Japanese Math Olympiad Question | You should know this Trick!!

[@Gnowop3]

This is the quickest way: 1. The number must be ending with 5 as original number is ending with 25 2. by inspection it is a 5 digit number begining with 3 and ending with 5. That is 3xyz5. 3. The number barred the 25 (ie 11112222) must be a product of two consecutive numbers. 4. 11112222=1111x10002 (easy to see from pattern) = 1111x3334x3=3333x3334 5. The number = 33335 (rule of square of a number ending with 5)

[@richardchiu9975]

by inspection ,the square near 11 is 9 ,the last digit ends at 5 must be ,so the answer is 33335. Easy.

[@paisley6660]

Did you know from the beginning that it could be applied to the formula for squaring (a+b)?

[@BambangSurodjo]

Menurut saya, untuk akar kwadrat itu lebih mudah dan lebih sederhana kalau DIHITUNG LANGSUNG saja dengan menerapkan bahwa (a + b)² = a² + 2ab + b² = a² + b(2a +b). Dengan mengambil setiap tahap 2 digit dihitung dari depan kebelakang. Dengan cara itu bahkan bisa untuk menghitung angka pecahan desimal.

[@omnipotent11]

I did that shit in my head, dunce.

[@subbaraob8474]

33335

[@subbaraob8474]

Not fit for compitative exams

[@brodieanderson9598]

my calculator can do this in 3 seconds

[@brodieanderson9598]

@@jetstream-h6p ever heard of efficency, kinda what evolution banks on

[@brodieanderson9598]

@@jetstream-h6p so how about you keep your words to yourself and grow up

[@chrisisbell3080]

This is a maths problem, not an arithmetic problem.

[@jetstream-h6p]

⁠@@brodieanderson9598 Why don't you use chatGPT to comment on this page. It is not a sentence,but just an enume ration of words.