L21.3 Integral equation for scattering and Green's function

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MIT OpenCourseWare

MIT OpenCourseWare

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MIT 8.06 Quantum Physics III, Spring 2018
Instructor: Barton Zwiebach
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L21.2 Integral equation for scattering and Green's function
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Пікірлер: 18
@yomboh7033
@yomboh7033 3 жыл бұрын
とても分かりやすくて感動致しました。非常に大らかかつ表現性のある喋り方で、心地よく内容を理解することができました。 I was really moved by the informative expression by Barton Zwiebach! He speaks in really fun and informative way which is easy to understand for me Japanese.
@him31anshu
@him31anshu Жыл бұрын
I have been looking for this for 3 years!! It was here all the time!
@physicsboy3108
@physicsboy3108 4 жыл бұрын
Really he had mastered Quantum Mechanics in present era of physics!!!
@Higgsinophysics
@Higgsinophysics 5 жыл бұрын
Helped me a lot - thanks for the upload
@dontForgetTheConstantC
@dontForgetTheConstantC 2 ай бұрын
nice and neat explanation. thanks so much
@dpavlovsky
@dpavlovsky 5 жыл бұрын
Excellent explanation. Thank you for the upload.
@ey3796
@ey3796 5 жыл бұрын
Bro could you explain the phase approximation done at 27:00?, Cheers.
@skipperglume
@skipperglume 4 жыл бұрын
@@ey3796 It was done just to have an approximation for small r primes in compare to r.
@Kathie-ov8lv
@Kathie-ov8lv 4 ай бұрын
​​​​@@ey3796 n is the unit vector in the r direction. For a small angle between r' and r (which occurs for r >> r'), projection of r' on the r direction (n.r') is approximately equal to r' itself. Thus we write |r - r'| as approximately equal to |r - n.r'| in the numerator where this term is being multiplied by "k" to keep the possible error under control (instead of writing |r-r'| ~ r as we did for the denominator). And why do we need such an approximation instead of leaving r' just as r'? It is to connote the relation between r and r' instead of treating them as two totally irrelevant vectors/objects in our equation (which would dampen the information we get from the solution).
@huitang1853
@huitang1853 3 жыл бұрын
Easy to understand, thx!
@not_amanullah
@not_amanullah 7 ай бұрын
Thanks 🤍❤️
@vikashkumarmukhia3013
@vikashkumarmukhia3013 4 жыл бұрын
Equivalent to Griffith solution
@not_amanullah
@not_amanullah 7 ай бұрын
This is helpful ❤️🤍
@ananddaawar4741
@ananddaawar4741 4 жыл бұрын
String theorist explains pretty well! I thought it would short circuit me xD
@justicepatrick6366
@justicepatrick6366 3 жыл бұрын
i guess I am pretty off topic but does anybody know a good site to stream newly released series online?
@joeltrevor3257
@joeltrevor3257 3 жыл бұрын
@Justice Patrick flixportal :D
@justicepatrick6366
@justicepatrick6366 3 жыл бұрын
@Joel Trevor Thank you, signed up and it seems like they got a lot of movies there :D Appreciate it !
@joeltrevor3257
@joeltrevor3257 3 жыл бұрын
@Justice Patrick happy to help xD
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