Laws Of LOGARITHMS used to Solve for X!! | Easy step by Step solution | MATHEMATICS | Pre-Calculus

Laws Of LOGARITHMS used to Solve for X!! | Easy step by Step solution | MATHEMATICS | Pre-Calculus
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[@oahuhawaii2141]

Note that x > 1 for ln(√(x - 1)) to be valid. Exponentiate both sides. √(x² - 1) = √3 x² - 1 = 3 x² = 4 x = ±2 { Discard x ≤ 1 } x = 2

[@ApexmathematicsInMotion78]

Exactly 👍🏽 , that’s why at the end I declared the X=-2 as inadmissible