Lecture - 12 Transistor Biasing

[@rounakpagare1055]

Thanks prof. For saving our assses! Aapko shat shat pranaam! 🙏🏻

[@spinctah]

@tajiknomi The best method for approaching this problem is to keep cranking up the voltage untill smoke comes out of the transistor. At this point it is then safe to assume that you have gone too far. Hope this helps.

[@dhananjaykumar5114]

Very Good Lecture

[@capoman1]

Such a thorough lecture, I applaud you sir, many thanks.

[@michaelharrison2775]

Best explanation I have ever heard. I appreciate your explaning the meaning of bias.

[@sbhdgr8]

Thank you professor Natarajan for your valuable inputs Would like to comment that Ib=Ic/beta= 5mA/100=.05 mA; therefore Rb= Vb/Ib= 5.7V/.05mA= 114 K-ohm

[@sheeptrik]

Hello prof Natarajan, thahks from Estonia for Your cursussen and they are fine work, thanks again I wish you can make more of these

[@jtracee1]

Many Thanks!! This course is wonderful!!

[@styno2010]

What a wonderful lecture. Thank you very much sir.

[@Peacemaker2027]

@hus787 I noticed that to, I think the program just made it in-phase. it's probably a program specific setting to knock the signal out of phase.

[@MageKim]

Thank you so much from Brazil for such a brilliant lecture Prof. T.S.Natarajan. Ive been using an java applet as an electronic circuit simulator. If someone knows about some "better" software, please let me know.

[@PauLWaFFleZ]

Since Vce is Zero, there won't be a need to include Re. It will just be Ic = Vcc/Rc

[@supriyameshram3510]

Thank you Professor, except some clarity problem the whole lecture is very helpful.

[@sonuraaj2148]

ok

[@supriyameshram3510]

Which s/w is used for simulation process?

[@parthugct123]

Thank you very much Professor...How do they deal with invertion at the output ? pass them through another amplifier ?

[@shellroom]

@kishoreiiap I agree - Vcc on the left at 16:27, not Vce.

[@evensteve284]

I just wish that the picture quality was better. I'm having trouble seeing the formulas and the schematic details. Otherwise it's great!

[@evensteve284]

@goodbyelonglive44 I don't understand how my not being able to see the formulas and schematic details makes you think I'm lazy. I'm squinting and straining to see; so I'm doing extra work! I'll repeat: I think that this whole series of lectures is great; they have helped me very much. Cheers goodbyelonglive44! {;-)

[@IGIMYM]

Excellent teacher. Thank you very much

[@MageKim]

Could you please tell me wich software you used to simulate the circuit ?

[@forbeswinthrop153]

Should LHS of next-to-last equation @ 17:06 be Vcc?

[@ClaudioArrau]

Vcc = .... is the correct. It is just a typo. At 16:16 there is a schematic which will make things clearer for you. :)

[@Noman_krakow]

its nice lectures,

[@9989351888]

this is a good video

[@jamesmasonic]

good explanations. would be great if the video quality would be better

[@Dpfpv1]

can someone confirm if this is right . I(saturation current)= Vcc/ Re+Rc when Vce is zero. because it says that the q point can be moved by varrying the emitter resistor Re.

[@abudujana123]

Hei, I think there is a wrong text in the minute 16:53. when he spoke about Vce=IcRc+Vce+Re(Is+Ic) .....If you look at this formela you will see at Vce are in the both sides and it doesnt mean any thing.... If I'm wrong I would like that someone can explain it for me and I'll be thankfull.. And not forgeting to say that its an awsome work and nice lecture :-)

[@mahendransshowtime3534]

Good lecture sir .....

[@sairamsmart1209]

sir ur lecture is very helpful to me... thank u sir _/\_

[@musikoako1]

sir tnx for sharing yopur knowledges

[@medwatt]

Can someone tell me the name of the breadboard simulating software use please?

[@RSuarez66]

Very good video, but there is a little problem. At 6:40, when he reads Vce=0, then Ic=Vce/Rc is not right! If Vce=0, how do we get Ic=0/Rc??!?? The correct statement should be: When Vce=0, then Ic should be Vcc/Rc.

[@shaikabdulrazakmiah3988]

0 divided by any thing is equal to 0

[@yashmidhamija1147]

In the example of emitter bias circuit, why we have supposed that the voltage will be divided equally and have halved the value for Ve??

[@Axceed1]

What happens if the Re is not there. (the emitter is connected to ground. Will Vb be the voltage division between R1 and R2, or will it be 0.6-0.7?

[@RSuarez66]

It would be 0.6-->0.7 Volts.

[@biuly]

Thank you

[@chuckjls]

the best free spice simulator in the world is LTSPICE IV. you can get it at the Linear Tech website.

[@RSuarez66]

TRUE!

[@tajiknomi]

hay guys...I have NPN transistor TO-92 package.... How can i find the maximum Voltage to operate it on Collector & base..??if some1 knows....plzz reply me...........max Operating voltage & current..>>???

[@sanjumon1991]

sir Why the current I2 is limited to 1/10th of Ic

[@EscortsSociety]

The text is fuzzy, its hard to read the slides.

[@stefengullicksen]

Great stuff, but please go slower over math, not faster! Thanks for the great work

[@asadbashir6991]

how to find I sat and vce max

[@MageKim]

I cant post the url, so Google for "falstad circuit simulator" to get the electronic circuit simulator applet.

[@RobBob555]

can someone please do this video in English ?? and who is looking after the shop ??

[@madamerotten]

I am a relentless troll that mispells words. Please hate me.

[@sbhdgr8]

Thank you professor Natarajan for your valuable inputs Would like to comment that Ib=Ic/beta= 5mA/100=.05 mA; therefore Rb= Vb/Ib= 5.7V/.05mA= 114 K-ohm

[@MageKim]

Could you please tell me wich software you used to simulate the circuit ?