Second Law Application

[@LearnChemE]

This screencast has been reviewed by faculty from other academic institutions.

[@msafwa]

How did we conclude H1 = H2 ? @ 1:31

[@samgrattan5465]

Isobaric process means dP = 0, and adiabatic means Q = 0. Enthalpy (H) is a function of S and P (it is helpful to think of H as H(S, P) = U + PV). Because the process is isobaric, pressure (P) is not changing. Because the system is adiabatic and reversible, entropy (S) is not changing. Therefore, enthalpy (H) is also not changing (dH=0, H1=H2).

[@msafwa]

@@samgrattan5465 I already graduated 😂✌🏻

[@samgrattan5465]

@@msafwa yeah I figured, just answering for anyone else who might have had the same question. Congrats btw!!!

[@kylecatman7738]

he said if P2 = P1 then enthalpy doesn't change, but enthalpy is based on temp not pressure