 remainder 1 eppid varum

[@lubinajeyarajs9045]

Bro 4la ÷ panna epudi kandu pidiganum na namagu kuduthuruga number la last 2 digit 4÷ panna pothum 945 kuduthuruguranga ipo 45÷4 panunga remainder 1 kidigum so remainder 1 than varum

[@nikaranlk]

Superb..