How would you know the measure of the material removed from the contour plot
@rezaamiri4520 Жыл бұрын
Hello, any one has the amended code ? please kindly help! mine is not working
@kushagrakirtiman32922 жыл бұрын
can you explain what the last plot mean? why the temperature was shown on left edge of the geometry?
@pinalrana2 жыл бұрын
This is the axis-symmetric model, so the temperature is shown on the left edge.
@bgborden68522 жыл бұрын
@@pinalrana Can you explain what changes should I make if I want to put the laser beam in the middle of the workpiece
@vincentfeng9802 Жыл бұрын
When i try to upload the code, it says line 1: parse error
@thenoobers46282 жыл бұрын
Hey Pinal, do you mind sharing the code file again? The link in the description seems to be broken
@pinalrana2 жыл бұрын
Updated
@jessefonarcus2 жыл бұрын
Im getting this error when i interpret 'function returning float returns double'
@pinalrana2 жыл бұрын
Replace float with double
@kushagrakirtiman32922 жыл бұрын
Can you plz explain the temperature contour plot you are getting is top view or front view?
@pinalrana2 жыл бұрын
Front view
@bgborden68522 жыл бұрын
@@pinalrana Thank you, so it showing the depth values of laser ablation?
@pinalrana2 жыл бұрын
@@bgborden6852 Yes
@pinalrana2 жыл бұрын
@@bgborden6852 Yes
@bgborden68522 жыл бұрын
Do you know why I am getting max temp as 5000K while you are only getting around 444K ?
@pinalrana2 жыл бұрын
You may have used different laser intensity or material properties.
@kushagrakirtiman32922 жыл бұрын
I am getting temperature of 5000K with float I = 7.95455*pow(10,11), which is used in your code. Can you tell how are you getting max temp of just 400K? I have used the same material as you have used
@pinalrana2 жыл бұрын
Actually, you are getting a temperature more than 5000 K. By default In Ansys the maximum temperature limit is 5000 K. However you can change the default value to some higher number. In my case, I have used a different source file. You are using the updated version of the source file, which shows more accurate results.
@kushagrakirtiman32922 жыл бұрын
@@pinalrana Do you know how to change the limit and is not drilling as temperature is quite is high more than melting point of the material?
@pinalrana2 жыл бұрын
@@kushagrakirtiman3292 Workbench > Setup > Solution > Solution control > Limits > Maximum static temperature
@kushagrakirtiman32922 жыл бұрын
@@pinalrana thank you so much, Cant we say this simulation as drilling since max temp is more than the melting point
@pinalrana2 жыл бұрын
@@kushagrakirtiman3292 Its depends on your assumptions and mechanism of material removal.
@bgborden68522 жыл бұрын
Is this not multiple pulses because your time step is 100 and the pulse on time is in ms? and if not can you suggest the changes that we can make in order to simulate two or three pulses ?
@pinalrana2 жыл бұрын
You need to include time term in the code and make appropriate changes based on pulse on and pulse off time.
@alinaderi3332 жыл бұрын
Hi Pinal, Thanks for your interesting tutorial. I have an error while adding the code. (Error, line 32: function returning float returns double). Can you please check what is the problem?
@alinaderi3332 жыл бұрын
The name of the file is Laser_heating_1.c
@pinalrana2 жыл бұрын
You have to write float instead of double.
@alinaderi3332 жыл бұрын
@@pinalrana Dear Pinal, the error is removed. Thanks.
@alinaderi3332 жыл бұрын
Excuse me, Did you use different parameters for the laser system in this code?
@pinalrana2 жыл бұрын
@@alinaderi333 possible, I an not sure
@anandasinha90982 жыл бұрын
sir...not able to access the code file
@pinalrana2 жыл бұрын
Sorry for the later response. I have updated the link.
@anandasinha90982 жыл бұрын
@@pinalrana thank u so much sir.... thank u :-)
@kushagrakirtiman32922 жыл бұрын
Q = (I/6.28)*(1-R)*a*exp(a*(y1))*exp(-1*(y*y)/(r0*r0)); Can plz tell from where exp(-1*(y*y)/(r0*r0)) coz in the formula it is exp(-2(r/w)^2) and why are u dividing the whole term by 6.28 moreover the need to add absorption and reflectivity
@pinalrana2 жыл бұрын
Various types of profiles can be used for simulation such as 1/e, 1/e2, FWHM, etc. I have used a 1/e profile.
@pinalrana2 жыл бұрын
a is absorption coefficient and R is reflectivity
@kushagrakirtiman32922 жыл бұрын
@@pinalrana Thank you so much, can you please tell why 6.28 is used to divide this?
@pinalrana2 жыл бұрын
@@kushagrakirtiman3292 Its obtained from the integration of Beer-Lambert law.
@jessefonarcus2 жыл бұрын
Sir you uploaded docx file.. it is asking for .c file. What should i do?
@pinalrana2 жыл бұрын
Conver it into .c file.
@jessefonarcus2 жыл бұрын
@@pinalrana i cant convert it...can you please help me?
@kushagrakirtiman32922 жыл бұрын
how to simulate multiple pulses ?
@pinalrana2 жыл бұрын
It's computationally intensive. Still, it is possible to do in Ansys simply by editing code.
@kushagrakirtiman32922 жыл бұрын
@@pinalrana Thanks a lot, Can you tell me how to beam at the canter of the workpiece as in the video u have put it on the corner
@kushagrakirtiman32922 жыл бұрын
@@pinalrana Can you guide what changes should I make
@rajivsinha48782 жыл бұрын
Excellent simulation brother, I am new to C language so can you tell what the following line in your code does? C_CENTROID(x,c,t) y=x[0] y1=x[1] y2=x[2]
@pinalrana2 жыл бұрын
Its defined co-ordinates in X, Y, and Z
@rajivsinha48782 жыл бұрын
@@pinalrana it would be great help if u explain that in a bit more detail. Thanks in advance
@pinalrana2 жыл бұрын
@@rajivsinha4878 y=x[0] represents co-ordinates in X direction, y1=x[1] in Y, and y2=x[2] in Z direction.
@rajivsinha48782 жыл бұрын
@@pinalrana thanks a lot, So what does this line do? Coz I cannot understand like how the gaussian distribution was applied on the top face?
@divyayadav5834 Жыл бұрын
Thanks for this video....can you please share any contact details....i needed a small help...for my project
@pinalrana Жыл бұрын
You can connect me on Linkedin: www.linkedin.com/in/pinal-rana-207413104/