Lect. 2.1 Impulse Function and a capacitor with impulse input || Crack Placements with Me

[@HimanshuAgarwal_]

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[@Googleelgoog-q6s]

Your way of looking at a problem ila awesome sir great job. And I have one doubt in impulse function initially width is -1/a to +1/a right which means 2/a and height is let say 'x' and area is fixed 'A' A=h×w A=X×2/a X=aA/2 na sir! But you wrote 2aA ? What is the reason

[@HimanshuAgarwal_]

My mistake there

[@samanwaypal4552]

Sir if you multiply width with height the total area comes 4A

[@chedudhupusravankumar6984]

Can u please explain 2aA is derived

[@mohankrishna5198]

How defend the conclusion theoretically - when there is impulse current source , voltage will be changing immediately

[@MeAdarshSingh]

Sir why does we. Have different condition of rise time for underdamped,critical damped and overdamped in 2nd order system plzz reply sir

[@amanruke3961]

❤❤❤❤

[@98505177229850590818]

Last part 5/C is voltage ? V is Q BY C .. not sure why you saying it’s different

[@HimanshuAgarwal_]

I didn't say it's not voltage. I was just explaining the unit 😅